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I-have-a-background-in-building-design-but-I-have-great-interest-in-Mathematics-That-s-one-major-reason-why-I-joined-this-platform-cause-I-did-little-or-no-maths-in-my-undergraduate-days-as-a-buildin

Question Number 206591 by necx122 last updated on 19/Apr/24 $${I}\:{have}\:{a}\:{background}\:{in}\:{building}\:{design} \\ $$$${but}\:{I}\:{have}\:{great}\:{interest}\:{in}\:{Mathematics}. \\ $$$${That}'{s}\:{one}\:{major}\:{reason}\:{why}\:{I}\:{joined} \\ $$$${this}\:{platform}\:{cause}\:{I}\:{did}\:{little}\:{or}\:{no} \\ $$$${maths}\:{in}\:{my}\:{undergraduate}\:{days}\:{as}\:{a} \\ $$$${building}\:{design}\:{student}. \\ $$$$ \\ $$$${This}\:{forum}\:{has}\:{contributed}\:{greatly}\:{to} \\…

Question-206452

Question Number 206452 by langatfredrick last updated on 15/Apr/24 Answered by A5T last updated on 15/Apr/24 $${If}\:{remainder}\:{means}\:\mid{x}−{y}\mid,\:{then}: \\ $$$$\frac{{t}_{{x}} }{{x}}={x};\frac{{t}_{{y}} }{{y}}={y}\Rightarrow{t}_{\mid{x}−{y}\mid} =\mid{t}_{{x}} −{t}_{{y}} \mid=\mid{x}^{\mathrm{2}} −{y}^{\mathrm{2}}…

Hi-everyone-This-is-not-a-question-per-say-sorry-bout-that-It-s-just-that-for-past-4-years-to-type-math-messages-to-my-friends-text-messages-I-ve-been-painfully-using-the-two-most-famous-and

Question Number 206311 by TheHoneyCat last updated on 11/Apr/24 $$\mathrm{Hi}\:\mathrm{everyone}… \\ $$$$\mathrm{This}\:\mathrm{is}\:\mathrm{not}\:\mathrm{a}\:\mathrm{question}\:\mathrm{per}\:\mathrm{say}\:\left(\mathrm{sorry}\:'\mathrm{bout}\right. \\ $$$$\left.\mathrm{that}\right).\:\mathrm{It}'\mathrm{s}\:\mathrm{just}\:\mathrm{that}\:\mathrm{for}\:\mathrm{past}\:\mathrm{4}\:\mathrm{years},\:\mathrm{to}\:\mathrm{type} \\ $$$$\mathrm{math}\:\mathrm{messages}\:\mathrm{to}\:\mathrm{my}\:\mathrm{friends}\:\left(\mathrm{text}\:\mathrm{messages}\right) \\ $$$$\mathrm{I}'\mathrm{ve}\:\mathrm{been}\:\mathrm{painfully}\:\mathrm{using}\:\mathrm{the}\:\mathrm{two}\:\mathrm{most}\:\mathrm{famous} \\ $$$$\mathrm{android}\:\mathrm{ones}\:\left({matheditor}\:\mathrm{and}\:{dxmath}\right). \\ $$$$\mathrm{And}\:\mathrm{I}\:\mathrm{was}\:\mathrm{thinking},\:\mathrm{I}\:\mathrm{realised}\:\mathrm{how}\:\mathrm{typing} \\ $$$$\mathrm{on}\:\mathrm{this}\:\mathrm{app}\:\mathrm{on}\:\mathrm{android}\:\left({matheditor}\right)\:\mathrm{is}\:\mathrm{so} \\…

Question-205915

Question Number 205915 by dodo last updated on 02/Apr/24 Answered by Skabetix last updated on 03/Apr/24 $${Placement}\::\:{U}_{{n}} =\:\mathrm{6}\:\mathrm{000}\:\mathrm{000}\:×\mathrm{1}.\mathrm{03}^{{n}} \\ $$$${Valeur}\:{vehicule}\::\:{V}_{{n}} =\:\mathrm{30}\:\mathrm{000}\:\mathrm{000}\:×\mathrm{0}.\mathrm{95}^{{n}} \\ $$$${En}\:{notant}\:{n}\:{le}\:{nombre}\:{d}\:{annees}\:{on}\:{a}\:: \\ $$$$\mathrm{6}\:\mathrm{000}\:\mathrm{000}\:×\:\mathrm{1}.\mathrm{03}^{{n}}…

Given-A-B-a-b-A-C-b-c-B-C-b-d-then-A-C-A-B-B-C-

Question Number 205070 by dimentri last updated on 07/Mar/24 $$\:\:\:\mathrm{Given}\:\begin{cases}{\mathrm{A}\cap\mathrm{B}=\:\left\{\:\mathrm{a},\:\mathrm{b}\right\}}\\{\mathrm{A}\cap\mathrm{C}\:=\:\left\{\:\mathrm{b},\:\mathrm{c}\right\}\:}\\{\mathrm{B}\cap\mathrm{C}=\:\left\{\:\mathrm{b}\:,\mathrm{d}\:\right\}}\end{cases} \\ $$$$\:\:\:\:\mathrm{then}\:\left(\mathrm{A}\cap\mathrm{C}\right)\:+\:\left(\mathrm{A}\cap\mathrm{B}\right)\:+\:\left(\mathrm{B}\cap\mathrm{C}\right) \\ $$ Commented by JDamian last updated on 07/Mar/24 $${Do}\:{you}\:{mean}\:\:\left(\mathrm{A}\cap\mathrm{C}\right)\:\cup\:\left(\mathrm{A}\cap\mathrm{B}\right)\:\cup\:\left(\mathrm{B}\cap\mathrm{C}\right)\:\:? \\ $$ Commented…

Evaluate-sinx-x-4-x-2-1-dx-I-need-full-detailed-explanation-thank-you-in-advance-

Question Number 204804 by Mastermind last updated on 27/Feb/24 $$\mathrm{Evaluate}\:\int\frac{\mathrm{sinx}}{\mathrm{x}^{\mathrm{4}} +\mathrm{x}^{\mathrm{2}} +\mathrm{1}}\mathrm{dx} \\ $$$$ \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{need}\:\mathrm{full}\:\mathrm{detailed}\:\mathrm{explanation},\:\mathrm{thank}\:\mathrm{you}\:\mathrm{in} \\ $$$$\mathrm{advance}. \\ $$ Commented by TonyCWX08…