Question Number 60143 by pete last updated on 18/May/19 $$\mathrm{Two}\:\mathrm{passenger}\:\mathrm{trains},\:\mathrm{A}\:\mathrm{and}\:\mathrm{B},\:\mathrm{450km}\:\mathrm{apart}, \\ $$$$\mathrm{start}\:\mathrm{to}\:\mathrm{move}\:\mathrm{towards}\:\mathrm{each}\:\mathrm{other}\:\mathrm{at}\:\mathrm{the} \\ $$$$\mathrm{same}\:\mathrm{time}\:\mathrm{and}\:\mathrm{meet}\:\mathrm{after}\:\mathrm{2}\:\mathrm{hours}.\:\mathrm{If}\:\mathrm{train}\:\mathrm{B}, \\ $$$$\mathrm{travels}\:\frac{\mathrm{8}}{\mathrm{7}}\:\mathrm{as}\:\mathrm{fast}\:\mathrm{as}\:\mathrm{train}\:\mathrm{A},\:\mathrm{find}\:\mathrm{the}\:\mathrm{speed} \\ $$$$\mathrm{of}\:\mathrm{each}\:\mathrm{train}. \\ $$ Answered by tanmay last updated…
Question Number 60135 by Tawa1 last updated on 18/May/19 Answered by tanmay last updated on 18/May/19 $${q}_{\mathrm{1}} =\mathrm{8}.\mathrm{5}×\mathrm{10}^{−\mathrm{6}} {C}\:{at}\:{x}_{\mathrm{1}} =\mathrm{3}.\mathrm{0}×\mathrm{10}^{−\mathrm{2}} {meter} \\ $$$${q}_{\mathrm{2}} =−\mathrm{21}×\mathrm{10}^{−\mathrm{6}} {C}\:{at}\:{x}_{\mathrm{2}}…
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Question Number 191129 by Mastermind last updated on 18/Apr/23 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}\:: \\ $$$$\mathrm{x}\:+\:\mathrm{ln}\left(\mathrm{1}−\mathrm{x}\right)\:=\:\mathrm{0}.\mathrm{1614} \\ $$$$ \\ $$$$\mathrm{Help}! \\ $$ Answered by Skabetix last updated on 18/Apr/23…
Question Number 125585 by Dwaipayan Shikari last updated on 12/Dec/20 $$\frac{\left(\frac{\mathrm{1}}{\mathrm{1}!}\right)^{\mathrm{2}} −\left(\frac{\mathrm{1}}{\mathrm{2}!}\right)^{\mathrm{2}} +\left(\frac{\mathrm{1}}{\mathrm{3}!}\right)^{\mathrm{2}} −\left(\frac{\mathrm{1}}{\mathrm{4}!}\right)^{\mathrm{2}} +…\:}{\left(\frac{\mathrm{1}}{\mathrm{1}!}\right)^{\mathrm{2}} +\left(\frac{\mathrm{1}}{\mathrm{2}!}\right)^{\mathrm{2}} +\left(\frac{\mathrm{1}}{\mathrm{3}!}\right)^{\mathrm{2}} +……} \\ $$ Commented by Dwaipayan Shikari last…
Question Number 60021 by Tawa1 last updated on 17/May/19 Answered by tanmay last updated on 17/May/19 $${dW}=\overset{\rightarrow} {{F}}.{d}\overset{\rightarrow} {{r}} \\ $$$$\:\:\:\:\:\:\:\:\:={Fdrco}\theta \\ $$$$=\frac{\mathrm{1}}{\mathrm{4}\pi\epsilon_{\mathrm{0}} }\frac{{q}_{\mathrm{1}} {q}_{\mathrm{2}}…
Question Number 60022 by meme last updated on 17/May/19 $${construct}\:{M}^{'} \:{z}^{'} =\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{{z}+\mid{z}\mid}{\mathrm{3}}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 60001 by Tawa1 last updated on 16/May/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 191069 by uchihayahia last updated on 17/Apr/23 $$ \\ $$$$\:{both}\:{has}\:{same}\:{number}\:{of}\:{degrees},\:{edges} \\ $$$$\:{and}\:{vertices},\:{i}\:{think}\:{the}\:{graph}\:{below}\:{are}\:{not} \\ $$$$\:{isomorhic}\:{hos}\:{do}\:{i}\:{prove}\:{it}? \\ $$$$ \\ $$ Commented by uchihayahia last updated…
Question Number 125490 by Dwaipayan Shikari last updated on 11/Dec/20 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{x}^{\mathrm{3}} −\mathrm{2}}{\left({x}^{\mathrm{3}} +\mathrm{1}\right)^{\mathrm{2}} }\sqrt{{x}^{\mathrm{3}} −{x}^{\mathrm{2}} +\mathrm{1}}\:{dx} \\ $$ Terms of Service Privacy Policy…