Question Number 6638 by Tawakalitu. last updated on 07/Jul/16 $${The}\:{radius}\:{of}\:{curvature}\:{of}\:{a}\:{thin}\:{equiconvex}\:{lens}\:{is}\:\mathrm{40}.\mathrm{0}\:{cm} \\ $$$${the}\:{lens}\:{is}\:{made}\:{of}\:{glass}\:{of}\:{refractive}\:{index}\:\mathrm{1}.\mathrm{660}.\:\:{find}\:{the}\: \\ $$$${position}\:{of}\:{the}\:{image}\:{of}\:{an}\:{object}\:{placed}\:{on}\:{the}\:{axis}\:{of}\:{the}\: \\ $$$${axis}\:{of}\:{the}\:{lens}\:{at}\:{a}\:{distance}\:{of}\:\mathrm{50}.\mathrm{0}\:{mm}\:\:{from}\:{the}\:{pole}. \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 6630 by Tawakalitu. last updated on 06/Jul/16 $${A}\:{small}\:{source}\:{of}\:{sound}\:{emit}\:{energy}\:{uniformly}\:{in}\:{all}\: \\ $$$${direction}\:{for}\:{a}\:{particular}\:{frequency},\:{the}\:{intensity}\:{of}\:{sound}\: \\ $$$${at}\:{a}\:{distane}\:\mathrm{2}.\mathrm{0}{m}\:{from}\:{the}\:{source}\:{is}\:\mathrm{1}.\mathrm{0}\:×\:\mathrm{10}^{−\mathrm{5}} \:\:{and}\: \\ $$$${corresponds}\:{to}\:{amplitude}\:{of}\:{oscillation}\:{on}\:{the}\:{air}\:{molecules} \\ $$$${of}\:\:\mathrm{7}{u}\:.\:{assuming}\:{sound}\:{is}\:{propagated}\:{with}\:{any}\:{loss}\:{of}\:{energy} \\ $$$${calculate}: \\ $$$$\left(\mathrm{1}\right)\:{Intensity}\:{of}\:{sound} \\ $$$$\left(\mathrm{2}\right)\:{the}\:{amplitude}\:{of}\:{oscillation}\:{of}\:{the}\:{air}\:{molecules}…
Question Number 72153 by 20190927 last updated on 25/Oct/19 $$\int\frac{\mathrm{sin}\:^{\mathrm{3}} \mathrm{x}}{\:\sqrt{\mathrm{cos}\:\mathrm{x}}}\mathrm{dx} \\ $$$$\int\mathrm{sin}\left(\mathrm{lnx}\right)\mathrm{dx} \\ $$ Commented by Prithwish sen last updated on 25/Oct/19 $$\left.\boldsymbol{\mathrm{a}}\right)\:\mathrm{let}\:\mathrm{cosx}\:=\:\mathrm{t}^{\mathrm{2}} \Rightarrow−\mathrm{sinx}\:\mathrm{dx}=\:\mathrm{2tdt}…
Question Number 6609 by Temp last updated on 05/Jul/16 $$\mathrm{You}\:\mathrm{have}\:\mathrm{a}\:\mathrm{1×1}\:\mathrm{cm}\:\mathrm{square}.\:\mathrm{If}\:\mathrm{you}\:\mathrm{pick} \\ $$$$\mathrm{two}\:\mathrm{random}\:\mathrm{points}\:\mathrm{inside}\:\mathrm{the}\:\mathrm{square}, \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{average}\:\mathrm{distance}\:\mathrm{between} \\ $$$$\mathrm{those}\:\mathrm{points}? \\ $$ Commented by prakash jain last updated on…
Question Number 6583 by Tawakalitu. last updated on 04/Jul/16 $${An}\:{aqeous}\:{solution}\:{of}\:{tetraoxosulphate}\left({IV}\right)\:{has}\:{a}\:{density}\: \\ $$$${of}\:\mathrm{1}.\mathrm{80}\:{g}/{cm}^{\mathrm{3}} \:{and}\:\mathrm{98\%}\:{purity}\:{level}.\:{what}\:{volume}\:{of}\:{this}\: \\ $$$${solution}\:{must}\:{be}\:{diluted}\:{to}\:{give}\:\mathrm{250}\:{cm}^{\mathrm{3}} \:{of}\:\mathrm{0}.\mathrm{500}\:{mol}/{dm}^{\mathrm{3}} \\ $$$${H}_{\mathrm{2}} {SO}_{\mathrm{4}} \:{solution}\:? \\ $$$$ \\ $$ Answered…
Question Number 137645 by mey3nipaba last updated on 05/Apr/21 $${The}\:{sum}\:{of}\:{the}\:{squares}\:{of}\:{two}\:{consecutive} \\ $$$${odd}\:{numbers}\:{is}\:\mathrm{130}.\:{Find}\:{the}\:{larger}\:{number}. \\ $$ Answered by bemath last updated on 05/Apr/21 $${x}^{\mathrm{2}} +\left({x}+\mathrm{2}\right)^{\mathrm{2}} =\mathrm{130} \\…
Question Number 137637 by Dwaipayan Shikari last updated on 04/Apr/21 $$\boldsymbol{\mathrm{Prove}}\:\boldsymbol{\mathrm{or}}\:\boldsymbol{\mathrm{disprove}} \\ $$$$\frac{{cos}\left(\mathrm{1}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right)\boldsymbol{\pi}}{\mathrm{1}^{\mathrm{2}} }+\frac{{cos}\left(\mathrm{1}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right)\mathrm{2}\pi}{\mathrm{2}^{\mathrm{2}} }+\frac{{cos}\left(\mathrm{1}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right)\mathrm{3}\pi}{\mathrm{3}^{\mathrm{2}} }+…=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137641 by mey3nipaba last updated on 04/Apr/21 Answered by mr W last updated on 05/Apr/21 Commented by mey3nipaba last updated on 05/Apr/21 $${oh}\:{okay}.\:{i}'{m}\:{sorry}.\:{thanks}\:{though}\:{for}\:{the}\:{solution}.…
Question Number 137634 by mey3nipaba last updated on 04/Apr/21 $${x}=\mathrm{2}^{{p}\:} {and}\:{y}=\mathrm{2}^{{q}\:} .\:{Evaluate}\:{in}\:{terms}\:{of}\:{x}\:{and}/\:{or}\:{y}\: \\ $$$$\left({i}\right)\mathrm{2}^{{p}+{q}} \:\:\left({ii}\right)\:\mathrm{2}^{\mathrm{2}{q}\:} \:\:\:\left({iii}\right)\:\mathrm{2}^{{p}−\mathrm{1}} \\ $$ Answered by mr W last updated on…
Question Number 137618 by I want to learn more last updated on 04/Apr/21 Commented by I want to learn more last updated on 04/Apr/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:\:\mathrm{nth}\:\:\mathrm{trajectory}.…