Question Number 136761 by I want to learn more last updated on 25/Mar/21 Commented by I want to learn more last updated on 25/Mar/21 $$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}.…
Question Number 136757 by Dwaipayan Shikari last updated on 25/Mar/21 $$\mathrm{1}+\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} \frac{\mathrm{1}}{\mathrm{2}.\mathrm{1}!}+\left(\frac{\mathrm{1}.\mathrm{3}}{\mathrm{2}^{\mathrm{2}} }\right)^{\mathrm{2}} \frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} .\mathrm{2}!}+\left(\frac{\mathrm{1}.\mathrm{3}.\mathrm{5}}{\mathrm{2}^{\mathrm{3}} }\right).\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{3}} .\mathrm{3}!}+….=\left(\frac{\Gamma\left(\frac{\mathrm{1}}{\mathrm{4}}\right)}{\left(\mathrm{2}\pi^{\mathrm{3}} \right)^{\mathrm{1}/\mathrm{4}} }\right)^{\mathrm{2}} \\ $$ Answered by mindispower last…
Question Number 136760 by I want to learn more last updated on 25/Mar/21 Answered by mr W last updated on 25/Mar/21 $$\frac{{BC}}{\mathrm{sin}\:\angle{BDC}}=\frac{{CD}}{\mathrm{sin}\:\mathrm{30}°}\:\:\:\:\:…\left({i}\right) \\ $$$$\frac{\mathrm{sin}\:\angle{BDA}}{{AB}}=\frac{\mathrm{sin}\:\mathrm{45}°}{{DA}}\:\:\:…\left({ii}\right) \\…
Question Number 136661 by Dwaipayan Shikari last updated on 24/Mar/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \left(\mathrm{1}−{x}\right)^{−\frac{\mathrm{7}}{\mathrm{8}}} \left(\mathrm{1}+{x}\right)^{−\frac{\mathrm{1}}{\mathrm{16}}} {dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 5585 by 123456 last updated on 21/May/16 $${f}_{{n}} \left({x}\right)=\frac{{x}}{\mathrm{1}−{x}}+\frac{\mathrm{2}{x}}{\mathrm{2}−{x}}+…+\frac{{nx}}{{n}−{x}} \\ $$$${n}\in\mathbb{N}^{\ast} \\ $$$$−−−−−−−−−−−−−−−− \\ $$$${f}_{{n}} \left({x}\right)={f}_{{n}−\mathrm{1}} \left({x}\right)+\frac{{nx}}{{n}−{x}} \\ $$$${f}_{\mathrm{1}} \left({x}\right)=\frac{{x}}{\mathrm{1}−{x}} \\ $$$${f}_{{n}−\mathrm{1}} \left({x}\right)={f}_{{n}}…
Question Number 136593 by I want to learn more last updated on 23/Mar/21 Answered by mr W last updated on 24/Mar/21 Commented by otchereabdullai@gmail.com last…
Question Number 5522 by Kasih last updated on 17/May/16 $$\mathrm{3}^{{x}} +\mathrm{3}^{\mathrm{3}−{x}} −\mathrm{18}=\mathrm{10} \\ $$$${x}=? \\ $$ Answered by Yozzii last updated on 17/May/16 $$\mathrm{3}^{{x}} +\mathrm{3}^{\mathrm{3}−{x}}…
Question Number 136520 by mey3nipaba last updated on 22/Mar/21 Commented by mey3nipaba last updated on 22/Mar/21 $$\mathrm{help}\:\mathrm{please}. \\ $$ Answered by mindispower last updated on…
Question Number 136519 by Dwaipayan Shikari last updated on 22/Mar/21 $$\mathrm{1}−\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}{k}} +\left(\frac{\mathrm{1}.\mathrm{3}}{\mathrm{2}.\mathrm{4}}\right)^{\mathrm{2}{k}} −\left(\frac{\mathrm{1}.\mathrm{3}.\mathrm{5}}{\mathrm{2}.\mathrm{4}.\mathrm{6}}\right)^{\mathrm{2}{k}} +\left(\frac{\mathrm{1}.\mathrm{3}.\mathrm{5}.\mathrm{7}}{\mathrm{2}.\mathrm{4}.\mathrm{6}.\mathrm{8}}\right)^{\mathrm{2}{k}} −…. \\ $$$${Find}\:{the}\:{general}\:{form} \\ $$ Answered by mindispower last updated on…
Question Number 70914 by 20190927 last updated on 09/Oct/19 $$\mathrm{1}+\left(\mathrm{z}+\mathrm{2i}\right)+\left(\mathrm{z}+\mathrm{2i}\right)^{\mathrm{2}} +\left(\mathrm{z}+\mathrm{2i}\right)^{\mathrm{3}} +\left(\mathrm{z}+\mathrm{2i}\right)^{\mathrm{4}} =\mathrm{0} \\ $$$$\mathrm{find}\:\mathrm{z}\:,\:\mathrm{z}\in\mathrm{C} \\ $$ Commented by mathmax by abdo last updated on…