Question Number 185181 by Noorzai last updated on 18/Jan/23 Commented by Shrinava last updated on 18/Jan/23 $$\mathrm{ln}\left(\mathrm{ln}\left(\mathrm{ln}\left(\mathrm{ln}\left(\mathrm{ln}\left(\mathrm{lnx}\right)\right)\right)\right)\right)+\mathbb{C} \\ $$ Commented by Noorzai last updated on…
Question Number 54051 by Tawa1 last updated on 28/Jan/19 Answered by ajfour last updated on 28/Jan/19 $${y}=\mathrm{20}°\:,\:{z}=\mathrm{110}°\:. \\ $$ Commented by Tawa1 last updated on…
Question Number 185116 by Noorzai last updated on 17/Jan/23 Answered by MJS_new last updated on 17/Jan/23 $$\mathrm{6}^{{x}/\mathrm{2}} +\mathrm{2}^{{x}/\mathrm{2}} =\mathrm{4}^{{x}} \\ $$$$\mathrm{2}^{{x}/\mathrm{2}} \left(\mathrm{3}^{{x}/\mathrm{2}} +\mathrm{1}\right)=\mathrm{2}^{\mathrm{2}{x}} \\ $$$$\mathrm{3}^{{x}/\mathrm{2}}…
Question Number 119564 by Abdulmajeed last updated on 25/Oct/20 $$\left(\frac{\mathrm{3}}{{x}}\:−\:\frac{\mathrm{15}}{\mathrm{2}{y}}\:\right)\:\boldsymbol{\div}\:\frac{\mathrm{6}}{{xy}}\:=\:\frac{\mathrm{6}{y}\:−\:\mathrm{15}{x}}{\mathrm{2}{xy}}\:×\:\frac{{xy}}{\mathrm{6}}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 119529 by I want to learn more last updated on 25/Oct/20 Commented by help last updated on 25/Oct/20 $${Area}\:{of}\:{shaded}\:{portion} \\ $$$$\left\{\frac{\mathrm{4}}{\mathrm{7}}×\mathrm{10}^{\mathrm{2}} \right\}=\mathrm{400}/\mathrm{7}{cm}^{\mathrm{2}} \\…
Question Number 185036 by Mastermind last updated on 16/Jan/23 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{series}\:\mathrm{for}\:\mathrm{cosx}.\:\mathrm{Hence},\: \\ $$$$\mathrm{deduce}\:\mathrm{series}\:\mathrm{sin}^{\mathrm{2}} \mathrm{x}\:\mathrm{and}\:\mathrm{show}\:\mathrm{that}, \\ $$$$\mathrm{if}\:\mathrm{x}\:\mathrm{is}\:\mathrm{small},\:\frac{\mathrm{sin}^{\mathrm{2}} \mathrm{x}−\mathrm{x}^{\mathrm{2}} \mathrm{cosx}}{\mathrm{x}^{\mathrm{4}} }=\frac{\mathrm{1}}{\mathrm{6}}+\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{360}} \\ $$$$\mathrm{approximately}. \\ $$$$ \\ $$$$…
Question Number 185038 by Mastermind last updated on 16/Jan/23 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:\mathrm{values}\:\mathrm{of}\:\mathrm{x}\:\mathrm{for}\:\mathrm{which} \\ $$$$\mathrm{the}\:\mathrm{series}\:\frac{\mathrm{x}}{\mathrm{27}}+\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{125}}+…+\frac{\mathrm{x}^{\mathrm{n}} }{\left(\mathrm{2n}+\mathrm{1}\right)^{\mathrm{3}} }+… \\ $$$$\mathrm{is}\:\mathrm{absolutely}\:\mathrm{convergent}. \\ $$$$ \\ $$$$ \\ $$$$\mathrm{Help}! \\ $$…
Question Number 185014 by Mastermind last updated on 19/Jan/23 $$\mathrm{The}\:\mathrm{relation}\:\mathrm{y}=\mathrm{x}^{\mathrm{2}} +\mathrm{kx}+\mathrm{c},\:\mathrm{where}\:\mathrm{K} \\ $$$$\mathrm{and}\:\mathrm{C}\:\mathrm{are}\:\mathrm{constant}\:\mathrm{passes}\:\mathrm{through} \\ $$$$\mathrm{the}\:\mathrm{points}\:\left(−\mathrm{1},\:−\mathrm{2}\right)\:\mathrm{and}\:\left(\mathrm{1},\:\mathrm{8}\right)\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{coordinate}\:\mathrm{axes}.\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{value} \\ $$$$\mathrm{of}\:\mathrm{C}\:\mathrm{and}\:\mathrm{K}. \\ $$$$ \\ $$$$ \\ $$$$\mathrm{M}.\mathrm{m}…
Question Number 53935 by Mikael_Marshall last updated on 27/Jan/19 $$\sqrt{\mathrm{8}^{{x}−\mathrm{2}} }×\sqrt[{{x}+\mathrm{1}}]{\mathrm{4}^{\mathrm{2}{x}−\mathrm{3}} }=\sqrt[{\mathrm{6}}]{\mathrm{2}^{\mathrm{5}{x}+\mathrm{5}} } \\ $$$$ \\ $$ Answered by Kunal12588 last updated on 27/Jan/19 $$\mathrm{2}^{\frac{\mathrm{3}{x}−\mathrm{6}}{\mathrm{2}}}…
Question Number 119463 by TANMAY PANACEA last updated on 24/Oct/20 $${one}\:{cube}\:{of}\:{side}\:{length}\:\mathrm{3}{cm}\:{is}\:{painted}\:{by}\:{three}\:{colour} \\ $$$${say}\:\left({red}\:{blue}\:{and}\:{black}\right)\:{opposte}\:{face}\:{same}\:{colour} \\ $$$${Now}\:{cube}\:{is}\:{cut}\:{into}\:\mathrm{27}\:{small}\:{cube} \\ $$$$\left.{i}\right){How}\:{many}\:{cube}\:{has}\:{three}\:{face}\:{coloured} \\ $$$$\left.{ii}\right){How}\:{many}\:{cube}\:{two}\:{face}\:{coloured} \\ $$$$\left.{iii}\right){How}\:{many}\:{cube}\:\:{has}\:{no}\:{colour}\:{in}\:{its}\:{face} \\ $$ Commented by…