Menu Close

Category: Permutation and Combination

The-number-of-triangles-that-can-be-formed-by-5-points-in-a-line-and-3-points-on-a-parralel-line-is-

Question Number 180520 by cortano1 last updated on 13/Nov/22 $$\:\:\:\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{triangles}\: \\ $$$$\:\:\:\mathrm{that}\:\mathrm{can}\:\mathrm{be}\:\mathrm{formed}\:\mathrm{by}\:\mathrm{5}\:\mathrm{points}\: \\ $$$$\:\:\:\mathrm{in}\:\mathrm{a}\:\mathrm{line}\:\mathrm{and}\:\mathrm{3}\:\mathrm{points}\:\mathrm{on}\:\mathrm{a}\:\mathrm{parralel}\:\mathrm{line} \\ $$$$\:\:\:\mathrm{is}\:\_\_\_\: \\ $$ Answered by nikif99 last updated on 13/Nov/22…

Find-the-number-of-all-such-7-digit-no-which-satisfy-conditions-1-divisible-by-3-2-repetition-allowed-3-zero-is-not-used-

Question Number 49408 by rahul 19 last updated on 06/Dec/18 $${Find}\:{the}\:{number}\:{of}\:{all}\:{such}\:\mathrm{7}−{digit} \\ $$$${no}.\:{which}\:{satisfy}\:{conditions}: \\ $$$$\left.\mathrm{1}\right)\:{divisible}\:{by}\:\mathrm{3} \\ $$$$\left.\mathrm{2}\right)\:{repetition}\:{allowed} \\ $$$$\left.\mathrm{3}\right)\:{zero}\:{is}\:{not}\:{used}. \\ $$ Commented by mr W…

The-integers-between-1-to-10-4-contain-exactly-one-8-and-one-9-is-I-got-1160-but-one-is-arguing-1154only-kindly-help-me-out-

Question Number 180335 by SLVR last updated on 10/Nov/22 $${The}\:{integers}\:{between}\:\mathrm{1}\:{to}\:\mathrm{10}^{\mathrm{4}} \\ $$$${contain}\:{exactly}\:{one}\:\mathrm{8}\:\:{and}\:{one}\:\mathrm{9} \\ $$$${is}?\:{I}\:{got}\:\mathrm{1160}\:{but}\:{one}\:\:{is}\:{arguing} \\ $$$$\mathrm{1154}{only}..{kindly}\:{help}\:{me}\:{out} \\ $$ Commented by mr W last updated on…

There-are-6-people-going-to-sit-in-a-circle-The-number-of-arrangements-they-sit-if-there-are-2-people-who-always-sit-next-to-each-other-

Question Number 114797 by bemath last updated on 21/Sep/20 $${There}\:{are}\:\mathrm{6}\:{people}\:{going}\:{to}\:{sit}\:{in}\: \\ $$$${a}\:{circle}\:.\:{The}\:{number}\:{of}\:{arrangements} \\ $$$${they}\:{sit}\:{if}\:{there}\:{are}\:\mathrm{2}\:{people}\:{who} \\ $$$${always}\:{sit}\:{next}\:{to}\:{each}\:{other} \\ $$ Answered by mr W last updated on…

Question-49036

Question Number 49036 by Tinkutara last updated on 01/Dec/18 Commented by prakash jain last updated on 02/Dec/18 $$\mathrm{2}^{{n}−\mathrm{1}} \:{gave}\:{at}\:{least}\:\mathrm{1}\:{wrong}\:{answer} \\ $$$$\left({include}\:{student}\:{with}\:\mathrm{2}\:{wrong}\:{answers}\right) \\ $$$$\mathrm{2}^{{n}−\mathrm{2}} \:{gave}\:{at}\:{least}\:\mathrm{2}\:{wrong}\:{amswers}\: \\…