Question Number 135906 by SWPlaysMC last updated on 16/Dec/21 $${Edit}:\:{this}\:{is}\:{already}\:{fixed}.\:{Therefore}\:{this}\:{thread}\:{is}\:{closed}… \\ $$$$ \\ $$$$\mathrm{There}'\mathrm{s}\:\mathrm{a}\:\mathrm{glitch}! \\ $$$$\mathrm{Whenever}\:\mathrm{you}\:\mathrm{backspace}\:\mathrm{from}\:\mathrm{a}\:\mathrm{line}\:\mathrm{to}\:\mathrm{delete}\:\mathrm{it},\:\mathrm{you}'\mathrm{ll}\:\mathrm{end}\:\mathrm{up}\:\mathrm{directly}\:\mathrm{in}\:\mathrm{front}\:\mathrm{of}\:\mathrm{the}\:\mathrm{first}\:\mathrm{thing}\:\mathrm{you}\:\mathrm{typed}, \\ $$$$\mathrm{whatever}\:\mathrm{it}\:\mathrm{is}. \\ $$$$ \\ $$$$\mathrm{Also},\:\mathrm{is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{way}\:\mathrm{for}\:\mathrm{this}\:\mathrm{app}\:\mathrm{to}\:\mathrm{run}\:\mathrm{in}\:\mathrm{portrait}\:\mathrm{orrentation}\:\mathrm{on}\:\mathrm{tablets}?\:\mathrm{Because}\:\mathrm{I}\:\mathrm{can}'\mathrm{t}\:\mathrm{seem}\:\mathrm{to}\:\mathrm{get}\:\mathrm{it}\:\mathrm{to}\:\mathrm{rotate} \\ $$$$\mathrm{to}\:\mathrm{that}\:\mathrm{mode}.\:\mathrm{I}\:\mathrm{saw}\:\mathrm{in}\:\mathrm{your}\:\mathrm{screenshots}\:\mathrm{on}\:\mathrm{the}\:\mathrm{Google}\:\mathrm{Play}\:\mathrm{page}\:\mathrm{that}\:\mathrm{it}\:\mathrm{was}\:\mathrm{possible},\:\mathrm{but}\:\mathrm{I}\:\mathrm{can}'\mathrm{t}\:\mathrm{get}\:\mathrm{it}\:\mathrm{to}\:\mathrm{work}. \\…
Question Number 4817 by 123456 last updated on 15/Mar/16 $${f}\left(\alpha{x}\right)=\alpha{f}\left({x}−\alpha\right) \\ $$$${f}\left({x}\right)=? \\ $$ Commented by prakash jain last updated on 15/Mar/16 $${x}=\mathrm{0} \\ $$$$\mathrm{Trivial}\:\mathrm{solution}\:\mathrm{satisfies}\:\mathrm{the}\:\mathrm{equation}\:{f}\left({x}\right)=\mathrm{0}…
Question Number 135884 by Dwaipayan Shikari last updated on 16/Mar/21 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{H}_{{n}} ^{\left(\mathrm{7}\right)} }{{n}^{\mathrm{2}} }−\frac{{H}_{{n}} ^{\left(\mathrm{7}\right)} }{\left({n}+\mathrm{1}\right)^{\mathrm{2}} } \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{{k}^{{m}} }={H}_{{n}} ^{\left({m}\right)}…
Question Number 4807 by Dnilka228 last updated on 14/Mar/16 $${Find}\:\mathbb{X}\:{if}… \\ $$$$\underset{\mathrm{0}} {\overset{{e}} {\int}}{x}\neq\mathrm{0}\:{and}\:\frac{{xr}}{{r}^{{e}} }=\sqrt{{e}+{n}} \\ $$$${or} \\ $$$$\underset{{n}!} {\sum}{e}=\mathrm{0}\:{and}\:\frac{\mho{x}\neq{y}}{\mho{y}\neq{x}}=−\mathrm{1} \\ $$ Commented by Dnilka228…
Question Number 4800 by 123456 last updated on 13/Mar/16 $${m}\frac{{d}^{\mathrm{2}} {x}}{{dt}^{\mathrm{2}\:} }={f}−{k}\frac{{dx}}{{dt}} \\ $$$${x}\left(\mathrm{0}\right)={x}_{\mathrm{0}} \\ $$$${x}'\left(\mathrm{0}\right)={v}_{\mathrm{0}} \\ $$$${x}\left({t}\right)=? \\ $$ Answered by Yozzii last updated…
Question Number 4795 by 123456 last updated on 13/Mar/16 $${a},{b},{c}\in\mathbb{C} \\ $$$${x}_{\mathrm{0}} ={a} \\ $$$${y}_{\mathrm{0}} ={b} \\ $$$${z}_{\mathrm{0}} ={c} \\ $$$${x}_{{n}+\mathrm{1}} ={x}_{{n}} −{y}_{{n}} \\ $$$${y}_{{n}+\mathrm{1}}…
Question Number 70310 by Rio Michael last updated on 03/Oct/19 $${please}\:{help}\:{me}\:{find}\:{the}\:{term}\:{independent}\:{of}\:{x} \\ $$$${in}\:{the}\:{expansion}\:{of}\: \\ $$$$\:\:\:\:\:\:\left({x}\:+\:\frac{\mathrm{3}}{{x}}\right)^{−\mathrm{12}\:} \\ $$ Commented by mr W last updated on 03/Oct/19…
Question Number 4750 by 123456 last updated on 04/Mar/16 $${f}_{{n}} \left({x}\right)=\begin{cases}{\mathrm{1}\:\:\:\:{n}=\mathrm{1}}\\{\frac{\left(\mathrm{1}−{x}^{\mathrm{2}} \right)…\left(\mathrm{1}−{x}^{{n}} \right)}{\left(\mathrm{1}−\mathrm{2}{x}\right)…\left(\mathrm{1}−{nx}\right)}\:\:\:\:{n}\in\mathbb{N},{n}>\mathrm{1}}\end{cases} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}{f}_{{n}} \left({x}\right)=? \\ $$$${n}>\mathrm{1},{f}\left({x}\right)=\mathrm{0},{x}=? \\ $$ Commented by prakash jain…
Question Number 135808 by oustmuchiya@gmail.com last updated on 16/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 4728 by 123456 last updated on 01/Mar/16 $$\mathrm{if}\:\mid{x}^{\mathrm{2}} −{c}\mid\leqslant\epsilon,\:{c}\in\mathbb{R},{c}\geqslant\mathrm{0} \\ $$$$\mathrm{does}? \\ $$$$\mid{x}−\sqrt{{c}}\mid\leqslant\epsilon \\ $$ Commented by Yozzii last updated on 01/Mar/16 $$\mid\left({x}−\sqrt{{c}}\right)\mid\mid{x}+\sqrt{{c}}\mid\leqslant\epsilon…