Question Number 222373 by Tawa11 last updated on 24/Jun/25 An 80 kg man floats with 4% of his volume above the surface in fresh water.what…
Question Number 222276 by Nicholas666 last updated on 27/Jun/25 $$ \\ $$$$\:\mathrm{Prove};\:\underset{{k}\:=\:\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{{k}}{\mathrm{sinh}\left(\pi{k}\right)}\:=\:\frac{\Gamma\left(\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{4}} −\:\mathrm{8}\pi^{\mathrm{2}} }{\mathrm{32}\pi^{\mathrm{3}} }\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 222195 by MathematicalUser2357 last updated on 20/Jun/25 $${f}\left({x}\right)={x}^{\mathrm{3}} +\sqrt{{x}}+\mathrm{sin}\:{x} \\ $$$${f}=? \\ $$ Answered by MrGaster last updated on 20/Jun/25 Commented by MathematicalUser2357…
Question Number 221962 by Tawa11 last updated on 13/Jun/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 221913 by Tawa11 last updated on 12/Jun/25 A man standing 10m away from a plane mirror moves towards the mirror with a speed…
Question Number 221788 by Tawa11 last updated on 10/Jun/25 Answered by mr W last updated on 10/Jun/25 Commented by mr W last updated on 10/Jun/25…
Question Number 221814 by Tawa11 last updated on 10/Jun/25 Answered by wewji12 last updated on 11/Jun/25 $$\mathrm{log}_{{a}} \left({b}\right)=\frac{\mathrm{log}_{{b}} \left({c}\right)}{\mathrm{log}_{{a}} \left({c}\right)} \\ $$$$\frac{\mathrm{ln}\left(\mathrm{2}\right)}{\mathrm{ln}\left({x}+\mathrm{1}\right)}+\frac{\mathrm{ln}\left(\mathrm{3}\right)}{\mathrm{ln}\left({x}+\mathrm{2}\right)}+\frac{\mathrm{ln}\left(\mathrm{4}\right)}{\mathrm{ln}\left({x}+\mathrm{3}\right)}=\mathrm{3} \\ $$$$\mathrm{if}\:{x}=\mathrm{1}\: \\…
Question Number 221638 by ASAD7391 last updated on 08/Jun/25 Answered by som(math1967) last updated on 09/Jun/25 $$\:\:\frac{\mathrm{100}}{\mathrm{16}}×\mathrm{100}=\mathrm{625} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 221500 by gautamprajapati last updated on 07/Jun/25 $$\boldsymbol{{Ip}}\:=\:\frac{\mathrm{p1q0}}{\mathrm{p0q0}}×\mathrm{100} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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