Question Number 58350 by tanmay last updated on 21/Apr/19 Commented by tanmay last updated on 21/Apr/19 $${this}\:{is}\:{not}\:{a}\:{question}\:{but}\:{may}\:{help}\:{other} \\ $$ Commented by maxmathsup by imad last…
Question Number 123845 by Akeyz last updated on 28/Nov/20 Commented by TANMAY PANACEA last updated on 28/Nov/20 $${n}=\mathrm{1} \\ $$$$\frac{\mathrm{8}+\mathrm{27}}{\mathrm{12}+\mathrm{18}}=\frac{\mathrm{35}}{\mathrm{30}}=\frac{\mathrm{7}}{\mathrm{6}} \\ $$ Answered by floor(10²Eta[1])…
Question Number 189375 by moh777 last updated on 15/Mar/23 $$ \\ $$$$\:\:\:\:{show}\:{that}\:: \\ $$$$\:\:\:\:\frac{\mathrm{1}}{{cscx}\:+\:{cot}\:{x}}\:=\:{cscx}\:−\:{cot}\:{x} \\ $$$$ \\ $$$$ \\ $$ Answered by Ar Brandon last…
Question Number 123823 by Dwaipayan Shikari last updated on 28/Nov/20 Answered by mindispower last updated on 29/Nov/20 $$\left(\mathrm{1}+{x}\right)^{{a}} =\mathrm{1}+\underset{{n}\geqslant\mathrm{1}} {\sum}\frac{\mathrm{1}}{{n}!}\underset{{k}=\mathrm{0}} {\overset{{n}−\mathrm{1}} {\prod}}\left({a}−{k}\right).{x}^{{n}} \\ $$$$\left(\mathrm{1}−{ksin}^{\mathrm{2}} \left({x}\right)\right)^{−\frac{\mathrm{1}}{\mathrm{2}}}…
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Question Number 123807 by Dwaipayan Shikari last updated on 28/Nov/20 $$\frac{\left(\frac{\mathrm{1}}{\mathrm{2}}\right)!\left(\mathrm{1}\right)!}{\left(\frac{\mathrm{5}}{\mathrm{2}}\right)!}−\frac{\left(\frac{\mathrm{3}}{\mathrm{2}}\right)!\left(\mathrm{2}\right)!}{\left(\frac{\mathrm{9}}{\mathrm{2}}\right)!}+\frac{\left(\frac{\mathrm{5}}{\mathrm{2}}\right)!\mathrm{3}!}{\left(\frac{\mathrm{13}}{\mathrm{2}}\right)!}−\frac{\left(\frac{\mathrm{7}}{\mathrm{2}}\right)!\mathrm{4}!}{\left(\frac{\mathrm{17}}{\mathrm{2}}\right)!}+…. \\ $$ Commented by Dwaipayan Shikari last updated on 28/Nov/20 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{{n}+\mathrm{1}} \frac{\Gamma\left({n}+\frac{\mathrm{1}}{\mathrm{2}}\right)\Gamma\left({n}+\mathrm{1}\right)}{\Gamma\left(\mathrm{2}{n}+\frac{\mathrm{3}}{\mathrm{2}}\right)}…
Question Number 123794 by mnjuly1970 last updated on 28/Nov/20 $$\:\:\:\:\:\:\:\:\:\:\:…{mathematical}\:\:{analysis}… \\ $$$$\:{suppose}\:\:\left({X}_{\mathrm{1}} ,\tau_{\mathrm{1}} \right)\:{and}\:\left({X}_{\mathrm{2}} ,\tau_{\mathrm{2}} \right) \\ $$$$\:{are}\:{two}\:{topological}\:{spaces}. \\ $$$${prove}\:\:{f}:\left({X}_{\mathrm{1}} ,\tau_{\mathrm{1}} \right)\rightarrow\left({X}_{\mathrm{2}} ,\tau_{\mathrm{2}} \right)\:{is}\: \\…
Question Number 58245 by tanmay last updated on 20/Apr/19 $${if}\:{log}\left({a}+{b}+{c}\right)={loga}+{logb}+{logc} \\ $$$${prove} \\ $$$${log}\left(\frac{\mathrm{2}{a}}{\mathrm{1}−{a}^{\mathrm{2}} }+\frac{\mathrm{2}{b}}{\mathrm{1}−{b}^{\mathrm{2}} }+\frac{\mathrm{2}{c}}{\mathrm{1}−{c}^{\mathrm{2}} }\right)={log}\left(\frac{\mathrm{2}{a}}{\mathrm{1}−{a}^{\mathrm{2}} }\right)+{log}\left(\frac{\mathrm{2}{b}}{\mathrm{1}−{b}^{\mathrm{2}} }\right)+{log}\left(\frac{\mathrm{2}{c}}{\mathrm{1}−{c}^{\mathrm{2}} }\right) \\ $$ Answered by Kunal12588…
Question Number 123776 by Dwaipayan Shikari last updated on 28/Nov/20 $${Another}\:{unanswered}\:{question} \\ $$$$\frac{{log}\mathrm{1}}{\:\sqrt{\mathrm{1}}}−\frac{{log}\mathrm{3}}{\:\sqrt{\mathrm{3}}}+\frac{{log}\mathrm{5}}{\:\sqrt{\mathrm{5}}}−\frac{{log}\mathrm{7}}{\:\sqrt{\mathrm{7}}}+..=\left(\frac{\pi}{\mathrm{4}}−\frac{\gamma}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}{log}\left(\mathrm{2}\pi\right)\right)\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}−.\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 189292 by Rupesh123 last updated on 14/Mar/23 Commented by talminator2856792 last updated on 14/Mar/23 $$\:\mathrm{the}\:\mathrm{question}\:\mathrm{is}\:\mathrm{incomplete}. \\ $$$$\:\mathrm{it}\:\mathrm{doesnt}\:\mathrm{say}\:\mathrm{how}\:\mathrm{the}\:\mathrm{chords}\:\mathrm{are}\:\mathrm{chosen}\: \\ $$$$\:\mathrm{from}\:\mathrm{the}\:\mathrm{four}\:\mathrm{points}. \\ $$ Commented by…