Question Number 134530 by I want to learn more last updated on 04/Mar/21 $$\mathrm{The}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{a}\:\mathrm{train}\:\mathrm{is}\:\mathrm{reduced}\:\mathrm{from}\:\:\mathrm{80km}/\mathrm{hr}\:\:\mathrm{to}\:\:\mathrm{40km}/\mathrm{hr}\:\:\mathrm{in}\:\mathrm{a} \\ $$$$\mathrm{distance}\:\mathrm{of}\:\:\mathrm{500m}\:\:\mathrm{on}\:\mathrm{applying}\:\mathrm{the}\:\mathrm{brakes}. \\ $$$$\left(\mathrm{i}\right)\:\:\mathrm{How}\:\mathrm{much}\:\mathrm{further}\:\mathrm{will}\:\mathrm{the}\:\mathrm{train}\:\mathrm{travels}\:\mathrm{before}\:\mathrm{coming}\:\mathrm{to}\:\mathrm{rest}. \\ $$$$\left(\mathrm{ii}\right)\:\:\mathrm{Assuming}\:\mathrm{the}\:\mathrm{retardation}\:\mathrm{remains}\:\mathrm{constant},\:\mathrm{how}\:\mathrm{long}\:\mathrm{will}\:\mathrm{it} \\ $$$$\mathrm{take}\:\mathrm{to}\:\mathrm{bring}\:\mathrm{the}\:\mathrm{train}\:\mathrm{to}\:\mathrm{rest}\:\mathrm{after}\:\mathrm{the}\:\mathrm{application}\:\mathrm{of}\:\mathrm{the}\:\mathrm{brakes}? \\ $$ Answered…
Question Number 3410 by 123456 last updated on 13/Dec/15 $$\mathrm{lets}\:\left({u},{v},{w}\right)\in\mathbb{C}^{\mathrm{3}} \:\mathrm{such}\:\mathrm{that}\:{uvw}\neq\mathrm{0},\:\mathrm{proof} \\ $$$$\mathrm{that}\:\left(\mathrm{or}\:\mathrm{give}\:\mathrm{a}\:\mathrm{counter}\:\mathrm{example}\right) \\ $$$$\frac{{v}}{{u}}=\frac{{w}}{{v}}\wedge\mid{u}\mid=\mid{v}\mid=\mid{w}\mid\wedge{u}\neq{w}\Rightarrow{u}+{v}+{w}=\mathrm{0} \\ $$ Commented by RasheedSindhi last updated on 13/Dec/15 $$\mathcal{W}{hat}\:{is}\:{meant}\:{by}\:{u},{v},{w}\in\mathbb{C}^{\mathrm{3}}…
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Question Number 134439 by Dwaipayan Shikari last updated on 03/Mar/21 $${sin}\mathrm{1}−\frac{{sin}\mathrm{2}}{\mathrm{2}}+\frac{{sin}\mathrm{3}}{\mathrm{3}}−\frac{{sin}\mathrm{4}}{\mathrm{4}}+…=\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Answered by mnjuly1970 last updated on 03/Mar/21 $$\:\:\:\boldsymbol{\Omega}=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}−\mathrm{1}} {sin}\left({nx}\right)}{{n}}=\:\:\: \\…
Question Number 3337 by Yozzi last updated on 11/Dec/15 $$\:\: \\ $$$$\:\:\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ast\:\:\:\ast\:\:\:\ast \\ $$$$\:\:\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast \\ $$$$\:\:\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast \\ $$$$\:\:\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\ast \\ $$$$\:\:\:\:\:\ast\:\:\:\ast\:\:\:\ast\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ast\:\:\:\ast\:\:\:\ast \\ $$$$\:\:\:\:\:\dashleftarrow\dashleftarrow\:\:\:\:\:\:\:\:\:\:\:\:\:\dashleftarrow\dashleftarrow \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{h}_{\mathrm{1}} \:\:\:\:\:\:\:\:\:{h}_{\mathrm{2}}…
Question Number 134399 by Chhing last updated on 03/Mar/21 Commented by Chhing last updated on 03/Mar/21 $$\:\mathrm{Solve}\:\mathrm{differentail}\:\mathrm{equation} \\ $$$$\:\mathrm{help}\:\mathrm{me} \\ $$ Terms of Service Privacy…
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Question Number 134369 by I want to learn more last updated on 02/Mar/21 Answered by Dwaipayan Shikari last updated on 03/Mar/21 $${Vertical}\:{Velocity}\: \\ $$$${v}^{\mathrm{2}} ={u}^{\mathrm{2}}…
Question Number 68830 by Rio Michael last updated on 15/Sep/19 $${please}\:{can}\:{someone}\:{check}\:{question}\:\:\:\mathrm{68728} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 134339 by subhambiswas last updated on 02/Mar/21 $$\mathrm{i}\:\mathrm{can}\:\mathrm{not}\:\mathrm{find}\:\mathrm{my}\:\mathrm{saved}\:\mathrm{pdf}\:\mathrm{please}\:\mathrm{tell}\:\mathrm{me}\:\mathrm{the}\:\mathrm{process}\:\mathrm{to}\:\mathrm{find}\:\mathrm{my}\:\mathrm{pdf} \\ $$ Commented by mr W last updated on 02/Mar/21 $${they}\:{are}\:{all}\:{saved}\:{in} \\ $$$${sdcard}/{tinkutara}/{maths} \\ $$…