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Question-131935

Question Number 131935 by Salman_Abir last updated on 09/Feb/21 Answered by physicstutes last updated on 10/Feb/21 $$\mathrm{2CH}_{\mathrm{3}} \mathrm{OH}\:+\:\mathrm{3O}_{\mathrm{2}} \:\rightarrow\mathrm{2}\:\mathrm{CO}_{\mathrm{2}} \:+\:\mathrm{4}\:\mathrm{H}_{\mathrm{2}} \mathrm{O} \\ $$$$\mathrm{number}\:\mathrm{of}\:\mathrm{moles}\:\mathrm{of}\:\mathrm{CH}_{\mathrm{3}} \mathrm{OH}: \\…

Question-66356

Question Number 66356 by sandeepkeshari0797@gmail.com last updated on 13/Aug/19 Answered by $@ty@m123 last updated on 13/Aug/19 $${Let}\:{the}\:{number}=\mathrm{10}{x}+{y} \\ $$$${ATQ}, \\ $$$$\mathrm{9}\left(\mathrm{10}{x}+{y}\right)=\mathrm{2}\left(\mathrm{10}{y}+{x}\right) \\ $$$$\mathrm{90}{x}+\mathrm{9}{y}=\mathrm{20}{y}+\mathrm{2}{x} \\ $$$$\mathrm{88}{x}=\mathrm{11}{y}…

n-1-1-n-e-2pin-1-

Question Number 131877 by Dwaipayan Shikari last updated on 09/Feb/21 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{n}\left({e}^{\mathrm{2}\pi{n}} −\mathrm{1}\right)} \\ $$ Commented by Dwaipayan Shikari last updated on 09/Feb/21 $${I}\:{have}\:{found}\:…

1-1-3-1-2-3-1-5-3-1-10-3-1-17-3-1-26-3-1-37-3-1-50-3-1-65-3-1-82-3-1-101-3-

Question Number 131795 by Dwaipayan Shikari last updated on 08/Feb/21 $$\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{5}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{10}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{17}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{26}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{37}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{50}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{65}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{82}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{101}^{\mathrm{3}} }+… \\ $$ Answered…