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n-1-H-n-7-n-2-H-n-7-n-1-2-k-1-n-1-k-m-H-n-m-

Question Number 135884 by Dwaipayan Shikari last updated on 16/Mar/21 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{H}_{{n}} ^{\left(\mathrm{7}\right)} }{{n}^{\mathrm{2}} }−\frac{{H}_{{n}} ^{\left(\mathrm{7}\right)} }{\left({n}+\mathrm{1}\right)^{\mathrm{2}} } \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{{k}^{{m}} }={H}_{{n}} ^{\left({m}\right)}…

f-n-x-1-n-1-1-x-2-1-x-n-1-2x-1-nx-n-N-n-gt-1-lim-n-f-n-x-n-gt-1-f-x-0-x-

Question Number 4750 by 123456 last updated on 04/Mar/16 $${f}_{{n}} \left({x}\right)=\begin{cases}{\mathrm{1}\:\:\:\:{n}=\mathrm{1}}\\{\frac{\left(\mathrm{1}−{x}^{\mathrm{2}} \right)…\left(\mathrm{1}−{x}^{{n}} \right)}{\left(\mathrm{1}−\mathrm{2}{x}\right)…\left(\mathrm{1}−{nx}\right)}\:\:\:\:{n}\in\mathbb{N},{n}>\mathrm{1}}\end{cases} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}{f}_{{n}} \left({x}\right)=? \\ $$$${n}>\mathrm{1},{f}\left({x}\right)=\mathrm{0},{x}=? \\ $$ Commented by prakash jain…

if-x-2-c-c-R-c-0-does-x-c-

Question Number 4728 by 123456 last updated on 01/Mar/16 $$\mathrm{if}\:\mid{x}^{\mathrm{2}} −{c}\mid\leqslant\epsilon,\:{c}\in\mathbb{R},{c}\geqslant\mathrm{0} \\ $$$$\mathrm{does}? \\ $$$$\mid{x}−\sqrt{{c}}\mid\leqslant\epsilon \\ $$ Commented by Yozzii last updated on 01/Mar/16 $$\mid\left({x}−\sqrt{{c}}\right)\mid\mid{x}+\sqrt{{c}}\mid\leqslant\epsilon…

how-the-gravity-work-on-a-R-4-universe-does-any-R-3-people-will-be-atracted-by-some-ghost-object-

Question Number 4724 by 123456 last updated on 29/Feb/16 $$\mathrm{how}\:\mathrm{the}\:\mathrm{gravity}\:\mathrm{work}\:\mathrm{on}\:\mathrm{a}\:\mathbb{R}^{\mathrm{4}} \:\mathrm{universe}? \\ $$$$\mathrm{does}\:\mathrm{any}\:\mathbb{R}^{\mathrm{3}} \:\mathrm{people}\:\mathrm{will}\:\mathrm{be}\:\mathrm{atracted}\:\mathrm{by} \\ $$$$\mathrm{some}\:“\mathrm{ghost}''\:\mathrm{object}? \\ $$ Commented by Yozzii last updated on 29/Feb/16…

Question-135798

Question Number 135798 by ajfour last updated on 16/Mar/21 Commented by ajfour last updated on 16/Mar/21 $${When}\:{you}\:{can}\:{see}\:\mathrm{9}\:{of}\:{them}\:{in} \\ $$$${each}\:{row},\:{instead}\:{of}\:\mathrm{8}\:{in} \\ $$$${each}\:{row},\:{the}\:{image}\:{turns} \\ $$$${holographic}! \\ $$…