Question Number 5190 by sanusihammed last updated on 28/Apr/16 Commented by prakash jain last updated on 29/Apr/16 $$\frac{\mathrm{AB}}{\mathrm{BO}}=\frac{\mathrm{CD}}{\mathrm{DO}} \\ $$$$\frac{\mathrm{5}}{\mathrm{6}}=\frac{{x}}{\mathrm{4}} \\ $$$${x}=\frac{\mathrm{20}}{\mathrm{6}} \\ $$ Commented…
Question Number 5189 by sanusihammed last updated on 28/Apr/16 Commented by FilupSmith last updated on 28/Apr/16 $${Q}\mathrm{1} \\ $$$${V}={IR} \\ $$$${I}=\frac{{V}}{{R}}\:\Rightarrow\:{I}=\frac{\mathrm{12}}{\mathrm{16}+\mathrm{8}} \\ $$$${I}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$…
Question Number 5159 by 1771727373 last updated on 24/Apr/16 $${a}+\mathrm{24}\frac{{a}−\mathrm{3}}{{b}^{\mathrm{2}} +{a}}=\mathrm{2}{a}−{b}^{\mathrm{2}\:} \\ $$$${a}×{b}^{\mathrm{2}} =\mathrm{20} \\ $$$$ \\ $$$${would}\:{you}\:{solve}\:{this}? \\ $$ Answered by FilupSmith last updated…
Question Number 5117 by FilupSmith last updated on 14/Apr/16 $$\mathrm{I}\:\mathrm{have}\:\mathrm{a}\:\mathrm{question}.\:\mathrm{I}\:\mathrm{am}\:\mathrm{unsure}\:\mathrm{how}\:\mathrm{this} \\ $$$$\mathrm{is}\:\mathrm{done}\:\mathrm{because}\:\mathrm{I}\:\mathrm{have}\:\mathrm{never}\:\mathrm{learnt}\:\mathrm{it}. \\ $$$$ \\ $$$$\mathrm{How}\:\mathrm{do}\:\mathrm{you}\:\mathrm{determine}\:\mathrm{the}\:\mathrm{line}\:\mathrm{of}\:\mathrm{best}\:\mathrm{fit}? \\ $$ Commented by Yozzii last updated on 14/Apr/16…
Question Number 5090 by FilupSmith last updated on 11/Apr/16 $$\mathrm{This}\:\mathrm{is}\:\mathrm{a}\:\mathrm{silly}\:\mathrm{request},\:\mathrm{but}\:\mathrm{I}\:\mathrm{think}\:\mathrm{this} \\ $$$$\mathrm{app}\:\mathrm{should}\:\mathrm{have}\:\ddots\:\mathrm{but}\:\mathrm{the}\:\mathrm{other}\:\mathrm{direction}. \\ $$$$ \\ $$$$\mathrm{It}\:\mathrm{would}\:\mathrm{have}\:\mathrm{some}\:\mathrm{application}\:\mathrm{when} \\ $$$$\mathrm{writing}\:\mathrm{some}\:\mathrm{matricies}\:\mathrm{and}\:\mathrm{to}\:\mathrm{more}\:\mathrm{formally} \\ $$$$\mathrm{write}: \\ $$$${x}^{{x}^{…} } \:\:\:\:\:\:\mathrm{as}\:\:\:\:\:\:\:\:{x}^{{x}^{\ddots} }…
Question Number 136105 by I want to learn more last updated on 18/Mar/21 Commented by mr W last updated on 18/Mar/21 $${book}\:{is}\:{wrong}! \\ $$$${just}\:{think}:\:{can}\:{a}\:{man}\:{throw}\:{a}\:{stone} \\…
Question Number 136110 by physicstutes last updated on 18/Mar/21 $$\mathrm{An}\:\mathrm{engine}\:\mathrm{is}\:\mathrm{pumping}\:\mathrm{water}\:\mathrm{from}\:\mathrm{a}\:\mathrm{well}\:\mathrm{25m}\:\mathrm{deep}.\:\mathrm{It}\:\mathrm{discharges} \\ $$$$\mathrm{0}.\mathrm{4}\:\mathrm{m}^{\mathrm{3}} \:\mathrm{of}\:\mathrm{water}\:\mathrm{each}\:\mathrm{second}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{12}\:\mathrm{ms}^{−\mathrm{1}} .\:\mathrm{Find}\:\mathrm{the}\: \\ $$$$\mathrm{power}\:\mathrm{of}\:\mathrm{the}\:\mathrm{pump}\:\mathrm{given}\:\mathrm{that}\:\mathrm{the}\:\mathrm{density}\:\mathrm{of}\:\mathrm{water}\:\mathrm{is}\:\mathrm{1000}\:\mathrm{kg}\:\mathrm{m}^{−\mathrm{3}} . \\ $$$$\mathrm{take}\:\boldsymbol{\mathrm{g}}\:=\:\mathrm{10}\:\mathrm{ms}^{−\mathrm{2}} \\ $$ Commented by mr W…
Question Number 136104 by Dwaipayan Shikari last updated on 18/Mar/21 $$\frac{{cos}\left(\mathrm{1}+\sqrt{\frac{\mathrm{43}}{\mathrm{3}}}\right)\pi}{\mathrm{1}^{\mathrm{2}} }+\frac{{cos}\left(\mathrm{1}+\sqrt{\frac{\mathrm{43}}{\mathrm{3}}}\right)\mathrm{2}\pi}{\mathrm{2}^{\mathrm{2}} }+\frac{{cos}\left(\mathrm{1}+\sqrt{\frac{\mathrm{43}}{\mathrm{3}}}\right)\mathrm{3}\pi}{\mathrm{3}^{\mathrm{2}} }+…={a}\pi \\ $$$${Find}\:{a} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 5013 by Rasheed Soomro last updated on 01/Apr/16 $${The}\:{sign}\:{for}\:“\:{is}\:{not}\:{congruent}\:{to}'' \\ $$$${is}\:{present}\:{on}\:{the}\:{keyboard}\:\left(\ncong\right). \\ $$$${But}\:{its}\:{opposite}\:“\:{is}\:{congruent}\:{to}'' \\ $$$${doesn}'{t}\:{exist}. \\ $$$${Although}\:{by}\:{adding}\:{two}\:{signs}\:'='\:{and}\:'\sim' \\ $$$${we}\:{can}\:{make}\:{the}\:{required}\:{sign}\:\left(\overset{\sim} {=}\right)\:{but} \\ $$$${I}\:{think}\:{it}\:{should}\:{be}\:{directly}\:{present}. \\…
Question Number 136070 by Dwaipayan Shikari last updated on 18/Mar/21 $$\frac{{sin}\left(\sqrt{\mathrm{2}}\right)}{\mathrm{1}^{\mathrm{3}} }+\frac{{sin}\left(\mathrm{2}\sqrt{\mathrm{2}}\right)}{\mathrm{2}^{\mathrm{3}} }+\frac{{sin}\left(\mathrm{3}\sqrt{\mathrm{2}}\right)}{\mathrm{3}^{\mathrm{3}} }+…=\frac{\pi^{{b}} +\mathrm{1}}{\:{a}\sqrt{{b}}}−\frac{\pi}{{b}} \\ $$$${Find}\:{a}−{b} \\ $$ Answered by mnjuly1970 last updated on…