Question Number 57864 by mr W last updated on 13/Apr/19 Answered by mr W last updated on 14/Apr/19 $${to}\:{arrange}\:{n}\:{numbers}\:{there}\:{are}\:{n}!\:{ways}. \\ $$$${such}\:{that}\:{k}\:{numbers}\:{are}\:{together}\:{there} \\ $$$${are}\:\left({n}−{k}+\mathrm{1}\right)!{k}!\:{ways}. \\ $$$$\Rightarrow{p}=\frac{\left({n}−{k}+\mathrm{1}\right)!{k}!}{{n}!}=\frac{{n}−{k}+\mathrm{1}}{\frac{{n}!}{\left({n}−{k}\right)!{k}!}}=\frac{{n}−{k}+\mathrm{1}}{\:^{{n}}…
Question Number 57865 by mr W last updated on 13/Apr/19 Answered by MJS last updated on 13/Apr/19 $${n}=\mathrm{2}\:{p}=\mathrm{0} \\ $$$${n}=\mathrm{3}\:{p}=\mathrm{1}/\mathrm{3} \\ $$$${n}=\mathrm{4}\:{p}=\mathrm{3}/\mathrm{6}\:\left(=\mathrm{1}/\mathrm{2}\right) \\ $$$${n}=\mathrm{5}\:{p}=\mathrm{6}/\mathrm{10}\:\left(=\mathrm{3}/\mathrm{5}\right) \\…
Question Number 57863 by mr W last updated on 13/Apr/19 Commented by tanmay.chaudhury50@gmail.com last updated on 13/Apr/19 Commented by tanmay.chaudhury50@gmail.com last updated on 13/Apr/19 Answered…
Question Number 123100 by pticantor last updated on 23/Nov/20 $$\boldsymbol{{let}}\:\boldsymbol{{P}}_{\boldsymbol{{k}}} =\frac{\boldsymbol{{C}}}{\boldsymbol{{k}}×\mathrm{4}^{\boldsymbol{{k}}\:} } \\ $$$$\left.\mathrm{1}\right)\:\boldsymbol{{determine}}\:\boldsymbol{{C}}\:\boldsymbol{{so}}\:\boldsymbol{{that}}\:\boldsymbol{{the}}\:\boldsymbol{{family}} \\ $$$$\left(\boldsymbol{{p}}_{\boldsymbol{{k}}} ,\boldsymbol{{k}}\in\mathbb{N}^{\ast} \right)\:\boldsymbol{{define}}\:\boldsymbol{{a}}\:\boldsymbol{{measure}}\:\boldsymbol{{of}}\:\boldsymbol{{probability}} \\ $$$$\left.\mathrm{2}\right)\:\boldsymbol{{we}}\:\boldsymbol{{draw}}\:\boldsymbol{{a}}\:\boldsymbol{{number}}\:\boldsymbol{{in}}\:\mathbb{N}^{\ast} \:\boldsymbol{{according}}\:\boldsymbol{{to}}\:\boldsymbol{{the}}\: \\ $$$$\boldsymbol{{probability}}\:\boldsymbol{{P}}\:\boldsymbol{{determined}}\:\boldsymbol{{the}}\:\boldsymbol{{probability}}\:\boldsymbol{{that}}\:\boldsymbol{{the}}\:\boldsymbol{{number}} \\ $$$$\boldsymbol{{drawn}}\:\boldsymbol{{is}}\:\boldsymbol{{a}}\:\boldsymbol{{multiple}}\:\boldsymbol{{of}}\:\mathrm{4}…
Question Number 122973 by bemath last updated on 21/Nov/20 Answered by mr W last updated on 21/Nov/20 $$\mathrm{12}. \\ $$$$\frac{\mathrm{10}+{C}_{\mathrm{2}} ^{\mathrm{3}} ×\mathrm{10}}{\mathrm{10}^{\mathrm{3}} }=\frac{\mathrm{1}}{\mathrm{25}}=\mathrm{4\%} \\ $$…
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Question Number 57071 by necx1 last updated on 29/Mar/19 Commented by necx1 last updated on 29/Mar/19 $${please}\:{help} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 56951 by pete last updated on 27/Mar/19 $$\mathrm{The}\:\mathrm{deviations}\:\mathrm{from}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{of}\:\mathrm{a} \\ $$$$\mathrm{set}\:\mathrm{of}\:\mathrm{numbers}\:\mathrm{are}\:\left(\mathrm{x}+\mathrm{2}\right),\:\left(\mathrm{2x}−\mathrm{11}\right), \\ $$$$−\mathrm{9},\:\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} ,\:\left(\mathrm{x}−\mathrm{4}\right)^{\mathrm{2}} ,\:\left(\mathrm{1}−\mathrm{3x}\right).\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:\mathrm{where}\:\mathrm{x}>\mathrm{0}. \\ $$ Commented by pete last updated…