Question Number 138828 by BHOOPENDRA last updated on 18/Apr/21 Answered by Dwaipayan Shikari last updated on 22/Apr/21 $$\Psi={Asin}\frac{\pi{x}}{{l}} \\ $$$$\int_{\mathrm{0}} ^{{l}} \mid\Psi\mid^{\mathrm{2}} {dx}=\mathrm{1}\Rightarrow\int_{\mathrm{0}} ^{{l}} {A}^{\mathrm{2}}…
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Question Number 73255 by TawaTawa last updated on 09/Nov/19 Answered by mr W last updated on 09/Nov/19 $${there}\:{is}\:{no}\:{support}\:{on}\:{the}\:{right}\:{end} \\ $$$${of}\:{the}\:{beam}! \\ $$$$ \\ $$$$\mathrm{0}.\mathrm{4}{L}×{R}_{{Mid}} −\mathrm{0}.\mathrm{2}{L}×\mathrm{0}.\mathrm{6}{W}−\mathrm{0}.\mathrm{8}{L}×\mathrm{0}.\mathrm{15}{W}=\mathrm{0}…
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Question Number 73211 by vaibhav_0 last updated on 08/Nov/19 $${y}=\left({c}+\mathrm{3}\right)\sqrt{{x}}\:+\frac{\mathrm{3}+{d}}{{x}}−\frac{{a}+\mathrm{4}}{{x}^{{a}+\mathrm{3}} } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 7651 by FilupSmith last updated on 07/Sep/16 $${P}=\underset{{n}=\mathrm{1}} {\overset{{k}} {\prod}}{n}^{{n}} \\ $$$${P}=??? \\ $$ Commented by FilupSmith last updated on 07/Sep/16 $${P}=\mathrm{1}\left(\mathrm{2}×\mathrm{2}\right)\left(\mathrm{3}×\mathrm{3}×\mathrm{3}\right)\left(\mathrm{4}×\mathrm{4}×\mathrm{4}×\mathrm{4}\right)… \\…
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Question Number 138624 by Dwaipayan Shikari last updated on 15/Apr/21 $$\frac{\mathrm{1}^{\pi} }{\mathrm{3}!}+\frac{\mathrm{2}^{\pi} }{\mathrm{5}!}+\frac{\mathrm{3}^{\pi} }{\mathrm{7}!}+\frac{\mathrm{4}^{\pi} }{\mathrm{9}!}+\frac{\mathrm{5}^{\pi} }{\mathrm{11}!}+… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138619 by Dwaipayan Shikari last updated on 15/Apr/21 $$\int_{\mathrm{0}} ^{\infty} \left({e}^{−{x}^{\sqrt{\mathrm{3}}} } −\frac{\mathrm{1}}{\left(\mathrm{1}+{x}^{\sqrt{\mathrm{3}}} \right)^{\sqrt{\mathrm{3}}} }\right)\frac{{dx}}{{x}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\psi\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right) \\ $$ Commented by mnjuly1970 last updated on…