Question Number 96815 by Ar Brandon last updated on 05/Jun/20 $$\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{3}\:\mathrm{boys}\:\mathrm{and}\:\mathrm{3}\:\mathrm{girls}\:\mathrm{be} \\ $$$$\mathrm{sitted}\:\mathrm{in}\:\mathrm{a}\:\mathrm{line}? \\ $$ Answered by 1549442205 last updated on 05/Jun/20 $$\mathrm{it}\:\mathrm{is}\:\mathrm{too}\:\mathrm{simple}\:\mathrm{6}! \\ $$…
Question Number 96276 by mr W last updated on 31/May/20 Commented by mr W last updated on 31/May/20 $$\mathrm{Repost}\:\mathrm{of}\:\mathrm{an}\:\mathrm{unanswered}\:\mathrm{question} \\ $$$$\left({Q}\mathrm{88876}\right) \\ $$ Commented by…
Question Number 95912 by i jagooll last updated on 28/May/20 $$\begin{pmatrix}{\mathrm{2n}}\\{\mathrm{n}}\end{pmatrix}\:=\:\mathrm{20}\: \\ $$$$\mathrm{find}\:\mathrm{n}? \\ $$ Commented by MJS last updated on 28/May/20 $${n}=\mathrm{3} \\ $$…
Question Number 95888 by i jagooll last updated on 28/May/20 $$\left(\mathrm{1}−\mathrm{2x}\right)^{\mathrm{5}} \left(\mathrm{2}+\mathrm{x}\right)^{\mathrm{6}} =\:\mathrm{a}+\mathrm{bx}+\mathrm{cx}^{\mathrm{2}} +\mathrm{dx}^{\mathrm{3}} +… \\ $$$$\mathrm{find}\::\:\mathrm{a},\mathrm{b},\mathrm{c}\:\mathrm{and}\:\mathrm{d}\: \\ $$ Answered by john santu last updated…
Question Number 95723 by i jagooll last updated on 27/May/20 Commented by bobhans last updated on 27/May/20 the case is ssma with there are 5 women 2 men sitting in 7 chairs with no 2 men sitting side by side Answered by Rio Michael last updated on…
Question Number 95578 by i jagooll last updated on 26/May/20 Commented by i jagooll last updated on 26/May/20 anyone can help? Commented by john santu last updated…
Question Number 160980 by cortano last updated on 10/Dec/21 $$\:\mathrm{How}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{50}\:\mathrm{people} \\ $$$$\:\mathrm{be}\:\mathrm{divided}\:\mathrm{into}\:\mathrm{3}\:\mathrm{groups},\:\mathrm{so} \\ $$$$\:\mathrm{that}\:\mathrm{each}\:\mathrm{group}\:\mathrm{contains}\:\mathrm{members} \\ $$$$\:\mathrm{equal}\:\mathrm{to}\:\mathrm{a}\:\mathrm{prime}\:\mathrm{number}? \\ $$ Answered by Rasheed.Sindhi last updated on 10/Dec/21…
Question Number 95436 by 675480065 last updated on 25/May/20 $$\int\frac{\mathrm{x}^{\mathrm{4}} \mathrm{dx}}{\mathrm{x}^{\mathrm{8}} +\mathrm{x}^{\mathrm{4}} +\mathrm{1}} \\ $$ Answered by Mr.D.N. last updated on 25/May/20 $$\:\:\:\:\mathrm{I}=\:\int\:\frac{\mathrm{x}^{\mathrm{4}} \mathrm{dx}}{\mathrm{x}^{\mathrm{8}} +\mathrm{x}^{\mathrm{4}}…
Question Number 160829 by cortano last updated on 07/Dec/21 Commented by blackmamba last updated on 07/Dec/21 $$\left(\mathrm{6}−\mathrm{1}\right)!×\mathrm{6}×\mathrm{5}×\mathrm{4}\:=\:\mathrm{120}×\mathrm{120}=\mathrm{14400} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 160665 by mr W last updated on 04/Dec/21 $${In}\:{how}\:{many}\:{ways}\:{can}\:{you}\:{divide}\:\mathrm{20} \\ $$$${students}\:{into}\:\mathrm{5}\:{groups}\:{with}\:\mathrm{4}\:{students} \\ $$$${in}\:{each}\:{group}\:{such}\:{that}\:{any}\:{two} \\ $$$${students}\:{don}'{t}\:{meet}\:{each}\:{other}\:{in} \\ $$$${more}\:{than}\:{one}\:{group}. \\ $$ Commented by talminator2856791 last…