Question Number 111826 by Aina Samuel Temidayo last updated on 05/Sep/20 $$\mathrm{There}\:\mathrm{are}\:\mathrm{two}\:\mathrm{cards};\:\mathrm{one}\:\mathrm{is}\:\mathrm{yellow}\:\mathrm{on} \\ $$$$\mathrm{both}\:\mathrm{sides}\:\mathrm{and}\:\mathrm{the}\:\mathrm{other}\:\mathrm{one}\:\mathrm{is}\:\mathrm{yellow} \\ $$$$\mathrm{in}\:\mathrm{one}\:\mathrm{side}\:\mathrm{and}\:\mathrm{red}\:\mathrm{on}\:\mathrm{the}\:\mathrm{other}.\:\mathrm{The} \\ $$$$\mathrm{cards}\:\mathrm{have}\:\mathrm{the}\:\mathrm{same}\:\mathrm{probability}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$$$\mathrm{of}\:\mathrm{being}\:\mathrm{chosen},\:\mathrm{and}\:\mathrm{one}\:\mathrm{is}\:\mathrm{chosen}\:\mathrm{and} \\ $$$$\mathrm{placed}\:\mathrm{on}\:\mathrm{the}\:\mathrm{table}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{upper}\:\mathrm{side} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{card}\:\mathrm{on}\:\mathrm{the}\:\mathrm{table}\:\mathrm{is}\:\mathrm{yellow}, \\…
Question Number 111788 by 675480065 last updated on 04/Sep/20 Answered by bemath last updated on 05/Sep/20 $$\:{a}\:=\:\mathrm{3}\:,\:{b}\:=\:\mathrm{4}\:;\:{c}\:=\:\mathrm{4} \\ $$$$\Leftrightarrow\:\mathrm{3}!\:\mathrm{3}!\:=\:\left(\mathrm{6}\right)^{\mathrm{2}} \:=\:\mathrm{36} \\ $$$$\Leftrightarrow\:\mathrm{3}!+\mathrm{3}!+\mathrm{4}!\:=\:\mathrm{6}+\mathrm{6}+\mathrm{24}\:=\:\mathrm{36}\: \\ $$ Terms…
Question Number 111690 by bemath last updated on 04/Sep/20 Answered by john santu last updated on 04/Sep/20 $$\:{let}\:\begin{cases}{{white}\:{ball}\:=\:{x}}\\{{red}\:{ball}=\mathrm{2}{x}}\\{{black}\:{ball}=\mathrm{30}−\mathrm{3}{x}}\end{cases} \\ $$$${so}\:{the}\:{number}\:{of}\:{way}\:{to}\:{take}\: \\ $$$$\mathrm{2}\:{white}\:{balls}\:{and}\:\mathrm{1}\:{black}\:{ball}\:{is} \\ $$$${C}_{\mathrm{2}} ^{\:{x}}…
Question Number 111533 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{The}\:\mathrm{mean},\mathrm{median}\:\mathrm{and}\:\mathrm{mode}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{data}\:\mathrm{values}\:\mathrm{90},\mathrm{54},\mathrm{x},\mathrm{123},\mathrm{62},\mathrm{78},\mathrm{58},\mathrm{81} \\ $$$$\mathrm{are}\:\mathrm{all}\:\mathrm{equal}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}? \\ $$ Commented by Rasheed.Sindhi last updated on 04/Sep/20…
Question Number 45920 by byaw last updated on 18/Oct/18 Answered by math1967 last updated on 19/Oct/18 $$\left.{i}\right)\:{All}\:\mathrm{4}\:{balls}\:{are}\:{black}=\:\frac{\:^{\mathrm{8}} {c}_{\mathrm{2}} \:}{\:^{\mathrm{20}} {c}_{\mathrm{2}} }\cap\frac{\:^{\mathrm{15}} {c}_{\mathrm{2}} }{\:^{\mathrm{25}} {c}_{\mathrm{2}} }\:…
Question Number 45827 by byaw last updated on 17/Oct/18 Commented by MJS last updated on 17/Oct/18 $$\mathrm{the}\:\mathrm{source}\:\mathrm{of}\:\mathrm{these}\:\mathrm{questions}\:\mathrm{is}\:\mathrm{at}\:\mathrm{least}\:\mathrm{not} \\ $$$$\mathrm{accurate},\:\mathrm{always}\:\mathrm{something}\:\mathrm{missing}\:\mathrm{or}\:\mathrm{other} \\ $$$$\mathrm{mistakes} \\ $$ Answered by…
Question Number 111276 by Aina Samuel Temidayo last updated on 03/Sep/20 $$\mathrm{A}\:\mathrm{coin}\:\mathrm{that}\:\mathrm{comes}\:\mathrm{up}\:\mathrm{head}\:\mathrm{with} \\ $$$$\mathrm{probability}\:\mathrm{p}\:\mathrm{and}\:\mathrm{tail}\:\mathrm{with}\:\mathrm{probability} \\ $$$$\mathrm{1}−\mathrm{p}\:\mathrm{independently}\:\mathrm{of}\:\mathrm{each}\:\mathrm{flip}\:\mathrm{is}\:\mathrm{flipped}\:\mathrm{five}\:\mathrm{times}. \\ $$$$\mathrm{The}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{two}\:\mathrm{heads}\:\mathrm{and}\:\mathrm{three}\:\mathrm{tails}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\frac{\mathrm{1}}{\mathrm{7}}\:\mathrm{of}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{three} \\ $$$$\mathrm{heads}\:\mathrm{and}\:\mathrm{two}\:\mathrm{tails}.\:\mathrm{Let}\:\mathrm{p}=\frac{\mathrm{x}}{\mathrm{y}},\:\mathrm{where} \\ $$$$\mathrm{gcd}\left(\mathrm{x},\mathrm{y}\right)\:=\mathrm{1}\:.\:\mathrm{Find}\:\mathrm{x}+\mathrm{y}. \\ $$ Answered…
Question Number 45645 by byaw last updated on 15/Oct/18 Answered by MJS last updated on 15/Oct/18 $$\left\{\underset{\mathrm{1}} {\mathrm{1}},\:\underset{\mathrm{2}} {\mathrm{2}},\:\underset{\mathrm{2}} {\mathrm{3}},\:\underset{\mathrm{3}} {\mathrm{4}},\:\underset{\mathrm{2}} {\mathrm{5}},\:\underset{\mathrm{4}} {\mathrm{6}},\:\underset{\mathrm{2}} {\mathrm{8}},\:\underset{\mathrm{1}} {\mathrm{9}},\:\underset{\mathrm{2}}…
Question Number 111163 by Aina Samuel Temidayo last updated on 02/Sep/20 $$\mathrm{A}\:\mathrm{bag}\:\mathrm{contains}\:\mathrm{11}\:\mathrm{white}\:\mathrm{balls}\:\mathrm{and}\:\mathrm{9} \\ $$$$\mathrm{black}\:\mathrm{balls},\:\mathrm{another}\:\mathrm{contains}\:\mathrm{12}\:\mathrm{white} \\ $$$$\mathrm{balls}\:\mathrm{and}\:\mathrm{13}\:\mathrm{black}\:\mathrm{balls}.\:\mathrm{If}\:\mathrm{two}\:\mathrm{balls} \\ $$$$\mathrm{are}\:\mathrm{drawn}\:\mathrm{without}\:\mathrm{replacement},\:\mathrm{from} \\ $$$$\mathrm{each}\:\mathrm{bag}\:\mathrm{find}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that} \\ $$$$\mathrm{exactly}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{4}\:\mathrm{balls}\:\mathrm{is}\:\mathrm{white}? \\ $$ Commented…
Question Number 110953 by bemath last updated on 01/Sep/20 Commented by Khanacademy last updated on 01/Sep/20 $$\boldsymbol{{Mumkin}}\:\:\boldsymbol{{bo}}'\boldsymbol{{lgan}}\:\:\boldsymbol{{imkoniyatlar}}\:\:\mathrm{9}\bullet\mathrm{8}/\mathrm{2}=\mathrm{36}. \\ $$$$\boldsymbol{{Ikkita}}\:\:\boldsymbol{{oqni}}\:\:\:\:\boldsymbol{{tanlash}}\:\:\:\:\boldsymbol{{mumkinligi}}\:\:\mathrm{5}\bullet\mathrm{4}/\mathrm{2}=\mathrm{10}.\:\: \\ $$$$\boldsymbol{{Demak}}:\:\:\:\mathrm{10}/\mathrm{36}=\mathrm{5}/\mathrm{18}\:\:\:\:\:\boldsymbol{{C}}. \\ $$$$\:\:\:\:\:\boldsymbol{{Telegram}}\:\:\:\boldsymbol{{manzil}}:\:\:\alpha\boldsymbol{{Quvonchbek}}\mathrm{3737} \\ $$…