Question Number 127644 by Dwaipayan Shikari last updated on 31/Dec/20 $$\frac{\mathrm{1}}{\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}−\frac{\frac{\mathrm{1}}{\mathrm{2}}}{\frac{\mathrm{3}}{\mathrm{2}}−\frac{\frac{\mathrm{1}}{\mathrm{3}}}{\frac{\mathrm{4}}{\mathrm{3}}−\frac{\frac{\mathrm{1}}{\mathrm{4}}}{\frac{\mathrm{5}}{\mathrm{4}}−\frac{\frac{\mathrm{1}}{\mathrm{5}}}{\frac{\mathrm{6}}{\mathrm{5}}−…}}}}}} \\ $$ Commented by Dwaipayan Shikari last updated on 31/Dec/20 $${a}_{\mathrm{0}} +{a}_{\mathrm{0}} {a}_{\mathrm{1}} +{a}_{\mathrm{0}}…
Question Number 62109 by sandhyavs last updated on 15/Jun/19 $${Given}\:{that} \\ $$$$\left(\mathrm{1}+\sqrt{\mathrm{1}+{x}}\right)\mathrm{tan}\:{x}=\left(\mathrm{1}+\sqrt{\mathrm{1}−{x}}\right). \\ $$$${Then}\:{find}\:\:\:\mathrm{sin}\:\mathrm{4}{x}. \\ $$ Commented by sandhyavs last updated on 15/Jun/19 $${Also}\:{tell}\:{me}\:{the}\:{steps}.{Please}… \\…
Question Number 62088 by Cypher1207 last updated on 15/Jun/19 Commented by Cypher1207 last updated on 15/Jun/19 $$\left({very}\right)^{\mathrm{2}} {easy}…. \\ $$ Commented by maxmathsup by imad…
Question Number 62036 by Cypher1207 last updated on 14/Jun/19 $$\mathrm{Correct}\:\mathrm{me}\:\mathrm{if}\:\mathrm{I}\:\mathrm{am}\:\mathrm{wrong}. \\ $$$$\underset{\:\sqrt{−\mathrm{1}}=\mathrm{1}} {\overset{\mathrm{3}} {\sum}}\mathrm{x}_{\sqrt{−\mathrm{1}}} +\mathrm{y}_{\sqrt{−\mathrm{1}}} \\ $$$$\therefore\left({i}=\sqrt{−\mathrm{1}}\right) \\ $$$$ \\ $$ Commented by Rasheed.Sindhi last…
Question Number 62037 by amingolkar20@gmail.com last updated on 14/Jun/19 $$\mathrm{3}{no}_{\mathrm{2}} +{h}_{\mathrm{2}} {o}\Rightarrow\mathrm{2}{hno}_{\mathrm{3}} +{no} \\ $$$$ \\ $$ Answered by aleks041103 last updated on 17/Jun/19 $${It}\:{is}\:{actually}:…
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Question Number 62016 by kiplangatryan89@gmail.com last updated on 14/Jun/19 $${the}\:\mathrm{2}\:{and}\:\mathrm{3}\:{term}\:{of}\:{GP}\:\:{is}\:\mathrm{24} \\ $$$${and}\:\mathrm{12}\left({x}+\mathrm{1}\right).{If}\:{the}\:{sum}\:{of}\:{the}\: \\ $$$${first}\:\mathrm{3}\:{terms}\:{is}\:\mathrm{76}.{Find}\:{the}\:{value} \\ $$$${of}\:{x} \\ $$ Commented by Tony Lin last updated on…
Question Number 193080 by Mastermind last updated on 03/Jun/23 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{for}\:\mathrm{a},\mathrm{b}\in\mathbb{R}, \\ $$$$\mid\mathrm{a}−\mathrm{b}\mid\geqslant\mid\mathrm{a}\mid−\mid\mathrm{b}\mid \\ $$$$ \\ $$$$\left(\mathrm{Hint}:\:\mathrm{write}\:\mathrm{a}=\left(\mathrm{a}−\mathrm{b}\right)+\mathrm{b}\right. \\ $$ Answered by Subhi last updated on 03/Jun/23…
Question Number 193079 by Mastermind last updated on 03/Jun/23 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{x}\in\mathbb{R}\:\mathrm{that}\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{inequalities}: \\ $$$$\left.\mathrm{a}\right)\:\mid\mathrm{4x}−\mathrm{3}\mid\leqslant\mathrm{11} \\ $$$$\left.\mathrm{b}\right)\:\mid\mathrm{x}−\mathrm{2}\mid>\mid\mathrm{x}+\mathrm{1}\mid \\ $$$$\left.\mathrm{c}\right)\:\mid\mathrm{x}\mid\:+\:\mid\mathrm{x}+\mathrm{2}\mid\:+\:\mid\mathrm{2}−\mathrm{x}\mid\leqslant\mathrm{8} \\ $$ Commented by MM42 last updated…
Question Number 193078 by Mastermind last updated on 03/Jun/23 $$\left.\mathrm{1}\right)\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{if}\:\varepsilon>\mathrm{0}\:\mathrm{and}\:\mathrm{a},\mathrm{x}\in\mathbb{R},\:\mathrm{then} \\ $$$$\mid\mathrm{a}−\mathrm{x}\mid<\varepsilon\:\mathrm{iff}\:\mathrm{x}−\varepsilon<\mathrm{a}<\mathrm{x}+\varepsilon \\ $$$$ \\ $$$$\mathrm{help} \\ $$ Answered by Subhi last updated on 03/Jun/23…