Question Number 11425 by tawa last updated on 25/Mar/17 Answered by mrW1 last updated on 25/Mar/17 $$\left(\mathrm{1}\right)\:\mathrm{12}{C}\mathrm{5}=\mathrm{792} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{9}{C}\mathrm{5}+\mathrm{3}×\left(\mathrm{9}{C}\mathrm{4}\right)+\mathrm{3}×\left(\mathrm{9}{C}\mathrm{3}\right)=\mathrm{126}+\mathrm{3}×\mathrm{126}+\mathrm{3}×\mathrm{84}=\mathrm{756} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{10}{C}\mathrm{5}+\mathrm{10}{C}\mathrm{3}=\mathrm{252}+\mathrm{120}=\mathrm{372} \\ $$ Commented by…
Question Number 11384 by tawa last updated on 22/Mar/17 $$\mathrm{Out}\:\mathrm{of}\:\mathrm{5}\:\mathrm{accountants}\:\mathrm{and}\:\mathrm{7}\:\mathrm{bankers},\:\mathrm{a}\:\mathrm{committee}\:\mathrm{consisting}\:\mathrm{of}\: \\ $$$$\mathrm{2}\:\mathrm{accountants}\:\mathrm{and}\:\mathrm{3}\:\mathrm{bankers}\:\mathrm{is}\:\mathrm{to}\:\mathrm{be}\:\mathrm{formed}.\:\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{this} \\ $$$$\mathrm{be}\:\mathrm{done}\:\mathrm{if} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{Any}\:\mathrm{acountant}\:\mathrm{and}\:\mathrm{any}\:\mathrm{bankers}\:\mathrm{must}\:\mathrm{be}\:\mathrm{included} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{One}\:\mathrm{particular}\:\mathrm{banker}\:\mathrm{must}\:\mathrm{be}\:\mathrm{included} \\ $$$$\left(\mathrm{c}\right)\:\mathrm{2}\:\mathrm{accountant}\:\mathrm{cannot}\:\mathrm{be}\:\mathrm{in}\:\mathrm{the}\:\mathrm{committee} \\ $$ Answered by sandy_suhendra…
Question Number 11382 by tawa last updated on 22/Mar/17 $$\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{24}\:\mathrm{different}\:\mathrm{articles}\:\mathrm{be}\:\mathrm{divided}\:\mathrm{into}\:\mathrm{groups}\:\mathrm{of} \\ $$$$\mathrm{12},\:\mathrm{8}\:\mathrm{and}\:\mathrm{4}\:\mathrm{articles}\:\mathrm{respectively} \\ $$ Commented by sandy_suhendra last updated on 23/Mar/17 $$\mathrm{24C12}\:×\:\mathrm{12C8}\:×\:\mathrm{4C4} \\ $$ Commented…
Question Number 142305 by anonymo last updated on 29/May/21 Answered by Olaf_Thorendsen last updated on 01/Jun/21 $$\left(\mathrm{1}+{i}\right)^{\mathrm{80}} \:=\:\underset{{p}=\mathrm{0}} {\overset{\mathrm{80}} {\sum}}\mathrm{C}_{{p}} ^{\mathrm{80}} {i}^{{p}} \\ $$$$\left(\mathrm{1}+{i}\right)^{\mathrm{80}} \:=\:\underset{{k}=\mathrm{0}}…
Question Number 141777 by SLVR last updated on 23/May/21 $${A}\:{pack}\:{of}\:\mathrm{52}\:{cards}\:{distributed}\:{equally}\:{to} \\ $$$$\mathrm{4}\:{people}\:{so}\:{as}\:\mathrm{4}\:{cards}\:{each}\:{from}\: \\ $$$${same}\:{suit}\left(\:{of}\:{any}\:\mathrm{3}\:{suit}=\mathrm{4}×\mathrm{3}=\mathrm{12}\right) \\ $$$${and}\:{last}\:{card}\:{from}\:\mathrm{4}{th}\:{remaining} \\ $$$${suit}\:.\:{Number}\:{of}\:{such} \\ $$$${distributions}\:{is}? \\ $$$$ \\ $$$$ \\…
Question Number 141435 by physicstutes last updated on 18/May/21 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{arraangment}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{letters} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{word}\:\mathrm{SYLLABUSES}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{each}\:\mathrm{word}\:\mathrm{contains}\:\mathrm{the}\:\mathrm{word}\:\mathrm{BUS}. \\ $$ Answered by mr W last updated on 19/May/21 $$\mathrm{SYLLABUSES}…
Question Number 10029 by Tawakalitu ayo mi last updated on 21/Jan/17 $$\mathrm{The}\:\mathrm{first}\:\mathrm{3}\:\mathrm{runners}\:\mathrm{in}\:\mathrm{100m}\:\mathrm{race}\:\mathrm{were}\:\mathrm{clocked} \\ $$$$\mathrm{9}.\mathrm{5s},\:\mathrm{10s},\:\mathrm{10}.\mathrm{5s}\:\mathrm{respectively}.\:\mathrm{How}\:\mathrm{far}\:\mathrm{is}\:\mathrm{the}\: \\ $$$$\mathrm{first}\:\mathrm{from}\:\mathrm{the}\:\mathrm{third}\:\mathrm{runners}\:\mathrm{when}\:\mathrm{the}\:\mathrm{first}\: \\ $$$$\mathrm{runner}\:\mathrm{reached}\:\mathrm{the}\:\mathrm{finished}\:\mathrm{line}. \\ $$ Commented by mrW1 last updated…
Question Number 9747 by tawakalitu last updated on 30/Dec/16 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{the}\:\mathrm{term}\:\mathrm{independent} \\ $$$$\mathrm{of}\:\mathrm{x}\:\mathrm{in}\:\mathrm{the}\:\mathrm{expansion}\:\mathrm{of} \\ $$$$\left(\frac{\mathrm{x}\:+\:\mathrm{1}}{\mathrm{x}^{\mathrm{2}/\mathrm{3}} \:−\:\mathrm{x}^{\mathrm{1}/\mathrm{3}} \:+\:\mathrm{1}}\:−\:\frac{\mathrm{x}\:−\:\mathrm{1}}{\mathrm{x}\:−\:\mathrm{x}^{\mathrm{1}/\mathrm{2}} }\right)^{\mathrm{10}} \\ $$ Answered by sandy_suhendra last updated on…
Question Number 75180 by Rio Michael last updated on 08/Dec/19 $${There}\:{are}\:\mathrm{6}\:{girls}\:{and}\:{four}\:{boys}\:{in}\:{a}\:{class}. \\ $$$$\mathrm{3}\:{students}\:{are}\:{choosen}\:{at}\:{random}\:{so}\:{as}\:{to}\:{be} \\ $$$${awarded}\:{a}\:{scholaship}.{In}\:{how}\:{many}\:{ways}\:{can} \\ $$$${this}\:{be}\:{done}\:{if}\:{atlease}\:\mathrm{1}\:{boy}\:{and}\:\mathrm{1}\:{girl}\:{must} \\ $$$${in}\:{the}\:{selection} \\ $$$$ \\ $$ Commented by…
Question Number 75122 by chess1 last updated on 07/Dec/19 Commented by JDamian last updated on 07/Dec/19 $${Open}\:{this}\:{app},\:{tap}\:{on}\:\boldsymbol{\mathrm{Study}}\:>\:\boldsymbol{\mathrm{Sequence}} \\ $$$$\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{Series}}\:{and}\:{look}\:{for}\:\boldsymbol{\mathrm{Sum}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{n}}\:\boldsymbol{\mathrm{terms}} \\ $$$$\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{G}}.\boldsymbol{\mathrm{P}}. \\ $$ Commented by…