Question Number 141359 by I want to learn more last updated on 17/May/21 Commented by mr W last updated on 18/May/21 $${bad}\:{diagram}!\:{you}\:{can}'{t}\:{know}\:{the} \\ $$$${displacement}\:{with}\:{the}\:{given}\:{diagram}. \\…
Question Number 10277 by Tawakalitu ayo mi last updated on 01/Feb/17 $$\mathrm{How}\:\mathrm{can}\:\mathrm{kerosine}\:\mathrm{be}\:\mathrm{heated}\:???.\: \\ $$$$\mathrm{please}\:\mathrm{give}\:\mathrm{reasons}. \\ $$ Answered by ridwan balatif last updated on 01/Feb/17 $$\mathrm{i}\:\mathrm{think}\:\mathrm{because}\:\mathrm{kerosine}\:\mathrm{has}\:\mathrm{short}\:\mathrm{carbon}\:\mathrm{chain}…
Question Number 10282 by Tawakalitu ayo mi last updated on 02/Feb/17 $$\mathrm{210}\:\mathrm{cm}^{\mathrm{3}} \:\mathrm{of}\:\mathrm{Nitrogen}\:\mathrm{at}\:\mathrm{a}\:\mathrm{pressure}\:\mathrm{of}\:\mathrm{400}\:\mathrm{mmHg} \\ $$$$\mathrm{and}\:\mathrm{100}\:\mathrm{cm}^{\mathrm{3}} \:\mathrm{of}\:\mathrm{carbon}\left(\mathrm{iv}\right)\mathrm{oxide}\:\mathrm{at}\:\mathrm{a}\:\mathrm{pressure}\: \\ $$$$\mathrm{of}\:\mathrm{350}\:\mathrm{mmHg}\:\mathrm{were}\:\mathrm{introduce}\:\mathrm{into}\:\mathrm{a}\:\mathrm{200}\:\mathrm{cm}^{\mathrm{3}} \\ $$$$\mathrm{vessel}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{total}\:\mathrm{pressure}\:\mathrm{in}\:\mathrm{the}\:\mathrm{vessel}. \\ $$ Commented by Tawakalitu…
Question Number 141345 by Dwaipayan Shikari last updated on 17/May/21 $$\frac{{log}\left(\zeta\left({s}\right)\right)}{{s}}=\int_{\mathrm{1}} ^{\infty} {J}\left({x}\right){x}^{−{s}−\mathrm{1}} {dx}\:\left(\:{Prove}\:{that}\right) \\ $$$${Here}\:\:{J}\left({x}\right)=\pi\left({x}\right)+\frac{\mathrm{1}}{\mathrm{2}}\pi\left(\sqrt{{x}}\right)+\frac{\mathrm{1}}{\mathrm{3}}\pi\left(\sqrt[{\mathrm{3}}]{{x}}\right)+… \\ $$$$\pi\left({x}\right):=\boldsymbol{\mathrm{P}{rime}}\:\boldsymbol{{counting}}\:\boldsymbol{{function}} \\ $$ Terms of Service Privacy Policy…
Question Number 141313 by 777316 last updated on 17/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141308 by BHOOPENDRA last updated on 17/May/21 Answered by Dwaipayan Shikari last updated on 17/May/21 $$\boldsymbol{\mathrm{M}}=\boldsymbol{\mathrm{I}}+\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{t}^{{n}} }{{n}!}\boldsymbol{\mathrm{A}}^{{n}} \\ $$$$\boldsymbol{\mathrm{A}}=\begin{pmatrix}{−\mathrm{3}\:−\mathrm{1}}\\{\mathrm{8}\:\:\:\:\:\mathrm{3}}\end{pmatrix}\Rightarrow\boldsymbol{\mathrm{A}}^{\mathrm{2}} =\begin{pmatrix}{−\mathrm{3}\:\:−\mathrm{1}}\\{\:\:\mathrm{8}\:\:\:\:\:\mathrm{3}}\end{pmatrix}\begin{pmatrix}{−\mathrm{3}\:\:−\mathrm{1}}\\{\:\:\:\mathrm{8}\:\:\:\:\mathrm{3}}\end{pmatrix}=\begin{pmatrix}{\mathrm{1}\:\:\mathrm{0}}\\{\mathrm{0}\:\:\mathrm{1}}\end{pmatrix}=\boldsymbol{\mathrm{I}} \\…
Question Number 10237 by Tawakalitu ayo mi last updated on 30/Jan/17 $$\left(\mathrm{1}\right)\:\mathrm{4H}_{\mathrm{2}} \mathrm{O}\:\: \\ $$$$\left(\mathrm{2}\right)\:\mathrm{FeSO}_{\mathrm{4}} \:+\:\mathrm{K}_{\mathrm{2}} \mathrm{Cr}_{\mathrm{2}} \mathrm{O}_{\mathrm{7}} \\ $$$$\mathrm{help}\:\mathrm{in}\:\mathrm{balancing}\:\mathrm{ironically}\:\mathrm{and}\:\mathrm{atomically}. \\ $$ Answered by ridwan…
Question Number 10236 by Tawakalitu ayo mi last updated on 30/Jan/17 $$\mathrm{An}\:\mathrm{electron}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{a}\:\mathrm{vacuum}\:\mathrm{between} \\ $$$$\mathrm{two}\:\mathrm{electrode}\:\mathrm{having}\:\mathrm{a}\:\mathrm{p}.\mathrm{d}\:\mathrm{of}\:\mathrm{3000v},\:\mathrm{calculate} \\ $$$$\mathrm{the}\:\mathrm{velocity}\:\mathrm{acquired}\:\mathrm{by}\:\mathrm{the}\:\mathrm{electon}\:\mathrm{if}\:\mathrm{the}\:\mathrm{ratio} \\ $$$$\mathrm{of}\:\mathrm{its}\:\mathrm{charge}\:\mathrm{to}\:\mathrm{mass}\:\mathrm{is}\:\mathrm{1}.\mathrm{8}×\mathrm{10}^{\mathrm{11}} \mathrm{Ckg}^{−\mathrm{1}} \\ $$ Answered by ridwan balatif…
Question Number 141304 by BHOOPENDRA last updated on 17/May/21 Commented by BHOOPENDRA last updated on 17/May/21 $${a},{b},{c}\:{part} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 141303 by BHOOPENDRA last updated on 17/May/21 Commented by BHOOPENDRA last updated on 17/May/21 $${iv} \\ $$ Answered by Dwaipayan Shikari last updated…