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Category: Permutation and Combination

If-6-x-4-x-then-x-

Question Number 145104 by imjagoll last updated on 02/Jul/21 $$\:\mathrm{If}\:\frac{!\mathrm{6}}{\mathrm{x}}\:−!\mathrm{4}\:=\:!\mathrm{x}\:\mathrm{then}\:\mathrm{x}\:=? \\ $$ Answered by liberty last updated on 02/Jul/21 $$\:\Rightarrow\:\mathrm{265}−\mathrm{9}{x}\:=\:{x}.\left(!{x}\right) \\ $$$${test}\:{x}=\mathrm{5}\: \\ $$$$\Rightarrow\mathrm{265}−\mathrm{45}\:=\:\mathrm{220}\:\wedge\:\mathrm{5}.\left(!\mathrm{5}\right)=\mathrm{5}×\mathrm{44}=\mathrm{220} \\…

how-do-16-people-play-3-matches-in-teams-of-4-but-must-only-be-in-the-same-team-once-

Question Number 79479 by jagoll last updated on 25/Jan/20 $$\mathrm{how}\:\mathrm{do}\:\mathrm{16}\:\mathrm{people}\:\mathrm{play}\:\mathrm{3}\:\mathrm{matches} \\ $$$$\mathrm{in}\:\mathrm{teams}\:\mathrm{of}\:\mathrm{4}\:\mathrm{but}\:\mathrm{must}\:\mathrm{only}\:\mathrm{be} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{same}\:\mathrm{team}\:\mathrm{once}\:?\: \\ $$ Commented by mr W last updated on 25/Jan/20 $${i}\:{don}'{t}\:{understand}\:{the}\:{question}…

what-the-minimum-value-of-f-x-x-2-2x-5-x-2-14x-65-

Question Number 79472 by jagoll last updated on 25/Jan/20 $$\mathrm{what}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}+\mathrm{5}}\:+\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{14x}+\mathrm{65}} \\ $$ Commented by john santu last updated on 25/Jan/20 $${yes}\:{sir}.\:{haha}\:{this}\:{method}\:{not}\:…

Question-78799

Question Number 78799 by Pratah last updated on 20/Jan/20 Commented by mathmax by abdo last updated on 20/Jan/20 $${convergence}?\:\:\:{let}\:{f}\left({x}\right)=\frac{{ln}\left({x}\right)}{{x}^{\frac{\mathrm{5}}{\mathrm{4}}} }\:\:\:{with}\:{x}\geqslant\mathrm{2}\:\:{we}\:{have} \\ $$$${f}^{'} \left({x}\right)=\frac{\frac{\mathrm{1}}{{x}}{x}^{\frac{\mathrm{5}}{\mathrm{4}}} −\frac{\mathrm{5}}{\mathrm{4}}{x}^{\frac{\mathrm{5}}{\mathrm{4}}−\mathrm{1}} {lnx}}{{x}^{\frac{\mathrm{5}}{\mathrm{2}}}…

determinant-old-plate-EEU-874-new-plate-1BXK-267-Old-California-license-plate-consisted-of-a-sequence-of-three-letters-followed-by-three-digits-see-figure-above-Assuming-that-any-s

Question Number 131464 by bemath last updated on 05/Feb/21 $$\:\begin{array}{|c|c|}{{old}\:{plate}\::\:{EEU}\:\mathrm{874}}\\{{new}\:{plate}\::\:\mathrm{1}{BXK}\:\mathrm{267}}\\\hline\end{array} \\ $$$${Old}\:{California}\:{license}\:{plate}\: \\ $$$${consisted}\:{of}\:{a}\:{sequence}\:{of} \\ $$$${three}\:{letters}\:{followed}\:{by}\:{three} \\ $$$${digits}\:\left({see}\:{figure}\:{above}\right). \\ $$$${Assuming}\:{that}\:{any}\:{sequence} \\ $$$${of}\:{letters}\:{and}\:{digits}\:{was}\:{allowed} \\ $$$$\left({though}\:{actually}\:{some}\:{combinations}\right. \\…

Eight-eligible-bachelor-and-seven-beautiful-models-happen-randomly-to-have-purchased-single-seats-in-the-same-15-seats-row-of-theather-On-the-average-how-many-pairs-of-adjacent-seats-are-ticketed-

Question Number 131459 by bramlexs22 last updated on 05/Feb/21 $${Eight}\:{eligible}\:{bachelor}\:{and}\:{seven}\:{beautiful} \\ $$$${models}\:{happen}\:{randomly}\:{to}\:{have}\: \\ $$$${purchased}\:{single}\:{seats}\:{in}\:{the}\:{same}\:\mathrm{15}−{seats} \\ $$$${row}\:{of}\:{theather}.\:{On}\:{the}\:{average}\:,\:{how}\:{many} \\ $$$${pairs}\:{of}\:{adjacent}\:{seats}\:{are}\:{ticketed} \\ $$$${for}\:{marriageable}\:{couples}\:? \\ $$ Answered by bemath…

If-and-are-the-coefficient-of-x-8-and-x-24-respectively-in-the-expansion-of-x-4-2-1-x-4-10-in-powers-of-x-then-is-equal-to-

Question Number 131248 by bramlexs22 last updated on 03/Feb/21 $${If}\:\alpha\:{and}\:\beta\:{are}\:{the}\:{coefficient}\: \\ $$$${of}\:{x}^{\mathrm{8}} \:{and}\:{x}^{−\mathrm{24}} \:{respectively}\: \\ $$$${in}\:{the}\:{expansion}\:{of}\:\left[\:{x}^{\mathrm{4}} +\mathrm{2}+\frac{\mathrm{1}}{{x}^{\mathrm{4}} }\:\right]^{\mathrm{10}} \\ $$$${in}\:{powers}\:{of}\:{x}\:{then}\:\frac{\alpha}{\beta}\:{is}\:{equal}\:{to}\: \\ $$ Answered by EDWIN88…