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Category: Permutation and Combination

Suppose-now-that-Allie-is-actually-70-years-old-and-that-her-life-expectancy-if-cured-is-12-years-rather-than-20-Which-procedure-now-has-the-greather-expected-value-What-if-her-life-expectancy

Question Number 182793 by cortano1 last updated on 14/Dec/22 $$\:{Suppose}\:{now}\:{that}\:{Allie}\:{is}\:{actually} \\ $$$$\mathrm{70}\:{years}\:{old},\:{and}\:{that}\:{her}\:{life}\:{expectancy} \\ $$$$\left({if}\:{cured}\right)\:{is}\:\mathrm{12}\:{years}\:{rather}\:{than} \\ $$$$\mathrm{20}\:.\:{Which}\:{procedure}\:{now}\:{has}\:{the} \\ $$$${greather}\:{expected}\:{value}\:?\:{What}\:{if}\:{her} \\ $$$${life}\:{expectancy}\:{is}\:\mathrm{8}\:{years}? \\ $$ Terms of Service…

Assuming-you-have-enough-coins-of-1-5-10-25-and-50cents-In-how-many-ways-can-you-make-a-change-for-1dollar-

Question Number 117192 by Lordose last updated on 10/Oct/20 $$\mathrm{Assuming}\:\mathrm{you}\:\mathrm{have}\:\mathrm{enough}\:\mathrm{coins}\: \\ $$$$\mathrm{of}\:\mathrm{1},\mathrm{5},\mathrm{10},\mathrm{25},\mathrm{and}\:\mathrm{50cents}.\:\mathrm{In}\:\mathrm{how} \\ $$$$\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{you}\:\mathrm{make}\:\mathrm{a}\:\mathrm{change}\:\mathrm{for}\:\mathrm{1dollar}. \\ $$ Answered by mr W last updated on 10/Oct/20 $${a}+\mathrm{5}{b}+\mathrm{10}{c}+\mathrm{25}{d}+\mathrm{50}{e}=\mathrm{100}…

If-two-events-A-and-B-are-such-that-P-A-c-0-3-P-B-0-4-and-P-A-B-c-0-5-then-P-B-A-B-c-A-0-20-B-0-25-C-0-30-D-0-35-

Question Number 182695 by cortano1 last updated on 13/Dec/22 $$\:\:\mathrm{If}\:\mathrm{two}\:\mathrm{events}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{are}\:\mathrm{such}\: \\ $$$$\:\:\mathrm{that}\:\mathrm{P}\left(\mathrm{A}^{\mathrm{c}} \right)=\mathrm{0}.\mathrm{3}\:;\:\mathrm{P}\left(\mathrm{B}\right)=\mathrm{0}.\mathrm{4}\:\mathrm{and} \\ $$$$\:\:\mathrm{P}\left(\mathrm{A}\cap\mathrm{B}^{\mathrm{c}} \right)=\:\mathrm{0}.\mathrm{5}\:\mathrm{then}\:\mathrm{P}\left(\frac{\mathrm{B}}{\mathrm{A}\cup\mathrm{B}^{\mathrm{c}} }\right)=? \\ $$$$\:\left(\mathrm{A}\right)\:\mathrm{0}.\mathrm{20}\:\:\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{0}.\mathrm{25}\:\:\:\:\:\:\left(\mathrm{C}\right)\:\mathrm{0}.\mathrm{30}\:\:\:\:\:\:\left(\mathrm{D}\right)\:\mathrm{0}.\mathrm{35} \\ $$$$\:\: \\ $$ Commented by…

Find-the-number-m-of-non-negative-integer-solution-of-x-y-z-18-

Question Number 116881 by bemath last updated on 07/Oct/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{m}\:\mathrm{of}\:\mathrm{non}\:\mathrm{negative} \\ $$$$\mathrm{integer}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{x}+\mathrm{y}+\mathrm{z}=\mathrm{18} \\ $$$$ \\ $$ Answered by john santu last updated on 07/Oct/20 $${we}\:{can}\:{view}\:{each}\:{solution}\:,{say}\:{x}=\mathrm{3},\:{y}=\mathrm{7}\:,{z}=\mathrm{8}…

Find-the-number-m-of-ways-to-partition-10-students-into-four-team-so-that-two-team-contains-3-students-and-two-team-contains-2-students-

Question Number 116883 by bemath last updated on 07/Oct/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{m}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{to} \\ $$$$\mathrm{partition}\:\mathrm{10}\:\mathrm{students}\:\mathrm{into}\:\mathrm{four}\:\mathrm{team} \\ $$$$\mathrm{so}\:\mathrm{that}\:\mathrm{two}\:\mathrm{team}\:\mathrm{contains}\:\mathrm{3}\:\mathrm{students} \\ $$$$\mathrm{and}\:\mathrm{two}\:\mathrm{team}\:\mathrm{contains}\:\mathrm{2}\:\mathrm{students}\:. \\ $$ Answered by john santu last updated on…

Question-51287

Question Number 51287 by aseerimad last updated on 25/Dec/18 Answered by mr W last updated on 26/Dec/18 $${let}'{s}\:{look}\:{at}\:{an}\:{example}: \\ $$$${the}\:{number}\:\mathrm{1234}\:{consists}\:{of}\:\mathrm{4}\:{digits}: \\ $$$$\mathrm{1}\:{represents}\:{here}\:{the}\:{value}\:\mathrm{1}×\mathrm{1000} \\ $$$$\mathrm{2}\:{represents}\:{here}\:{the}\:{value}\:\mathrm{2}×\mathrm{100} \\…

How-many-words-can-be-formed-from-different-letters-of-the-Your-answer-is-wrong-with-not-repeating-So-that-they-shouldn-t-start-with-o-neither-w-and-shouldn-t-end-with-w-and-should-be-r-

Question Number 181971 by Acem last updated on 03/Dec/22 $${How}\:{many}\:{words}\:{can}\:{be}\:{formed}\:{from}\:{different} \\ $$$${letters}\:{of}\:{the}\:“{Your}\:{answer}\:{is}\:{wrong}''\:{with}\:{not} \\ $$$${repeating}?\:{So}\:{that}\:{they}\:{shouldn}'{t}\:{start}\:{with}\:'{o}'\: \\ $$$$\:{neither}\:'{w}'\:{and}\:{shouldn}'{t}\:{end}\:{with}\:'{w}',\:{and} \\ $$$$\:{should}\:{be}'{r}'\:\&\:'{s}'\:{adjacents}. \\ $$$$ \\ $$$$\:\cancel{{O}ya}…{n},\:\cancel{{W}en}…{y},\:{Iog}…\cancel{{w}}\:,\:{You}\cancel{{r}w}\cancel{{s}}…{e}\:\::\:{are}\:{invalid} \\ $$$$\:{Enrsow}…{g}\::\:{is}\:{valid} \\…

If-10-different-balls-are-to-be-placed-in-4-boxes-at-random-then-the-probability-that-two-of-these-boxes-contain-exactly-2-and-3-balls-

Question Number 181939 by greougoury555 last updated on 02/Dec/22 $${If}\:\mathrm{10}\:{different}\:{balls}\:{are}\:{to}\:{be}\:{placed} \\ $$$${in}\:\mathrm{4}\:{boxes}\:{at}\:{random}\:,\:{then}\:{the}\:{probability} \\ $$$${that}\:{two}\:{of}\:{these}\:{boxes}\:{contain} \\ $$$${exactly}\:\mathrm{2}\:{and}\:\mathrm{3}\:{balls}\: \\ $$ Answered by Acem last updated on 02/Dec/22…