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Category: Permutation and Combination

There-are-many-ways-to-arrange-3-red-balls-and-9-black-balls-in-a-circle-so-that-there-are-a-minimum-of-2-black-balls-between-2-adjacent-red-balls-a-180-8-b-240-7-c-364-6-d-282-4

Question Number 200051 by cortano12 last updated on 13/Nov/23 Therearemanywaystoarrange3redballsand9blackballsinacirclesothatthereareaminimumof2blackballsbetween2adjacentredballs.(a)180×8!(b)240×7!(c)364×6!$$\:\left(\mathrm{d}\right)\:\mathrm{282}×\mathrm{4}!\:\:\:\:\left(\mathrm{e}\right)\:\mathrm{144}×\mathrm{5}!\: \