Menu Close

Category: Others

Question-8607

Question Number 8607 by tawakalitu last updated on 17/Oct/16 Answered by ridwan balatif last updated on 18/Oct/16 $$\mathrm{23}.\:\:\mathrm{C}=\mathrm{0}.\mathrm{50}\mu\mathrm{F}=\mathrm{5}×\mathrm{10}^{−\mathrm{7}} \mathrm{F} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{L}=\mathrm{0}.\mathrm{050H} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{f}=\frac{\mathrm{100}}{\pi} \\ $$$$\:\:\:\:\:\:\:\:\:\:\omega=\mathrm{2}\pi\mathrm{f}…

Question-74140

Question Number 74140 by MASANJAJ last updated on 19/Nov/19 Answered by Rio Michael last updated on 19/Nov/19 $${let}\:{he}\:{element}\:{be}\:{m} \\ $$$$\:\:{f}\left({m}\right)\:=\:\mathrm{2} \\ $$$$\Rightarrow\:\:\mathrm{4}{m}−\mathrm{2}=\mathrm{2} \\ $$$${m}\:=\:\mathrm{1}\: \\…

Question-74138

Question Number 74138 by MASANJAJ last updated on 19/Nov/19 Commented by mathmax by abdo last updated on 19/Nov/19 $${f}\left({x}\right)={x}^{\mathrm{2}} −{x}−\mathrm{2}\:={x}^{\mathrm{2}} −\mathrm{2}\frac{\mathrm{1}}{\mathrm{2}}{x}\:+\frac{\mathrm{1}}{\mathrm{4}}\:−\frac{\mathrm{1}}{\mathrm{4}}−\mathrm{2}\:=\left({x}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} −\frac{\mathrm{9}}{\mathrm{4}} \\ $$$$\Rightarrow{minf}\left({x}\right)=−\frac{\mathrm{9}}{\mathrm{4}}\:\:\:\:{and}\:{no}\:{maximum} \\…

Question-74141

Question Number 74141 by MASANJAJ last updated on 19/Nov/19 Commented by TawaTawa last updated on 19/Nov/19 $$\left.\mathrm{d}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}\:\:=\:\:\mathrm{5} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{Forth}\:\mathrm{term}\:\:=\:\:\:\mathrm{ar}^{\mathrm{3}} \:\:=\:\:\mathrm{40} \\ $$$$\:\:\:\:\:\:\:\therefore\:\:\:\:\:\:\:\mathrm{5r}^{\mathrm{3}} \:\:=\:\:\mathrm{40}…