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Question Number 187706 by Mingma last updated on 20/Feb/23 Answered by aleks041103 last updated on 20/Feb/23 $${since}\:{we}\:{can}\:{see}\:{a}\:{positive}\:{correlation} \\ $$$${then}\:{the}\:{two}\:{quantities}\:{tend}\:{to}\:{increase}\:{or} \\ $$$${decrease}\:{together}\left({simultaniously}\right) \\ $$$${i}.{e}.\:{the}\:{correct}\:{answer}\:{is}\:{no}.\mathrm{1} \\ $$…
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Question Number 56045 by mr W last updated on 09/Mar/19 Commented by mr W last updated on 09/Mar/19 $${An}\:{ellipse}\:{with}\:{semi}\:{axes}\:{a}\:{and}\:{b}\:{has} \\ $$$${a}\:{distance}\:{e}\:\left({e}>{a}\right)\:{from}\:{its}\:{center}\:{C}\:{to} \\ $$$${point}\:{O}.\:{Point}\:{A}\:{is}\:{choosen}\:{randomly} \\ $$$${inside}\:{the}\:{ellipse}.\:{Let}\:{d}\:{be}\:{the}\:{distance}…
Question Number 56011 by mr W last updated on 08/Mar/19 Commented by mr W last updated on 08/Mar/19 $${Point}\:{A}\:{is}\:{choosen}\:{at}\:{random}\:{in}\:{a} \\ $$$${square}\:{with}\:{side}\:{length}\:{a},\:{see}\:{figure}. \\ $$$${What}\:{is}\:{its}\:{average}\:{distance}\:{to}\:{the} \\ $$$${origin}?…
Question Number 187073 by Humble last updated on 13/Feb/23 $${suppose}\:{that}\:{a}\:{sample}\:{of}\:{size} \\ $$$${n}=\mathrm{8}\:{is}\:{drawn}\:{from}\:{a}\:{population}\:{with}\:{PDF}:\: \\ $$$$\left\{{f}\left({x}\right)=\frac{{x}^{\mathrm{2}} }{\mathrm{9}},\:\mathrm{0}\:<\:{x}\:<\:\mathrm{3}\right\} \\ $$$${find} \\ $$$$\left(\mathrm{1}\right)\:\:\:{p}\left(\mathrm{1}\:<\:{x}\:<\:\mathrm{2}\right) \\ $$$$\left(\mathrm{2}\right)\:\:{PDF}\:{and}\:{CDF}\:{of}\:{the}\:{fourth}\:{smallest}\:{O}.{S} \\ $$ Terms of…
Question Number 121472 by ATHISHHUZAIN last updated on 08/Nov/20 $$\:\boldsymbol{{Find}}\:\boldsymbol{{the}}\:\boldsymbol{{sum}}\:\boldsymbol{{to}}\:\boldsymbol{{n}}\:\boldsymbol{{terms}}\:\boldsymbol{{of}}\:\boldsymbol{{the}} \\ $$$$\:\:\boldsymbol{{series}}\:\mathrm{3}×\mathrm{8}+\mathrm{6}×\mathrm{11}+\mathrm{9}×\mathrm{14}+……. \\ $$$$\:\:\boldsymbol{{A}}{nswer}: \\ $$$$\:\:\:\:\boldsymbol{{n}}^{\boldsymbol{{th}}} \:\boldsymbol{{term}}\:\boldsymbol{{t}}_{\boldsymbol{{n}}} \:=\:\mathrm{3}\boldsymbol{{n}}\left(\mathrm{3}\boldsymbol{{n}}+\mathrm{5}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{9}\boldsymbol{{n}}^{\mathrm{2}} +\mathrm{15}\boldsymbol{{n}} \\ $$$$\:\:\:\:\:\: \\ $$…
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Question Number 55736 by byaw last updated on 03/Mar/19 Answered by tanmay.chaudhury50@gmail.com last updated on 03/Mar/19 $${p}\left({under}\:{wieight}\right)=\frac{\mathrm{1}}{\mathrm{20}}\rightarrow{p}\left({u}.{w}\right)=\frac{\mathrm{1}}{\mathrm{20}}\rightarrow\boldsymbol{{a}} \\ $$$${p}\left({actual}\:{weight}\right)=\frac{\mathrm{19}}{\mathrm{20}}\rightarrow{p}\left({a}.{w}\right)=\frac{\mathrm{19}}{\mathrm{20}}\rightarrow{b} \\ $$$${a}+{b}=\mathrm{1} \\ $$$$\left({b}+{a}\right)^{\mathrm{72}} ={b}^{\mathrm{72}} +\mathrm{72}{c}_{\mathrm{1}}…
Question Number 55737 by byaw last updated on 03/Mar/19 Commented by mr W last updated on 03/Mar/19 $$\left({i}\right) \\ $$$${p}=\left(\mathrm{0}.\mathrm{3}\right)^{\mathrm{4}} =\mathrm{0}.\mathrm{0081} \\ $$$$\left({ii}\right) \\ $$$${p}=\left(\mathrm{0}.\mathrm{7}\right)^{\mathrm{4}}…