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Question Number 69247 by Rio Michael last updated on 21/Sep/19 $${show}\:{that}\: \\ $$$$\:{c}\mid{a}\:\Leftrightarrow\:−{c}\mid{a}. \\ $$ Commented by kaivan.ahmadi last updated on 22/Sep/19 $${c}\mid{a}\Rightarrow{a}={cx};\:\exists{x}\in\mathbb{Z} \\ $$$$\Rightarrow{a}=−{c}\left(−{x}\right)…

Use-Residus-theorem-to-prove-that-a-gt-0-n-0-1-n-2-a-2-1-2-pi-ash-pia-1-a-2-and-n-0-1-n-n-2-a-2-1-2-pi-a-th-pia-1-a-2-Assume

Question Number 69236 by ~ À ® @ 237 ~ last updated on 21/Sep/19 $${Use}\:\:{Residus}\:{theorem}\:{to}\:{prove}\:{that}\:\forall\:{a}>\mathrm{0}\:\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\:{n}^{\mathrm{2}} +{a}^{\mathrm{2}} }\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\pi}{{ash}\left(\pi{a}\right)}\:\:\:−\frac{\mathrm{1}}{{a}^{\mathrm{2}} }\right) \\ $$$${and}\:\:\:\:\:\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\:\frac{\left(−\mathrm{1}\right)^{{n}} }{{n}^{\mathrm{2}}…

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Question Number 69207 by Rio Michael last updated on 21/Sep/19 $${help}\:{please}. \\ $$$$ \\ $$$${A}\:{river}\:{is}\:\mathrm{5}{m}\:{wide}\:{and}\:{flows}\:{at}\:\mathrm{3}.\mathrm{0}{ms}^{−\mathrm{1}} .\:{A}\:{man}\:{can}\:{swim}\:{at}\:\mathrm{2}.\mathrm{0}{ms}^{−\mathrm{1}} \\ $$$${in}\:{still}\:{water}.\:{if}\:{he}\:{sets}\:{off}\:{at}\:{an}\:{angle}\:{of}\:\mathrm{90}°\:{to}\:{the}\:{bank} \\ $$$${calculate} \\ $$$$\left.{a}\right)\:{the}\:{mans}\:{time}\:{and}\:{velocity} \\ $$$$\left.{b}\right)\:{his}\:{distance}\:{downstream}\:{from}\:{the}\:{starting}\:{point}\:{till} \\…

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Question Number 3655 by 123456 last updated on 17/Dec/15 $${f}\left({x}\right)=\begin{cases}{{p}+{q}}&{{x}=\frac{{p}}{{q}},{p}\in\mathbb{Z},{q}\in\mathbb{Z},{q}\neq\mathrm{0},\left({p},{q}\right)=\mathrm{1}}\\{\lfloor{x}\rfloor+\lfloor\mathrm{10}{x}\rfloor}&{\mathrm{overtise}}\end{cases} \\ $$$$\mathrm{does}\:{f}\:\mathrm{is}\:\mathrm{continuous}? \\ $$ Commented by prakash jain last updated on 18/Dec/15 $${choose}\:{p}\notin\mathbb{Q},\:\mathrm{say}\:{p}=\pi \\ $$$$\mathrm{Checking}\:\mathrm{for}\:\mathrm{definition}…

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Question Number 134657 by Dwaipayan Shikari last updated on 06/Mar/21 $$\frac{\mathrm{1}}{\pi{e}}+\frac{\mathrm{3}}{\mathrm{2}\pi^{\mathrm{2}} {e}^{\mathrm{2}} }+\frac{\mathrm{11}}{\mathrm{6}\pi^{\mathrm{3}} {e}^{\mathrm{3}} }+\frac{\mathrm{25}}{\mathrm{12}\pi^{\mathrm{4}} {e}^{\mathrm{4}} }+\frac{\mathrm{137}}{\mathrm{60}\pi^{\mathrm{5}} {e}^{\mathrm{5}} }+…=\frac{{log}\left(\pi\right)+\mathrm{1}−{log}\left(\pi{e}−\mathrm{1}\right)}{\pi{e}−\mathrm{1}} \\ $$ Terms of Service Privacy…