Question Number 62014 by Tawa1 last updated on 14/Jun/19 Answered by MJS last updated on 14/Jun/19 $$\mathrm{1} \\ $$$$\mathrm{5}×\mathrm{6}=\mathrm{30} \\ $$$$\mathrm{2} \\ $$$$\mathrm{4}×\mathrm{3}×\mathrm{2}=\mathrm{24} \\ $$…
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Question Number 61860 by Tawa1 last updated on 10/Jun/19 $$\mathrm{simplify}:\:\:\:\:\overset{\mathrm{n}\:+\:\mathrm{1}} {\:}\mathrm{C}_{\mathrm{r}} \:−\:\overset{\mathrm{n}\:−\:\mathrm{1}} {\:}\mathrm{C}_{\mathrm{r}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 61377 by Tawa1 last updated on 01/Jun/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{multinomial}\:\mathrm{coefficient}:\:\:\:\:\:\:\begin{pmatrix}{\:\:\:\:\:\:\:\mathrm{9}}\\{\mathrm{3},\:\mathrm{5},\:\mathrm{1},\:\mathrm{0}}\end{pmatrix} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 192256 by Red1ight last updated on 13/May/23 $$\mathrm{given}\:{f}\left({x}\right)={cx}\left({x}−\mathrm{20}\right)\:\mathrm{and}\:{A}=\left(\mathrm{2},\mathrm{5}\right) \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{nearst}\:\mathrm{point}\:\mathrm{to}\:{A}\:\mathrm{on}\:\mathrm{the}\:\mathrm{graph} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 191934 by Rupesh123 last updated on 04/May/23 Answered by mehdee42 last updated on 04/May/23 $${C}_{\:\mathrm{6}} ^{\:\mathrm{3}} \:×\mathrm{3}!×\mathrm{5}!=\mathrm{14400} \\ $$ Commented by mehdee42 last…
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Question Number 125548 by Don08q last updated on 12/Dec/20 $$\mathrm{How}\:\mathrm{many}\:\mathrm{four}−\mathrm{digit}\:\mathrm{numbers}\: \\ $$$$\mathrm{between}\:\mathrm{2000}\:\mathrm{and}\:\mathrm{4000}\:\mathrm{can}\:\mathrm{be}\:\mathrm{formed} \\ $$$$\mathrm{from}\:\mathrm{the}\:\mathrm{numbers}\:\mathrm{0},\:\mathrm{1},\:\mathrm{2},\:\mathrm{3},\:\mathrm{4}\:\mathrm{and}\:\mathrm{5}\: \\ $$$$\mathrm{if}\:\mathrm{repitition}\:\mathrm{is}\:\mathrm{allowed}? \\ $$ Commented by liberty last updated on 13/Dec/20…
Question Number 125460 by john_santu last updated on 11/Dec/20 $$\:{In}\:{a}\:{room}\:{containing}\:{N}\:{people} \\ $$$${N}>\mathrm{3},\:{at}\:{least}\:{one}\:{person}\:{has}\:{not} \\ $$$${shaken}\:{hands}\:{with}\:{everyone} \\ $$$${else}\:{in}\:{the}\:{room}.\:{What}\:{is}\:{the}\: \\ $$$${maximum}\:{number}\:{of}\:{people}\: \\ $$$${in}\:{the}\:{room}\:{that}\:{could}\:{have}\: \\ $$$${shaken}\:{hands}\:{with}\:{everyone}\: \\ $$$${else}?\: \\…
Question Number 125208 by liberty last updated on 09/Dec/20 $${There}\:{are}\:\mathrm{12}\:{students}\:{in}\:{a}\:{party}.\:{Five}\:{of} \\ $$$${them}\:{are}\:{girls}.\:{In}\:{how}\:{many}\:{ways}\:{can}\: \\ $$$${these}\:\mathrm{12}\:{students}\:{be}\:{arranged}\:{in}\:{a}\:{row}\:{if}\: \\ $$$$\left({i}\right)\:{there}\:{are}\:{no}\:{restrictions}? \\ $$$$\left({ii}\right)\:{the}\:\mathrm{5}\:{girls}\:{must}\:{be}\:{together}\:\left({forming}\:{a}\:{block}\right)? \\ $$$$\left({iii}\right)\:{no}\:\mathrm{2}\:{girls}\:{are}\:{adjacent}\: \\ $$$$\left({iv}\right)\:{between}\:{two}\:{particular}\:{boys}\:{A}\:{and}\:{B}\: \\ $$$$\:,\:{there}\:{no}\:{boys}\:{but}\:{exactly}\:\mathrm{3}\:{girls}? \\…