Question Number 223954 by MASANJAJJ last updated on 10/Aug/25 Answered by som(math1967) last updated on 11/Aug/25 $$\:{x}=\angle{BDC} \\ $$$$\angle{DBA}=\angle{BCD} \\ $$$$\:\therefore{x}=\mathrm{10}+\mathrm{90}−{x}\Rightarrow{x}=\mathrm{50} \\ $$ Answered by…
Question Number 223896 by MASANJAJJ last updated on 08/Aug/25 Commented by mr W last updated on 08/Aug/25 $${y}=\mathrm{81}° \\ $$$${x}\:{can}\:{not}\:{be}\:{determined},\:{because}\:{it} \\ $$$${is}\:{not}\:{clear}\:{what}\:{you}\:{mean}\:{with}\:{the} \\ $$$${angle}\:\angle{AOB}.\:{do}\:{you}\:{mean}\: \\…
Question Number 223851 by Tawa11 last updated on 06/Aug/25 Answered by mr W last updated on 07/Aug/25 Commented by mr W last updated on 08/Aug/25…
Question Number 223779 by MASANJAJJ last updated on 04/Aug/25 Answered by parthasc last updated on 04/Aug/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 223666 by MASANJAJJ last updated on 01/Aug/25 Answered by mr W last updated on 01/Aug/25 Commented by mr W last updated on 02/Aug/25…
Question Number 223591 by Tawa11 last updated on 31/Jul/25 Commented by ajfour last updated on 31/Jul/25 $${Very}\:{nice}\:{Question}! \\ $$ Commented by Tawa11 last updated on…
Question Number 223255 by profrey last updated on 19/Jul/25 $${Which}\:{of}\:{the}\:{following}\:{complex} \\ $$$${numbers}\:{is}\:{equivalent}\:{to}\:\frac{\mathrm{3}−\mathrm{5}{i}}{\mathrm{8}+\mathrm{2}{i}}?\left({Note}:\:{i}=\sqrt{\left.−\mathrm{1}\right)}\right. \\ $$$$\left.{A}\right)\frac{\mathrm{3}}{\mathrm{8}}−\frac{\mathrm{5}{i}}{\mathrm{2}} \\ $$$$ \\ $$$$\left.{B}\right)\frac{\mathrm{3}}{\mathrm{8}}+\frac{\mathrm{5}{i}}{\mathrm{2}} \\ $$$$\: \\ $$$$\left.{C}\right)\frac{\mathrm{7}}{\mathrm{34}}−\frac{\mathrm{23}{i}}{\mathrm{34}} \\ $$$$ \\…
Question Number 223101 by Jubr last updated on 14/Jul/25 Commented by Tawa11 last updated on 15/Jul/25 $$?\:\:=\:\:\frac{\mathrm{16}}{\mathrm{25}}\left(?\:\:+\:\:\mathrm{76}.\mathrm{5}\right) \\ $$$$\therefore\:\:\:\:?\:\:\:=\:\:\:\mathrm{136}\:\mathrm{cm}^{\mathrm{2}} \\ $$ Commented by mr W…
Question Number 222961 by Jubr last updated on 12/Jul/25 Answered by mr W last updated on 12/Jul/25 Commented by mr W last updated on 12/Jul/25…
Question Number 222995 by Jubr last updated on 12/Jul/25 Answered by mr W last updated on 12/Jul/25 $${T}={tension}\:{string}\:{around}\:{the}\:{pulley} \\ $$$${A}={acceleration}\:{of}\:{block}\:{M} \\ $$$${a}={acceleration}\:{of}\:{block}\:{m} \\ $$$${assume}\:{there}\:{is}\:{no}\:{friction}. \\…