Question Number 72232 by MJS last updated on 26/Oct/19 $$\mathrm{to}\:\mathrm{all}\:\mathrm{those}\:\mathrm{who}\:\mathrm{deleted}\:\mathrm{their}\:\mathrm{posts}\:\mathrm{after}\:\mathrm{they} \\ $$$$\mathrm{had}\:\mathrm{been}\:\mathrm{answered}:\:\mathrm{I}\:\mathrm{will}\:\mathrm{not}\:\mathrm{answer}\:\mathrm{you} \\ $$$$\mathrm{anymore} \\ $$$$\mathrm{this}\:\mathrm{forum}\:\mathrm{had}\:\mathrm{been}\:\mathrm{great}\:\mathrm{but}\:\mathrm{lately}\:\mathrm{it}\:\mathrm{has} \\ $$$$\mathrm{been}\:\mathrm{filling}\:\mathrm{with}\:\mathrm{unpolite}\:\mathrm{people} \\ $$$$\mathrm{I}'\mathrm{m}\:\mathrm{not}\:\mathrm{a}\:\mathrm{freebie}\:\mathrm{solver}\:\mathrm{for}\:\mathrm{anybody}'\mathrm{s}\:\mathrm{homework} \\ $$ Commented by mr…
Question Number 137751 by Lekhraj last updated on 06/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 6676 by FilupSmith last updated on 11/Jul/16 $$\mathrm{A}\:\mathrm{square}\:\mathrm{of}\:\mathrm{edge}\:\mathrm{lengths}\:\mathrm{1}\:\mathrm{has}\:\mathrm{two}\:\mathrm{points} \\ $$$${A}\:\mathrm{and}\:{B},\:\mathrm{with}\:\mathrm{center}\:{O}. \\ $$$${A}\:\mathrm{and}\:{B}\:\mathrm{are}\:\mathrm{on}\:\mathrm{the}\:\mathrm{perimiter}. \\ $$$$\Delta=\mathrm{Area}\:\mathrm{of}\:\bigtriangleup{ABO}. \\ $$$$ \\ $$$$\mathrm{If}\:{A}\:\mathrm{and}\:{B}\:\mathrm{are}\:\mathrm{random},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{average} \\ $$$$\mathrm{area}\:\mathrm{of}\:\Delta? \\ $$ Terms…
Question Number 137750 by Lekhraj last updated on 06/Apr/21 Commented by som(math1967) last updated on 06/Apr/21 $$\left(\mathrm{35},\mathrm{20},\mathrm{8},\mathrm{5},\mathrm{1}\right) \\ $$$$\left(\mathrm{24},\mathrm{18},\mathrm{15},\mathrm{10},\mathrm{2}\right) \\ $$ Commented by Rasheed.Sindhi last…
Question Number 6672 by FilupSmith last updated on 11/Jul/16 $$\mathrm{If}\:\mathrm{you}\:\mathrm{pick}\:\mathrm{two}\:\mathrm{random}\:\mathrm{points}\:\mathrm{on}\:\mathrm{a}\:\mathrm{circle}'\mathrm{s} \\ $$$$\mathrm{circumference}\:\mathrm{with}\:\mathrm{radius}\:\mathrm{1},\:\mathrm{what}\:\mathrm{is} \\ $$$$\mathrm{the}\:\mathrm{average}\:\mathrm{area}\:\mathrm{between}\:\mathrm{the} \\ $$$$\mathrm{two}\:\mathrm{points}\:\mathrm{and}\:\mathrm{the}\:\mathrm{origin}? \\ $$ Commented by Yozzii last updated on 11/Jul/16…
Question Number 137746 by AzizMuzeifa last updated on 06/Apr/21 Answered by bemath last updated on 06/Apr/21 $$\mathrm{1}.{x}^{\mathrm{2}} +\mathrm{1}.{x}\:=\:\mathrm{1}.\mathrm{4}^{\mathrm{3}} +\mathrm{0}+\mathrm{2}.\mathrm{4}+\mathrm{0} \\ $$$${x}^{\mathrm{2}} +{x}−\mathrm{72}=\mathrm{0} \\ $$$$\left({x}+\mathrm{9}\right)\left({x}−\mathrm{8}\right)=\mathrm{0} \\…
Question Number 6648 by Tawakalitu. last updated on 07/Jul/16 $${What}\:{mass}\:{of}\:{ice}\:{at}\:\:−\mathrm{14}\:{will}\:{be}\:{needed}\:{to}\:{cool}\:\mathrm{200}\:{cm}^{\mathrm{3}} \:{of} \\ $$$${an}\:{orange}\:{drink}\:\left({essentially}\:{water}\right)\:{from}\:\mathrm{25}°{C}\:\:{to}\:\:\mathrm{10}°{C} \\ $$$$\left({specific}\:{latent}\:{heat}\:{of}\:{fusion}\:{of}\:{ice}\:=\:\mathrm{3}.\mathrm{36}\:×\:\mathrm{10}^{\mathrm{5}} \:{jkg}^{−\mathrm{1}} \right. \\ $$$${specific}\:{heat}\:{capacity}\:{of}\:{ice}\:=\:\mathrm{2100}\:{jkg}^{−\mathrm{1}} {k}^{−\mathrm{1}} \\ $$$${specific}\:{heat}\:{capacity}\:{of}\:{water}\:=\:\mathrm{4200}\:{jkg}^{−\mathrm{1}} {k}^{−\mathrm{1}} . \\…
Question Number 6638 by Tawakalitu. last updated on 07/Jul/16 $${The}\:{radius}\:{of}\:{curvature}\:{of}\:{a}\:{thin}\:{equiconvex}\:{lens}\:{is}\:\mathrm{40}.\mathrm{0}\:{cm} \\ $$$${the}\:{lens}\:{is}\:{made}\:{of}\:{glass}\:{of}\:{refractive}\:{index}\:\mathrm{1}.\mathrm{660}.\:\:{find}\:{the}\: \\ $$$${position}\:{of}\:{the}\:{image}\:{of}\:{an}\:{object}\:{placed}\:{on}\:{the}\:{axis}\:{of}\:{the}\: \\ $$$${axis}\:{of}\:{the}\:{lens}\:{at}\:{a}\:{distance}\:{of}\:\mathrm{50}.\mathrm{0}\:{mm}\:\:{from}\:{the}\:{pole}. \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 6630 by Tawakalitu. last updated on 06/Jul/16 $${A}\:{small}\:{source}\:{of}\:{sound}\:{emit}\:{energy}\:{uniformly}\:{in}\:{all}\: \\ $$$${direction}\:{for}\:{a}\:{particular}\:{frequency},\:{the}\:{intensity}\:{of}\:{sound}\: \\ $$$${at}\:{a}\:{distane}\:\mathrm{2}.\mathrm{0}{m}\:{from}\:{the}\:{source}\:{is}\:\mathrm{1}.\mathrm{0}\:×\:\mathrm{10}^{−\mathrm{5}} \:\:{and}\: \\ $$$${corresponds}\:{to}\:{amplitude}\:{of}\:{oscillation}\:{on}\:{the}\:{air}\:{molecules} \\ $$$${of}\:\:\mathrm{7}{u}\:.\:{assuming}\:{sound}\:{is}\:{propagated}\:{with}\:{any}\:{loss}\:{of}\:{energy} \\ $$$${calculate}: \\ $$$$\left(\mathrm{1}\right)\:{Intensity}\:{of}\:{sound} \\ $$$$\left(\mathrm{2}\right)\:{the}\:{amplitude}\:{of}\:{oscillation}\:{of}\:{the}\:{air}\:{molecules}…
Question Number 72153 by 20190927 last updated on 25/Oct/19 $$\int\frac{\mathrm{sin}\:^{\mathrm{3}} \mathrm{x}}{\:\sqrt{\mathrm{cos}\:\mathrm{x}}}\mathrm{dx} \\ $$$$\int\mathrm{sin}\left(\mathrm{lnx}\right)\mathrm{dx} \\ $$ Commented by Prithwish sen last updated on 25/Oct/19 $$\left.\boldsymbol{\mathrm{a}}\right)\:\mathrm{let}\:\mathrm{cosx}\:=\:\mathrm{t}^{\mathrm{2}} \Rightarrow−\mathrm{sinx}\:\mathrm{dx}=\:\mathrm{2tdt}…