Question Number 150554 by pete last updated on 13/Aug/21 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{n}_{\mathrm{C}_{\mathrm{r}} } =\frac{\mathrm{n}\left(\mathrm{n}−\mathrm{1}\right)\left(\mathrm{n}−\mathrm{2}\right)…\left(\mathrm{n}−\mathrm{r}+\mathrm{1}\right)}{\mathrm{r}!} \\ $$ Answered by Ar Brandon last updated on 13/Aug/21 $$\frac{{n}\left({n}−\mathrm{1}\right)\left({n}−\mathrm{2}\right)…\left({n}−{r}+\mathrm{1}\right)}{{r}!} \\ $$$$=\frac{{n}\left({n}−\mathrm{1}\right)…\left({n}−{r}+\mathrm{1}\right)\left({n}−{r}\right)!}{\left({n}−{r}\right)!{r}!}…
Question Number 84998 by jagoll last updated on 18/Mar/20 $$\mathrm{what}\:\mathrm{is}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{x}^{\mathrm{29}} \\ $$$$\mathrm{in}\:\mathrm{expression}\:\left(\mathrm{1}+\mathrm{x}^{\mathrm{5}} +\mathrm{x}^{\mathrm{7}} +\mathrm{x}^{\mathrm{9}} \right)^{\mathrm{29}} \\ $$ Answered by mind is power last updated on…
Question Number 84993 by mr W last updated on 18/Mar/20 $$\mathrm{100}\:{apples}\:{should}\:{be}\:{packed}\:{in}\:{three} \\ $$$${boxes}\:{and}\:{each}\:{box}\:{should}\:{contain} \\ $$$${at}\:{least}\:\mathrm{10}\:{apples}.\:{in}\:{how}\:{many}\:{ways} \\ $$$${can}\:{this}\:{be}\:{done}? \\ $$ Commented by john santu last updated…
Question Number 149955 by jlewis last updated on 08/Aug/21 $$\mathrm{If}\:\mathrm{a}\:\mathrm{group}\:\mathrm{consist}\:\mathrm{of}\:\mathrm{8}\:\mathrm{men}\:\mathrm{and}\:\mathrm{6}\:\mathrm{women}, \\ $$$$\mathrm{in}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{a}\:\mathrm{committee}\:\mathrm{of} \\ $$$$\mathrm{5}\:\mathrm{be}\:\mathrm{selected}\:\mathrm{if}: \\ $$$$\left.\:\:\:\:\:\:\mathrm{i}\right)\:\mathrm{the}\:\mathrm{committee}\:\mathrm{is}\:\mathrm{to}\:\mathrm{consist}\:\mathrm{of}\:\mathrm{3}\:\mathrm{men} \\ $$$$\mathrm{and}\:\mathrm{3}\:\mathrm{women}. \\ $$$$\left.\:\:\:\:\:\:\mathrm{ii}\right)\:\mathrm{there}\:\mathrm{are}\:\mathrm{no}\:\mathrm{restrictions}\:\mathrm{on}\:\mathrm{the}\: \\ $$$$\mathrm{number}\:\mathrm{of}\:\mathrm{men}\:\mathrm{and}\:\mathrm{women}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{committee}. \\…
Question Number 84261 by 698148290 last updated on 10/Mar/20 Answered by Rio Michael last updated on 10/Mar/20 $$\:^{{n}} {C}_{{r}} =\:\frac{{n}!}{\left({n}−{r}\right)!{r}!} \\ $$$$\:^{{n}} {C}_{\mathrm{12}} \:=\:^{{n}} {C}_{\mathrm{8}}…
Question Number 84125 by redmiiuser last updated on 09/Mar/20 $${is}\:{it}\:{possible}\:{to}\:{find}\: \\ $$$${the}\:{no}.\:{of}\:{positive}\: \\ $$$${integral}\:{solutions} \\ $$$${of}\:{x}+{y}+\mathrm{2}{z}+\mathrm{3}{c}=\mathrm{7} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 149595 by SLVR last updated on 06/Aug/21 Commented by SLVR last updated on 06/Aug/21 $${sir}\:{solution}\:{please}.. \\ $$ Answered by mr W last updated…
Question Number 149437 by SLVR last updated on 05/Aug/21 Commented by SLVR last updated on 05/Aug/21 $${kindly}\:{solution}\:{please} \\ $$ Answered by Olaf_Thorendsen last updated on…
Question Number 149439 by SLVR last updated on 05/Aug/21 Commented by SLVR last updated on 05/Aug/21 $${solution}\:{please} \\ $$ Answered by mr W last updated…
Question Number 17770 by chux last updated on 10/Jul/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{the} \\ $$$$\mathrm{digits}\:\mathrm{0},\mathrm{1},\mathrm{2}\:\mathrm{and}\:\mathrm{3}\:\mathrm{can}\:\mathrm{be}\:\mathrm{permuted} \\ $$$$\mathrm{to}\:\mathrm{give}\:\mathrm{rise}\:\mathrm{to}\:\mathrm{a}\:\mathrm{number}\:\mathrm{greater} \\ $$$$\mathrm{than}\:\mathrm{2000}. \\ $$ Answered by alex041103 last updated on 10/Jul/17…