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SHARING-Martin-Gardner-famous-mathematician-found-a-way-to-write-his-name-so-that-it-can-also-be-read-upside-down-See-the-comment-below-

Question Number 6071 by Rasheed Soomro last updated on 11/Jun/16 $$\mathcal{SHARING}: \\ $$$$\mathrm{Martin}\:\mathrm{Gardner}\:\left(\mathrm{famous}\:\mathrm{mathematician}\right) \\ $$$$\mathrm{found}\:\mathrm{a}\:\mathrm{way}\:\mathrm{to}\:\mathrm{write}\:\mathrm{his}\:\mathrm{name}\:\mathrm{so}\:\mathrm{that}\:\mathrm{it}\:\mathrm{can} \\ $$$$\mathrm{also}\:\mathrm{be}\:\mathrm{read}\:\mathrm{upside}\:\:\mathrm{down}. \\ $$$$\mathrm{See}\:\mathrm{the}\:\mathrm{comment}\:\mathrm{below} \\ $$ Commented by Yozzii last…

z-i-4-7-24i-

Question Number 71564 by 20190927 last updated on 17/Oct/19 $$\left(\mathrm{z}−\mathrm{i}\right)^{\mathrm{4}} =−\mathrm{7}+\mathrm{24i} \\ $$ Commented by mathmax by abdo last updated on 18/Oct/19 $${we}\:{have}\:\mid−\mathrm{7}+\mathrm{24}{i}\mid=\sqrt{\mathrm{7}^{\mathrm{2}} \:+\mathrm{24}^{\mathrm{2}} }=\sqrt{\mathrm{49}+\mathrm{576}}=\sqrt{\mathrm{625}}=\mathrm{25}\:\Rightarrow…

equation-1-2A-5B-C-29-0-equation-2-9A-6B-C-117-0-equation-3-3A-2B-C-13-0-A-B-C-

Question Number 5966 by Kasih last updated on 07/Jun/16 $${equation}\:\left(\mathrm{1}\right)\:\mathrm{2}{A}+\mathrm{5}{B}+{C}+\mathrm{29}=\mathrm{0} \\ $$$${equation}\:\left(\mathrm{2}\right)\:\mathrm{9}{A}+\mathrm{6}{B}+{C}+\mathrm{117}=\mathrm{0} \\ $$$${equation}\:\left(\mathrm{3}\right)\:\mathrm{3}{A}−\mathrm{2}{B}+{C}+\mathrm{13}=\mathrm{0} \\ $$$${A}=…?\:{B}=…?\:{C}=…? \\ $$ Answered by Ashis last updated on 07/Jun/16…

Question-137016

Question Number 137016 by PGeeman last updated on 28/Mar/21 Answered by Dwaipayan Shikari last updated on 28/Mar/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}{a}^{{x}} \sim\mathrm{1}+{xlog}\left({a}\right)\:\:\:{sin}\left({x}\right)\sim{x}\:;\:\:{log}\left(\mathrm{1}+{x}\right)\sim{x} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\left(\mathrm{4}^{{x}} −\mathrm{1}\right)^{\mathrm{3}} }{{sin}\left(\frac{{x}}{{p}}\right){log}\left(\mathrm{1}+\frac{{x}^{\mathrm{2}}…

Does-1-i-1-1-i-converge-2-i-1-1-i-converge-

Question Number 5921 by FilupSmith last updated on 05/Jun/16 $$\mathrm{Does}:\: \\ $$$$\left(\mathrm{1}\right)\:\:\:\:\underset{{i}=\mathrm{1}} {\overset{\infty} {\sum}}\Gamma\left(\frac{\mathrm{1}}{{i}}\right)\:\:\mathrm{converge}? \\ $$$$\left(\mathrm{2}\right)\:\:\:\:\underset{{i}=\mathrm{1}} {\overset{\infty} {\prod}}\Gamma\left(\frac{\mathrm{1}}{{i}}\right)\:\:\mathrm{converge}? \\ $$ Commented by Yozzii last updated…

1-1-1-3-2-3-4-1-1-3-3-7-2-2-3-2-4-2-1-2-5-7-10-2-3-3-3-4-3-1-3-

Question Number 136995 by Dwaipayan Shikari last updated on 28/Mar/21 $$\mathrm{1}−\left(\frac{\mathrm{1}.\mathrm{1}.\mathrm{3}}{\mathrm{2}.\mathrm{3}.\mathrm{4}}\right)\frac{\mathrm{1}}{\mathrm{1}!}+\left(\frac{\mathrm{3}.\mathrm{3}.\mathrm{7}}{\mathrm{2}^{\mathrm{2}} .\mathrm{3}^{\mathrm{2}} .\mathrm{4}^{\mathrm{2}} }\right)\frac{\mathrm{1}}{\mathrm{2}!}−\left(\frac{\mathrm{5}.\mathrm{7}.\mathrm{10}}{\mathrm{2}^{\mathrm{3}} .\mathrm{3}^{\mathrm{3}} .\mathrm{4}^{\mathrm{3}} }\right)\frac{\mathrm{1}}{\mathrm{3}!}−…. \\ $$ Terms of Service Privacy Policy Contact:…