Question Number 112502 by bemath last updated on 08/Sep/20 Answered by floor(10²Eta[1]) last updated on 08/Sep/20 $$\mathrm{N}=\mathrm{10a}+\mathrm{b} \\ $$$$\mid\mathrm{a}^{\mathrm{2}} −\mathrm{b}^{\mathrm{2}} \mid=\mathrm{p} \\ $$$$\mathrm{suppose}\:\mathrm{WLOG}\:\mathrm{that}\:\mathrm{a}>\mathrm{b} \\ $$$$\left(\mathrm{a}−\mathrm{b}\right)\left(\mathrm{a}+\mathrm{b}\right)=\mathrm{p}…
Question Number 112359 by udaythool last updated on 07/Sep/20 $$\mathrm{Suppose}\:\mathrm{a}\:\mathrm{job}\:\mathrm{consists}\:\mathrm{of}\:\boldsymbol{{n}}\:\mathrm{tasks} \\ $$$$\mathrm{each}\:\mathrm{of}\:\mathrm{which}\:\mathrm{takes}\:\mathrm{time}\:\boldsymbol{{t}} \\ $$$$\mathrm{seconds}.\:\mathrm{Thus}\:\mathrm{if}\:\mathrm{there}\:\mathrm{are}\:\mathrm{no} \\ $$$$\mathrm{failuers}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{over}\:\mathrm{all}\:\mathrm{computed} \\ $$$$\mathrm{nodes}\:\mathrm{of}\:\mathrm{the}\:\mathrm{time}\:\mathrm{taken}\:\mathrm{to}\: \\ $$$$\mathrm{execute}\:\mathrm{tasks}\:\mathrm{at}\:\mathrm{that}\:\mathrm{node}\:\mathrm{is}\:\boldsymbol{{nt}}. \\ $$$$\mathrm{Sppose}\:\mathrm{also}\:\mathrm{that}\:\mathrm{the}\:\mathrm{probability} \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{task}\:\mathrm{failing}\:\mathrm{is}\:\boldsymbol{{p}}\:\mathrm{per}\:\mathrm{job}\:\mathrm{per} \\…
Question Number 177814 by mr W last updated on 09/Oct/22 $${The}\:{probability}\:{that}\:{you}\:{give}\:{the}\:{right} \\ $$$${answer}\:{to}\:{this}\:{question}\:{is}… \\ $$$$ \\ $$$$\left.{A}\left.\right)\left.\:\left.\mathrm{0\%}\:\:\:\:{B}\right)\:\mathrm{25\%}\:\:\:\:{C}\right)\:\mathrm{50\%}\:\:\:\:{D}\right)\mathrm{100\%} \\ $$ Commented by cortano1 last updated on…
Question Number 112163 by bobhans last updated on 06/Sep/20 $$\mathrm{In}\:\mathrm{a}\:\mathrm{class}\:\mathrm{of}\:\mathrm{30}\:\mathrm{pupils}\:,\:\mathrm{12}\:\mathrm{are}\:\mathrm{girls}\:\mathrm{and}\: \\ $$$$\mathrm{2}\:\mathrm{of}\:\mathrm{them}\:\mathrm{are}\:\mathrm{short}−\mathrm{sighted}.\:\mathrm{Among}\: \\ $$$$\mathrm{18}\:\mathrm{boys}\:,\:\mathrm{6}\:\mathrm{are}\:\mathrm{short}−\mathrm{sighted}\:.\:\mathrm{If}\:\mathrm{a}\:\mathrm{pupil} \\ $$$$\mathrm{is}\:\mathrm{selected}\:\mathrm{at}\:\mathrm{random},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability} \\ $$$$\mathrm{that}\:\mathrm{the}\:\mathrm{pupil}\:\mathrm{chosen}\:\mathrm{will}\:\mathrm{be}\: \\ $$$$\begin{cases}{\left(\mathrm{a}\right)\:\mathrm{a}\:\mathrm{girls}}\\{\left(\mathrm{b}\right)\:\mathrm{short}−\mathrm{sighted}}\\{\left(\mathrm{c}\right)\:\mathrm{a}\:\mathrm{short}−\mathrm{sighted}\:\mathrm{boy}}\end{cases} \\ $$ Answered by MJS_new…
Question Number 111826 by Aina Samuel Temidayo last updated on 05/Sep/20 $$\mathrm{There}\:\mathrm{are}\:\mathrm{two}\:\mathrm{cards};\:\mathrm{one}\:\mathrm{is}\:\mathrm{yellow}\:\mathrm{on} \\ $$$$\mathrm{both}\:\mathrm{sides}\:\mathrm{and}\:\mathrm{the}\:\mathrm{other}\:\mathrm{one}\:\mathrm{is}\:\mathrm{yellow} \\ $$$$\mathrm{in}\:\mathrm{one}\:\mathrm{side}\:\mathrm{and}\:\mathrm{red}\:\mathrm{on}\:\mathrm{the}\:\mathrm{other}.\:\mathrm{The} \\ $$$$\mathrm{cards}\:\mathrm{have}\:\mathrm{the}\:\mathrm{same}\:\mathrm{probability}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$$$\mathrm{of}\:\mathrm{being}\:\mathrm{chosen},\:\mathrm{and}\:\mathrm{one}\:\mathrm{is}\:\mathrm{chosen}\:\mathrm{and} \\ $$$$\mathrm{placed}\:\mathrm{on}\:\mathrm{the}\:\mathrm{table}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{upper}\:\mathrm{side} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{card}\:\mathrm{on}\:\mathrm{the}\:\mathrm{table}\:\mathrm{is}\:\mathrm{yellow}, \\…
Question Number 111788 by 675480065 last updated on 04/Sep/20 Answered by bemath last updated on 05/Sep/20 $$\:{a}\:=\:\mathrm{3}\:,\:{b}\:=\:\mathrm{4}\:;\:{c}\:=\:\mathrm{4} \\ $$$$\Leftrightarrow\:\mathrm{3}!\:\mathrm{3}!\:=\:\left(\mathrm{6}\right)^{\mathrm{2}} \:=\:\mathrm{36} \\ $$$$\Leftrightarrow\:\mathrm{3}!+\mathrm{3}!+\mathrm{4}!\:=\:\mathrm{6}+\mathrm{6}+\mathrm{24}\:=\:\mathrm{36}\: \\ $$ Terms…
Question Number 111690 by bemath last updated on 04/Sep/20 Answered by john santu last updated on 04/Sep/20 $$\:{let}\:\begin{cases}{{white}\:{ball}\:=\:{x}}\\{{red}\:{ball}=\mathrm{2}{x}}\\{{black}\:{ball}=\mathrm{30}−\mathrm{3}{x}}\end{cases} \\ $$$${so}\:{the}\:{number}\:{of}\:{way}\:{to}\:{take}\: \\ $$$$\mathrm{2}\:{white}\:{balls}\:{and}\:\mathrm{1}\:{black}\:{ball}\:{is} \\ $$$${C}_{\mathrm{2}} ^{\:{x}}…
Question Number 111533 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{The}\:\mathrm{mean},\mathrm{median}\:\mathrm{and}\:\mathrm{mode}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{data}\:\mathrm{values}\:\mathrm{90},\mathrm{54},\mathrm{x},\mathrm{123},\mathrm{62},\mathrm{78},\mathrm{58},\mathrm{81} \\ $$$$\mathrm{are}\:\mathrm{all}\:\mathrm{equal}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}? \\ $$ Commented by Rasheed.Sindhi last updated on 04/Sep/20…
Question Number 45920 by byaw last updated on 18/Oct/18 Answered by math1967 last updated on 19/Oct/18 $$\left.{i}\right)\:{All}\:\mathrm{4}\:{balls}\:{are}\:{black}=\:\frac{\:^{\mathrm{8}} {c}_{\mathrm{2}} \:}{\:^{\mathrm{20}} {c}_{\mathrm{2}} }\cap\frac{\:^{\mathrm{15}} {c}_{\mathrm{2}} }{\:^{\mathrm{25}} {c}_{\mathrm{2}} }\:…
Question Number 45827 by byaw last updated on 17/Oct/18 Commented by MJS last updated on 17/Oct/18 $$\mathrm{the}\:\mathrm{source}\:\mathrm{of}\:\mathrm{these}\:\mathrm{questions}\:\mathrm{is}\:\mathrm{at}\:\mathrm{least}\:\mathrm{not} \\ $$$$\mathrm{accurate},\:\mathrm{always}\:\mathrm{something}\:\mathrm{missing}\:\mathrm{or}\:\mathrm{other} \\ $$$$\mathrm{mistakes} \\ $$ Answered by…