Question Number 186074 by Mastermind last updated on 31/Jan/23 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{div}\left(\mathrm{curl}\overset{−} {\mathrm{A}}\right)=\mathrm{0} \\ $$$$ \\ $$$$ \\ $$$$\mathrm{Help}! \\ $$ Answered by aleks041103 last updated on…
Question Number 120541 by 77731 last updated on 01/Nov/20 Answered by snipers237 last updated on 01/Nov/20 $${Using}\:\:{cos}\left({z}\right)=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} {z}^{\mathrm{2}{n}} }{\left(\mathrm{2}{n}\right)!}\:,\:\mathrm{1}−{cosz}=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} {z}^{\mathrm{2}{n}} }{\left(\mathrm{2}{n}\right)!}\:…
Question Number 54966 by Tawa1 last updated on 15/Feb/19 $$\mathrm{By}\:\mathrm{differentiating}\:\:\:\mathrm{x}\:\sqrt{\mathrm{1}\:+\:\mathrm{x}}\:\:\mathrm{with}\:\mathrm{respect}\:\mathrm{to}\:\mathrm{x}\:, \\ $$$$\mathrm{Evaluate},\:\:\:\:\int_{\:\mathrm{0}} ^{\:\mathrm{2}} \:\frac{\mathrm{x}}{\:\sqrt{\mathrm{1}\:+\:\mathrm{x}}}\:\:\mathrm{dx} \\ $$ Commented by maxmathsup by imad last updated on 17/Feb/19…
Question Number 186026 by Michaelfaraday last updated on 31/Jan/23 Answered by mr W last updated on 31/Jan/23 $$\left({b}\right) \\ $$$${T}_{{A}−{B}} =\mu{m}_{{A}} {g}=\mathrm{0}.\mathrm{35}×\mathrm{25}=\mathrm{8}.\mathrm{75}\:{N}\:\checkmark \\ $$$${T}_{{B}−{C}} =\mu{m}_{{A}}…
Question Number 185996 by Noorzai last updated on 30/Jan/23 Answered by Rasheed.Sindhi last updated on 30/Jan/23 $$\mathrm{M}×\mathrm{3}=\mathrm{18}\Rightarrow\mathrm{M}=\mathrm{6} \\ $$$$\mathrm{2L}+\mathrm{1}=\mathrm{5},\mathrm{15}\Rightarrow\mathrm{L}=\mathrm{2},\mathrm{7}\Rightarrow\mathrm{K}=\mathrm{2},\mathrm{1} \\ $$$$\mathrm{K}+\mathrm{L}+\mathrm{M}=\mathrm{2}+\mathrm{2}+\mathrm{6}=\mathrm{10} \\ $$$$\mathrm{Or} \\ $$$$\mathrm{1}+\mathrm{7}+\mathrm{6}=\mathrm{14}\:\:\:\:\:…
Question Number 185900 by Mingma last updated on 29/Jan/23 Answered by mr W last updated on 29/Jan/23 $${say}\:{AB}={BC}={a} \\ $$$$\angle{ABQ}=\mathrm{15}° \\ $$$${DQ}={a}\left(\mathrm{1}−\mathrm{tan}\:\mathrm{15}°\right) \\ $$$${DR}=\frac{{DQ}}{\mathrm{tan}\:\mathrm{15}°} \\…
Question Number 54825 by Tawa1 last updated on 12/Feb/19 Answered by tanmay.chaudhury50@gmail.com last updated on 12/Feb/19 $${v}_{\mathrm{0}} ={volume}\:{of}\:{glass}\:{bottle}\:{before}\:{heating} \\ $$$${v}_{\mathrm{0}} \left(\mathrm{1}+\gamma_{{g}} \bigtriangleup{T}\right)={volume}\:{of}\:{glass}\:{bottle}\:{after}\:{heating} \\ $$$${v}_{\mathrm{0}} \left(\mathrm{1}+\gamma_{{m}}…
Question Number 120331 by Dwaipayan Shikari last updated on 30/Oct/20 Commented by Dwaipayan Shikari last updated on 30/Oct/20 $${Old}\:{unanswered}\:{Question}.{But}\:{i}\:{want}\:{to}\:{discuss}\:{it} \\ $$ Commented by MJS_new last…
Question Number 54790 by Anju last updated on 11/Feb/19 $${differenciatethefollowing} \\ $$$$\left.{i}\right){x}^{{x}} +\left({sinx}\right)^{{lnx}} = \\ $$$$\left.{ii}\right){sin}^{−\mathrm{1}} \left({tanhx}\right)= \\ $$$$\left.{iii}\right)\sqrt{\mathrm{1}+{x}^{\mathrm{2}} /\mathrm{1}−{x}^{\mathrm{2}} =} \\ $$ Commented by…
Question Number 185847 by Mingma last updated on 28/Jan/23 Terms of Service Privacy Policy Contact: info@tinkutara.com