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n-1-m-1-1-m-2-n-2-2-

Question Number 221228 by Nicholas666 last updated on 27/May/25 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}\:=\:\mathrm{1}} {\overset{\infty} {\sum}}\:\underset{{m}\:=\:\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\left({m}^{\mathrm{2}} \:+\:{n}^{\mathrm{2}} \right)^{\mathrm{2}} } \\ $$$$ \\ $$ Answered by…

Question-220495

Question Number 220495 by Jubr last updated on 13/May/25 Commented by mr W last updated on 14/May/25 $${i}\:{guess}\:{even}\:{you}\:{also}\:{don}'{t}\:{know} \\ $$$${what}\:{the}\:{question}\:{means}\:{with}\:{all} \\ $$$${the}\:{arrows}.\:{when}\:{the}\:{question}\:{is} \\ $$$${unclear},\:{it}\:{can}\:{not}\:{be}\:{solved}.\:{so} \\…

Question-220340

Question Number 220340 by Noorzai last updated on 11/May/25 Answered by som(math1967) last updated on 11/May/25 $$\:{b}^{\mathrm{2}} {a}−{a}^{\mathrm{2}} {b}+{c}^{\mathrm{2}} {b}−{c}^{\mathrm{2}} {a}+{b}^{\mathrm{2}} {c}−{a}^{\mathrm{2}} {c} \\ $$$$={ba}\left({b}−{a}\right)+{c}^{\mathrm{2}}…