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Question Number 186547 by ali009 last updated on 05/Feb/23 $${p}\left({a}\:{or}\:{b}\right)=\mathrm{0}.\mathrm{7}\:{and}\:{p}\left({a}\right)=\mathrm{0}.\mathrm{4} \\ $$$${find}\:{p}\left({b}\right)\:{if}\:{a}\:{and}\:{b}\:{are}\:{independent} \\ $$ Answered by som(math1967) last updated on 06/Feb/23 $${p}\left({aorb}\right)={p}\left({a}\right)+{p}\left({b}\right)−{p}\left({a}\:\:{and}\:{b}\right) \\ $$$$.\mathrm{7}=.\mathrm{4}+{p}\left({b}\right)−.\mathrm{4}{p}\left({b}\right) \\…
Question Number 55344 by Necxx last updated on 21/Feb/19 $${A}\:{whatsapp}\:{group}\:{contains}\:\mathrm{7}\:{women} \\ $$$${and}\:\mathrm{3}\:{men}.{If}\:{they}\:{are}\:{leaving} \\ $$$${the}\:{group}\:{one}\:{at}\:{a}\:{time}\:{from}\:{the} \\ $$$${group}\:{what}\:{is}\:{the}\:{probability}\:{of}\:{a} \\ $$$${woman}\:{leaving}\:{then}\:{a}\:{man}\:{leaving} \\ $$$${and}\:{so}\:{on}\:{alternately}\:{until}\:{only}\:{a} \\ $$$${woman}\:{is}\:{remaining}? \\ $$$$ \\…
Question Number 186331 by Red1ight last updated on 03/Feb/23 $$ \\ $$How many possibilities are there for picking random numbers that ranges from 1-3 that…
Question Number 54513 by byaw last updated on 05/Feb/19 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{interquartile}\:\mathrm{range}: \\ $$$$\mathrm{20},\mathrm{26},\mathrm{27},\mathrm{30},\mathrm{34},\mathrm{41},\mathrm{41},\mathrm{64},\mathrm{65},\mathrm{65},\mathrm{72},\mathrm{85} \\ $$ Answered by MJS last updated on 05/Feb/19 $$\mathrm{min}=\mathrm{20} \\ $$$$\mathrm{q1}=\frac{\mathrm{27}+\mathrm{30}}{\mathrm{2}}=\mathrm{28}.\mathrm{5} \\…
Question Number 119893 by peter frank last updated on 27/Oct/20 Answered by Ar Brandon last updated on 27/Oct/20 $$\mathrm{P}\left(\mathrm{both}\:\mathrm{black}\right)=\mathrm{P}\left(\mathrm{1}^{\mathrm{st}} \:\mathrm{black}\cap\mathrm{2}^{\mathrm{nd}} \:\mathrm{black}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{26}}{\mathrm{52}}×\frac{\mathrm{25}}{\mathrm{51}} \\ $$$$\mathrm{P}\left(\mathrm{both}\:\mathrm{queen}\right)=\mathrm{P}\left(\mathrm{1}^{\mathrm{st}}…
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Question Number 119646 by bemath last updated on 26/Oct/20 Commented by mr W last updated on 27/Oct/20 $$\mathrm{100\%} \\ $$ Terms of Service Privacy Policy…
Question Number 119527 by joki last updated on 25/Oct/20 Commented by benjo_mathlover last updated on 25/Oct/20 $$\left({a}\right){P}\left({male}/{secondary}\:{education}\right)\:=\:\frac{{P}\left({M}\cap{E}\right)}{{P}\left({E}\right)} \\ $$$$\:=\:\frac{\mathrm{28}}{\mathrm{28}+\mathrm{50}}\:=\:\frac{\mathrm{28}}{\mathrm{78}}\:=\:\frac{\mathrm{14}}{\mathrm{39}}\:. \\ $$ Commented by joki last…
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