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Question Number 189754 by Tawa11 last updated on 21/Mar/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 189755 by Tawa11 last updated on 21/Mar/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 58675 by ajfour last updated on 27/Apr/19 Commented by ajfour last updated on 27/Apr/19 $$\mathrm{ABCD}\:\mathrm{is}\:\mathrm{a}\:\mathrm{square};\:\mathrm{while},\:\mathrm{PQM}\:\mathrm{is} \\ $$$$\mathrm{a}\:\mathrm{sector}.\:\mathrm{Find}\:\mathrm{in}\:\mathrm{what}\:\mathrm{proportion} \\ $$$$\mathrm{are}\:\mathrm{radii}\:\mathrm{b},\:\mathrm{r},\:\mathrm{g}\:\left(\mathrm{blue},\:\mathrm{red},\:\mathrm{green}\right. \\ $$$$\left.\mathrm{respectively}\right). \\ $$…
Question Number 189716 by Mastermind last updated on 20/Mar/23 Answered by mr W last updated on 21/Mar/23 $$\mathrm{5}!×\mathrm{2}!=\mathrm{240} \\ $$ Commented by Mastermind last updated…
Question Number 124178 by Dwaipayan Shikari last updated on 01/Dec/20 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{\mathrm{1}}{\:\sqrt{{cos}^{\mathrm{4}} {x}+{sin}^{\mathrm{4}} {x}}}{dx} \\ $$ Commented by Dwaipayan Shikari last updated on 01/Dec/20…
Question Number 189710 by Mastermind last updated on 20/Mar/23 Answered by aleks041103 last updated on 20/Mar/23 $${V}\left(\mathrm{12}\right)={V}\left(\mathrm{21}\right)−{V}\left(\mathrm{21}−\mathrm{15}\right)={V}\left(\mathrm{21}\right)−{V}\left(\mathrm{6}\right) \\ $$$${V}\left(\mathrm{12}\right)=\mathrm{2}{V}\left(\mathrm{6}\right) \\ $$$$\Rightarrow\frac{\mathrm{3}}{\mathrm{2}}{V}\left(\mathrm{12}\right)={V}\left(\mathrm{21}\right)\Rightarrow{V}\left(\mathrm{12}\right)=\frac{\mathrm{2}}{\mathrm{3}}{V}\left(\mathrm{21}\right) \\ $$$$\Rightarrow{the}\:{water}\:{is}\:\frac{\mathrm{2}}{\mathrm{3}}\:{of}\:{the}\:{bottle} \\ $$$$\boldsymbol{{Note}}\:\mathrm{1}:\:{V}\left({x}\right)\:{is}\:{the}\:{volume}\:{of}\:{water}\:{for}\:…
Question Number 58584 by sclee last updated on 25/Apr/19 $$\frac{{X}−\lambda}{\:\sqrt{\frac{\lambda}{{n}}}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 58526 by Tawa1 last updated on 24/Apr/19 Commented by Tawa1 last updated on 24/Apr/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{centroid}\:\mathrm{of}\:\mathrm{the}\:\mathrm{shape} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 58519 by tanmay last updated on 24/Apr/19 Commented by tanmay last updated on 24/Apr/19 Answered by tanmay last updated on 26/Apr/19 $${nobody}\:{responded}\:{to}\:{these}\:{questions}… \\…