Question Number 73530 by Rio Michael last updated on 13/Nov/19 $${given}\:{the}\:\mathrm{3}^{{rd}} \:{degree}\:\:{polynomial} \\ $$$${P}\left({x}\right)\:=\:\left(\mathrm{2}{x}\:−\mathrm{1}\right)\left({x}−\mathrm{3}\right){Q}\left({x}\right)\:+\:\mathrm{12}{x}−\mathrm{8} \\ $$$${given}\:{that}\:\left({x}−\mathrm{1}\right)\:{is}\:{a}\:{factor}\:{of}\:{P}\left({x}\right)\:{and}\:\:{P}\left(\mathrm{0}\right)\:=\:\mathrm{10} \\ $$$${find}\:{Q}\left({x}\right) \\ $$ Answered by MJS last updated…
Question Number 73525 by arkanmath7@gmail.com last updated on 13/Nov/19 Commented by mathmax by abdo last updated on 13/Nov/19 $${z}^{\mathrm{2}} +\left(\mathrm{1}−{i}\right){z}−\mathrm{3}{i}\:=\mathrm{0} \\ $$$$\Delta=\left(\mathrm{1}−{i}\right)^{\mathrm{2}} −\mathrm{4}\left(−\mathrm{3}{i}\right)\:=\mathrm{1}−\mathrm{2}{i}−\mathrm{1}+\mathrm{12}{i}\:=\mathrm{10}{i} \\ $$$${z}_{\mathrm{1}}…
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Question Number 73466 by Rio Michael last updated on 12/Nov/19 $${please}\:{explain}\:{this}\: \\ $$$$\:\underset{{x}\rightarrow\mathrm{0}} {{Lim}}\frac{{sinx}}{{x}}\:=\:\mathrm{1}\:\:{by}\:{l}'{hopitals}\:{theorem} \\ $$$$ \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {{Lim}}\:\frac{{sinx}}{{x}}\:=\:\mathrm{0}\:{by}\:{Squeez}\:{theorem} \\ $$$${is}\:{there}\:{something}\:{wrong}? \\ $$ Answered by…
Question Number 73405 by Rio Michael last updated on 11/Nov/19 $${can}\:{someone}\:{please}\:{prove}\:{the}\: \\ $$$${Chinese}\:{Remainder}\:{theorem},\:{for}\: \\ $$$${modula}\:{arithmetic}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 7824 by ridwan balatif last updated on 17/Sep/16 Commented by Yozzia last updated on 17/Sep/16 $${n}×{n}!=\left({n}+\mathrm{1}−\mathrm{1}\right){n}!=\left({n}+\mathrm{1}\right)!−{n}! \\ $$$$\Rightarrow\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}{r}!{r}=\left({n}+\mathrm{1}\right)!−\mathrm{1} \\ $$ Commented…
Question Number 73358 by 07032041818 last updated on 10/Nov/19 $$\mathrm{1}/\mathrm{4}{x}\mathrm{2}−\mathrm{1}/\mathrm{2}{x}−\mathrm{13}=\mathrm{0} \\ $$ Commented by MJS last updated on 10/Nov/19 $$\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{clear}\:\mathrm{whether}\:\mathrm{you}\:\mathrm{mean} \\ $$$$\frac{\mathrm{1}}{\mathrm{4}}{x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{2}}{x}−\mathrm{13}=\mathrm{0} \\ $$$$\mathrm{in}\:\mathrm{this}\:\mathrm{case}\:×\mathrm{4}…
Question Number 138891 by I want to learn more last updated on 19/Apr/21 Commented by I want to learn more last updated on 19/Apr/21 $$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}.…