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Question-74140

Question Number 74140 by MASANJAJ last updated on 19/Nov/19 Answered by Rio Michael last updated on 19/Nov/19 $${let}\:{he}\:{element}\:{be}\:{m} \\ $$$$\:\:{f}\left({m}\right)\:=\:\mathrm{2} \\ $$$$\Rightarrow\:\:\mathrm{4}{m}−\mathrm{2}=\mathrm{2} \\ $$$${m}\:=\:\mathrm{1}\: \\…

Question-74138

Question Number 74138 by MASANJAJ last updated on 19/Nov/19 Commented by mathmax by abdo last updated on 19/Nov/19 $${f}\left({x}\right)={x}^{\mathrm{2}} −{x}−\mathrm{2}\:={x}^{\mathrm{2}} −\mathrm{2}\frac{\mathrm{1}}{\mathrm{2}}{x}\:+\frac{\mathrm{1}}{\mathrm{4}}\:−\frac{\mathrm{1}}{\mathrm{4}}−\mathrm{2}\:=\left({x}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} −\frac{\mathrm{9}}{\mathrm{4}} \\ $$$$\Rightarrow{minf}\left({x}\right)=−\frac{\mathrm{9}}{\mathrm{4}}\:\:\:\:{and}\:{no}\:{maximum} \\…

Question-74141

Question Number 74141 by MASANJAJ last updated on 19/Nov/19 Commented by TawaTawa last updated on 19/Nov/19 $$\left.\mathrm{d}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}\:\:=\:\:\mathrm{5} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{Forth}\:\mathrm{term}\:\:=\:\:\:\mathrm{ar}^{\mathrm{3}} \:\:=\:\:\mathrm{40} \\ $$$$\:\:\:\:\:\:\:\therefore\:\:\:\:\:\:\:\mathrm{5r}^{\mathrm{3}} \:\:=\:\:\mathrm{40}…

Question-74139

Question Number 74139 by MASANJAJ last updated on 19/Nov/19 Commented by TawaTawa last updated on 19/Nov/19 $$\mathrm{a}\::\:\mathrm{b}\:\:=\:\:\frac{\mathrm{21}}{\mathrm{4}}\:,\:\:\:\:\:\:\:\:\:\:\mathrm{and}\:\:\:\:\:\:\:\:\:\:\mathrm{b}\::\:\mathrm{c}\:\:=\:\:\frac{\mathrm{7}}{\mathrm{3}} \\ $$$$\therefore\:\:\:\:\:\:\:\frac{\mathrm{a}}{\mathrm{b}}\:\:=\:\:\frac{\mathrm{21}}{\mathrm{4}}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{and}\:\:\:\:\:\:\:\:\:\frac{\mathrm{b}}{\mathrm{c}}\:\:=\:\:\frac{\mathrm{7}}{\mathrm{3}} \\ $$$$\therefore\:\:\:\:\:\:\mathrm{a}\:\:=\:\:\frac{\mathrm{21b}}{\mathrm{4}}\:\:\:\:\:\:\:\:\:\:\:\mathrm{and}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{c}\:\:\:=\:\:\frac{\mathrm{3b}}{\mathrm{7}} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}\::\:\mathrm{b}\::\:\mathrm{c}\:\:\:=\:\:\:\frac{\mathrm{21b}}{\mathrm{4}}\::\:\mathrm{b}\::\:\frac{\mathrm{3b}}{\mathrm{7}} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}\::\:\mathrm{b}\::\:\mathrm{c}\:\:\:=\:\:\:\frac{\mathrm{21b}}{\mathrm{4}}\:×\:\mathrm{28}\::\:\mathrm{b}\:×\:\mathrm{28}\::\:\frac{\mathrm{3b}}{\mathrm{7}}\:×\:\mathrm{28}…

Question-8578

Question Number 8578 by tawakalitu last updated on 16/Oct/16 Answered by ridwan balatif last updated on 17/Oct/16 Commented by tawakalitu last updated on 17/Oct/16 $$\mathrm{Thanks}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir}.\:\mathrm{for}\:\mathrm{your}\:\mathrm{help}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}…

Question-8571

Question Number 8571 by tawakalitu last updated on 16/Oct/16 Commented by sandy_suhendra last updated on 16/Oct/16 $$\mathrm{Is}\:\mathrm{the}\:\mathrm{potensial}\:\mathrm{of}\:\mathrm{supply}\:\mathrm{1}.\mathrm{0}\:\mathrm{volt}? \\ $$ Commented by tawakalitu last updated on…

Question-8564

Question Number 8564 by tawakalitu last updated on 16/Oct/16 Commented by ridwan balatif last updated on 16/Oct/16 $$\mathrm{let}:\:\mathrm{V}'=\mathrm{V}_{\mathrm{o}} −\mathrm{4}\:,\:\:\:\mathrm{with}\:\mathrm{V}_{\mathrm{o}} \:\mathrm{is}\:\mathrm{speed}\:\mathrm{that}\:\mathrm{we}\:\mathrm{want}\:\mathrm{to}\:\mathrm{count}\:\mathrm{it} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{t}^{'} \:=\mathrm{t}+\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{S}\:=\mathrm{240}\:\mathrm{km}…