Question Number 74139 by MASANJAJ last updated on 19/Nov/19 Commented by TawaTawa last updated on 19/Nov/19 $$\mathrm{a}\::\:\mathrm{b}\:\:=\:\:\frac{\mathrm{21}}{\mathrm{4}}\:,\:\:\:\:\:\:\:\:\:\:\mathrm{and}\:\:\:\:\:\:\:\:\:\:\mathrm{b}\::\:\mathrm{c}\:\:=\:\:\frac{\mathrm{7}}{\mathrm{3}} \\ $$$$\therefore\:\:\:\:\:\:\:\frac{\mathrm{a}}{\mathrm{b}}\:\:=\:\:\frac{\mathrm{21}}{\mathrm{4}}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{and}\:\:\:\:\:\:\:\:\:\frac{\mathrm{b}}{\mathrm{c}}\:\:=\:\:\frac{\mathrm{7}}{\mathrm{3}} \\ $$$$\therefore\:\:\:\:\:\:\mathrm{a}\:\:=\:\:\frac{\mathrm{21b}}{\mathrm{4}}\:\:\:\:\:\:\:\:\:\:\:\mathrm{and}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{c}\:\:\:=\:\:\frac{\mathrm{3b}}{\mathrm{7}} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}\::\:\mathrm{b}\::\:\mathrm{c}\:\:\:=\:\:\:\frac{\mathrm{21b}}{\mathrm{4}}\::\:\mathrm{b}\::\:\frac{\mathrm{3b}}{\mathrm{7}} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}\::\:\mathrm{b}\::\:\mathrm{c}\:\:\:=\:\:\:\frac{\mathrm{21b}}{\mathrm{4}}\:×\:\mathrm{28}\::\:\mathrm{b}\:×\:\mathrm{28}\::\:\frac{\mathrm{3b}}{\mathrm{7}}\:×\:\mathrm{28}…
Question Number 8578 by tawakalitu last updated on 16/Oct/16 Answered by ridwan balatif last updated on 17/Oct/16 Commented by tawakalitu last updated on 17/Oct/16 $$\mathrm{Thanks}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir}.\:\mathrm{for}\:\mathrm{your}\:\mathrm{help}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}…
Question Number 8571 by tawakalitu last updated on 16/Oct/16 Commented by sandy_suhendra last updated on 16/Oct/16 $$\mathrm{Is}\:\mathrm{the}\:\mathrm{potensial}\:\mathrm{of}\:\mathrm{supply}\:\mathrm{1}.\mathrm{0}\:\mathrm{volt}? \\ $$ Commented by tawakalitu last updated on…
Question Number 8564 by tawakalitu last updated on 16/Oct/16 Commented by ridwan balatif last updated on 16/Oct/16 $$\mathrm{let}:\:\mathrm{V}'=\mathrm{V}_{\mathrm{o}} −\mathrm{4}\:,\:\:\:\mathrm{with}\:\mathrm{V}_{\mathrm{o}} \:\mathrm{is}\:\mathrm{speed}\:\mathrm{that}\:\mathrm{we}\:\mathrm{want}\:\mathrm{to}\:\mathrm{count}\:\mathrm{it} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{t}^{'} \:=\mathrm{t}+\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{S}\:=\mathrm{240}\:\mathrm{km}…
Question Number 139619 by I want to learn more last updated on 29/Apr/21 Answered by mr W last updated on 30/Apr/21 $${P}={pressure} \\ $$$${V}={volume}\:{of}\:{gas}\:\left({air}\right) \\…
Question Number 8550 by tawakalitu last updated on 15/Oct/16 Answered by ridwan balatif last updated on 16/Oct/16 Commented by tawakalitu last updated on 16/Oct/16 $$\mathrm{Wow}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.…
Question Number 139618 by I want to learn more last updated on 29/Apr/21 Answered by mr W last updated on 29/Apr/21 $$\frac{\mathrm{0}.\mathrm{00015}×\mathrm{0}.\mathrm{4}×\mathrm{1000}}{\mathrm{0}.\mathrm{03}}=\mathrm{2}\:{mm} \\ $$$${a}\:{degree}\:{is}\:\mathrm{2}{mm}\:{length}\:{on}\:{the}\:{scale}. \\…
Question Number 8527 by suci last updated on 14/Oct/16 $$\sqrt{\mathrm{6}−\sqrt{\mathrm{32}}}\:=…? \\ $$ Answered by prakash jain last updated on 14/Oct/16 $$\sqrt{\mathrm{6}−\sqrt{\mathrm{32}}}=\sqrt{\mathrm{6}−\mathrm{4}\sqrt{\mathrm{2}}} \\ $$$$\sqrt{\mathrm{6}−\mathrm{4}\sqrt{\mathrm{2}}}=\sqrt{\mathrm{a}}−\sqrt{\mathrm{b}} \\ $$$$\mathrm{squaring}…
Question Number 139599 by I want to learn more last updated on 29/Apr/21 Answered by mr W last updated on 29/Apr/21 Commented by mr W…
Question Number 8526 by suci last updated on 14/Oct/16 $$\sqrt{\mathrm{8}+\mathrm{2}\sqrt{\mathrm{5}}}\:=\:…? \\ $$ Answered by ridwan balatif last updated on 14/Oct/16 $$\sqrt{\mathrm{8}+\mathrm{2}\sqrt{\mathrm{5}}}=\sqrt{\mathrm{k}}+\sqrt{\mathrm{p}} \\ $$$$\left(\sqrt{\mathrm{8}+\mathrm{2}\sqrt{\mathrm{5}}}\right)^{\mathrm{2}} =\left(\sqrt{\mathrm{k}}+\sqrt{\mathrm{p}}\right)^{\mathrm{2}} \\…