Question Number 186662 by pascal889 last updated on 08/Feb/23 Answered by Frix last updated on 08/Feb/23 $${u}=\sqrt{{x}+\mathrm{1}}\geqslant\mathrm{0}\:\Leftrightarrow\:{x}={u}^{\mathrm{2}} −\mathrm{1} \\ $$$$\frac{{u}^{\mathrm{2}} }{\:\sqrt{{u}+\mathrm{2}}}=\mathrm{2}{u}^{\mathrm{2}} −\mathrm{1} \\ $$$${v}=\sqrt{{u}+\mathrm{2}}\geqslant\sqrt{\mathrm{2}}\:\Leftrightarrow\:{u}={v}^{\mathrm{2}} −\mathrm{1}…
Question Number 186636 by Noorzai last updated on 07/Feb/23 $${x}^{\mathrm{2}} +{x}+\mathrm{1}=\mathrm{0} \\ $$$$\:\:\:{x}^{\mathrm{92}} =? \\ $$ Commented by Rasheed.Sindhi last updated on 07/Feb/23 $${x}^{\mathrm{92}} =\omega,\omega^{\mathrm{2}}…
Question Number 55557 by necx1 last updated on 26/Feb/19 $${Goodday}\:{great}\:{minds}.{Its}\:{been}\:{quite}\:{a} \\ $$$${while}.\:{Please}\:{can}\:{anyone}\:{recommend} \\ $$$${any}\:{site},\:{app}\:{or}\:{video}\:{that}\:{can}\:{explain}\:{the} \\ $$$${elevation}\:{and}\:\mathrm{3}{d}\:{of}\:{shapes}.{Please}\:{I} \\ $$$${sincerely}\:{need}\:{your}\:{help}. \\ $$$$ \\ $$$${Thanks}\:{in}\:{advance}. \\ $$ Terms…
Question Number 121085 by TITA last updated on 05/Nov/20 Commented by TITA last updated on 05/Nov/20 $${please}\:{help} \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 55534 by otchereabdullai@gmail.com last updated on 26/Feb/19 $${A}\:{dish}\:{of}\:{mixed}\:{nut}\:{contains}\:{cashew} \\ $$$${and}\:{peanut}\:.\:{then}\:{two}\:{ounces}\:{of}\: \\ $$$${peanut}\:{are}\:{added}\:{to}\:{the}\:{dish}\:{making} \\ $$$${the}\:{new}\:{mixture}\:{of}\:\mathrm{20\%}\:{cashew}.\: \\ $$$${Sara}\:{like}\:{cashew}\:{so}\:{she}\:{added}\: \\ $$$$\mathrm{2}\:{ounces}\:{of}\:{them}\:{to}\:{the}\:{dish}.\:{The} \\ $$$${mixture}\:{in}\:{the}\:{dish}\:{is}\:{now}\:\:\mathrm{33}.\mathrm{33\%}.\: \\ $$$${Cashews}.\:{what}\:{percentage}\:{of}\:{the}\: \\…
Question Number 121044 by hadis last updated on 05/Nov/20 $$\frac{\mathrm{3}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{2}}=…..\begin{cases}{}\\{}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 55449 by ketto2 last updated on 24/Feb/19 Answered by Kunal12588 last updated on 24/Feb/19 $$\mathrm{16}{y}^{\mathrm{2}} +{xy}−\mathrm{15}{x}^{\mathrm{2}} \\ $$$$=\mathrm{16}{y}^{\mathrm{2}} +\mathrm{16}{xy}−\mathrm{15}{xy}−\mathrm{15}{x}^{\mathrm{2}} \\ $$$$=\mathrm{16}{y}\left({y}+{x}\right)−\mathrm{15}{x}\left({y}+{x}\right) \\ $$$$=\left(\mathrm{16}{y}−\mathrm{15}{x}\right)\left({x}+{y}\right)…
Question Number 55418 by Tawa1 last updated on 23/Feb/19 Commented by tanmay.chaudhury50@gmail.com last updated on 23/Feb/19 $${pls}\:{calculate}\:{sin}\mathrm{2}\theta=\frac{\mathrm{5}}{\mathrm{13}}\:{using}\:{calculatr} \\ $$$${i}\:{have}\:{not}\:{downloaded}\:{scientific}\:{calcuator}.. \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 55375 by Tawa1 last updated on 23/Feb/19 Commented by tanmay.chaudhury50@gmail.com last updated on 23/Feb/19 $${pls}\:{specify}\:{the}\:{point}\:{of}\:{applicstion}\:{of}\:{force} \\ $$$${on}\:{axle}… \\ $$ Answered by mr W…
Question Number 186446 by Mingma last updated on 04/Feb/23 Terms of Service Privacy Policy Contact: info@tinkutara.com