Question Number 211315 by MWSuSon last updated on 05/Sep/24 $$\mathrm{does}\:\mathrm{anyone}\:\mathrm{know}\:\mathrm{if}\:\mathrm{charpit}'\mathrm{s}\:\mathrm{method}\:\mathrm{for}\:\mathrm{solving}\: \\ $$$$\mathrm{PDE}\:\mathrm{can}\:\mathrm{be}\:\mathrm{used}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{second}\:\mathrm{order}\:\mathrm{pde}? \\ $$$$\mathrm{Also}\:\mathrm{is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{reduce}\:\mathrm{second}\:\mathrm{order}\:\mathrm{PDE}\:\mathrm{to}\:\mathrm{first}\:\mathrm{order}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 210912 by Tawa11 last updated on 21/Aug/24 A uniform stick AB of length L and mass M is balanced horizontally on a knife…
Question Number 210765 by shhhh last updated on 18/Aug/24 Answered by Berbere last updated on 19/Aug/24 $$\begin{cases}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{4}}\\{\left({x}−\mathrm{3}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{9}\Rightarrow−\mathrm{6}{x}=−\mathrm{4}}\end{cases} \\ $$$${x}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$${y}^{\mathrm{2}}…
Question Number 210228 by MASANJAJJ last updated on 03/Aug/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 210227 by MASANJAJJ last updated on 03/Aug/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 210180 by BHOOPENDRA last updated on 02/Aug/24 Commented by mr W last updated on 02/Aug/24 $${is}\:{the}\:{load}\:{acting}\:{in}\:{the}\:{shear}\:{center} \\ $$$${in}\:{both}\:{cases}? \\ $$ Commented by BHOOPENDRA…
Question Number 210017 by klipto last updated on 28/Jul/24 $$ \\ $$$$\boldsymbol{\mathrm{MATH}}−\boldsymbol{\mathrm{WHIZZKID}} \\ $$$$\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{kamke}}\:\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{genral}} \\ $$$$\boldsymbol{\mathrm{solution}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{differential}}\:\boldsymbol{\mathrm{equation}} \\ $$$$\mathrm{1}.\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} \boldsymbol{\mathrm{y}}''+\boldsymbol{\mathrm{x}}^{\mathrm{2}} \boldsymbol{\mathrm{y}}'−\mathrm{2}\boldsymbol{\mathrm{y}}=\mathrm{0} \\ $$$$−−−−−−−−− \\ $$$$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{forbenius}}\:\boldsymbol{\mathrm{mtd}} \\…
Question Number 209944 by Tawa11 last updated on 26/Jul/24 Commented by mr W last updated on 26/Jul/24 $${f}=\frac{\mathrm{100}×\mathrm{6}}{\mathrm{2}\pi×\mathrm{2}.\mathrm{5}}=\mathrm{38}.\mathrm{2}\:{Hz} \\ $$ Terms of Service Privacy Policy…
Question Number 209886 by Tawa11 last updated on 24/Jul/24 Commented by Tawa11 last updated on 25/Jul/24 $$\mathrm{g}\:=\:\mathrm{9}.\mathrm{8}\:\mathrm{ms}^{−\mathrm{2}} \\ $$ Answered by mr W last updated…
Question Number 209847 by SonGoku last updated on 23/Jul/24 Answered by mr W last updated on 23/Jul/24 $${depth}\:={h} \\ $$$${h}=\sqrt{\mathrm{23}^{\mathrm{2}} −\left(\frac{\mathrm{53}−\mathrm{41}}{\mathrm{2}}\right)^{\mathrm{2}} }=\sqrt{\mathrm{493}}=\mathrm{22}.\mathrm{20}{m} \\ $$$${cross}\:{section}\:{area}\:={A} \\…