Question Number 56215 by necx1 last updated on 12/Mar/19 $$\sqrt{\frac{{x}}{{x}−\mathrm{1}}}+\sqrt{\frac{{x}−\mathrm{1}}{{x}}}=\mathrm{2} \\ $$$$ \\ $$$${find}\:{x} \\ $$ Commented by necx1 last updated on 12/Mar/19 $${I}\:{got}\:{confused}\:{at}\:{a}\:{point}\:{where}\:{i}\:{solved} \\…
Question Number 56213 by necx1 last updated on 12/Mar/19 $${x}\mathrm{sin}\:{x}=\mathrm{5} \\ $$$$ \\ $$$${find}\:{x} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 12/Mar/19 $${use}\:{grhical}\:{apps} \\…
Question Number 56214 by necx1 last updated on 12/Mar/19 $${x}^{{x}} =\mathrm{4} \\ $$$$ \\ $$$${find}\:{x} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 12/Mar/19 $${x}=\mathrm{2}\:{only}\:{one}\:{solution}……
Question Number 56205 by 121194 last updated on 12/Mar/19 $$\mathrm{find}\:\left(\mathrm{or}\:\mathrm{prove}\:\mathrm{it}\:\mathrm{can}'\mathrm{t}\:\mathrm{exist}\right)\:\mathrm{a}\:{f}:\mathbb{R}\rightarrow\mathbb{R}\:\mathrm{diferentiable} \\ $$$$\mathrm{such}\:\mathrm{that} \\ $$$$\underset{{a}−\delta} {\overset{{a}+\delta} {\int}}{f}\left({x}\right){dx}=\mathrm{0},\forall{a}\in\mathbb{R},\delta>\mathrm{0} \\ $$$$\frac{{df}}{{dx}}=\mathrm{0},\forall{x}\in\mathbb{R} \\ $$ Answered by MJS last updated…
Question Number 121739 by Dwaipayan Shikari last updated on 11/Nov/20 $$\frac{\mathrm{1}^{\mathrm{13}} }{{e}^{\mathrm{2}\pi} −\mathrm{1}}+\frac{\mathrm{2}^{\mathrm{13}} }{{e}^{\mathrm{4}\pi} −\mathrm{1}}+\frac{\mathrm{3}^{\mathrm{13}} }{{e}^{\mathrm{6}\pi} −\mathrm{1}}+…. \\ $$ Answered by mindispower last updated on…
Question Number 56190 by Tinku Tara last updated on 11/Mar/19 $$\mathrm{There}\:\mathrm{was}\:\mathrm{a}\:\mathrm{post}\:\mathrm{some}\:\mathrm{time}\:\mathrm{back} \\ $$$$\mathrm{for}\:\mathrm{failed}\:\mathrm{import}.\:\mathrm{Can}\:\mathrm{u}\:\mathrm{please} \\ $$$$\mathrm{resend}\:\mathrm{the}\:\mathrm{email}?\:\mathrm{Email}\:\mathrm{address} \\ $$$$\mathrm{to}\:\mathrm{be}\:\mathrm{used}\:\mathrm{is}\:\mathrm{info}@\mathrm{tinkutara}.\mathrm{com} \\ $$$$\mathrm{Thanks} \\ $$ Terms of Service Privacy…
Question Number 56165 by Tawa1 last updated on 11/Mar/19 Answered by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19 $${A}=\mathrm{6}{cos}\mathrm{36}^{\mathrm{0}} {i}+\mathrm{6}{sin}\mathrm{36}^{{o}} {j} \\ $$$${B}=−\mathrm{7}{i} \\ $$$${A}+{B}=\left(\mathrm{6}{cos}\mathrm{36}^{{o}} −\mathrm{7}\right){i}+\mathrm{6}{sin}\mathrm{36}^{\mathrm{0}} {j}…
Question Number 121697 by Vishal Sharma last updated on 11/Nov/20 $$\:\mathbb{Q}.\:\mathbb{FACTORIZE}− \\ $$$$\:\left(\mathrm{1}\right)\:\mathrm{9x}^{\mathrm{2}} +\mathrm{12xy}+\mathrm{4y}^{\mathrm{2}} \\ $$$$\:\left(\mathrm{2}\right)\:\mathrm{25x}^{\mathrm{2}} −\mathrm{20xy}+\mathrm{16y}^{\mathrm{2}} \\ $$$$\:\left(\mathrm{3}\right)\:\mathrm{36x}^{\mathrm{2}} +\mathrm{42xy}+\mathrm{49y}^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\bigstar\bigstar\mathbb{VISHAL}\bigstar\bigstar \\ $$ Answered…
Question Number 121678 by TITA last updated on 10/Nov/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 121677 by TITA last updated on 10/Nov/20 Commented by TITA last updated on 10/Nov/20 $${please}\:{help} \\ $$ Answered by MJS_new last updated on…