Category: Probability and Statistics

Question Number 45645 by byaw last updated on 15/Oct/18 Answered by MJS last updated on 15/Oct/18 $$\left\{\underset{\mathrm{1}} {\mathrm{1}},\:\underset{\mathrm{2}} {\mathrm{2}},\:\underset{\mathrm{2}} {\mathrm{3}},\:\underset{\mathrm{3}} {\mathrm{4}},\:\underset{\mathrm{2}} {\mathrm{5}},\:\underset{\mathrm{4}} {\mathrm{6}},\:\underset{\mathrm{2}} {\mathrm{8}},\:\underset{\mathrm{1}} {\mathrm{9}},\:\underset{\mathrm{2}}…

Question Number 110953 by bemath last updated on 01/Sep/20 Commented by Khanacademy last updated on 01/Sep/20 $$\mathit{M}\mathit{u}\mathit{m}\mathit{k}\mathit{i}\mathit{n}{\mathit{b}\mathit{o}}^{\prime }\mathit{l}\mathit{g}\mathit{a}\mathit{n}\mathit{i}\mathit{m}\mathit{k}\mathit{o}\mathit{n}\mathit{i}\mathit{y}\mathit{a}\mathit{t}\mathit{l}\mathit{a}\mathit{r}9\bullet 8/2=36.$$$$\mathit{I}\mathit{k}\mathit{k}\mathit{i}\mathit{t}\mathit{a}\mathit{o}\mathit{q}\mathit{n}\mathit{i}\mathit{t}\mathit{a}\mathit{n}\mathit{l}\mathit{a}\mathit{s}\mathit{h}\mathit{m}\mathit{u}\mathit{m}\mathit{k}\mathit{i}\mathit{n}\mathit{l}\mathit{i}\mathit{g}\mathit{i}5\bullet 4/2=10.$$$$\mathit{D}\mathit{e}\mathit{m}\mathit{a}\mathit{k}:10/36=5/18\mathit{C}.$$$$\mathit{T}\mathit{e}\mathit{l}\mathit{e}\mathit{g}\mathit{r}\mathit{a}\mathit{m}\mathit{m}\mathit{a}\mathit{n}\mathit{z}\mathit{i}\mathit{l}:\alpha \mathit{Q}\mathit{u}\mathit{v}\mathit{o}\mathit{n}\mathit{c}\mathit{h}\mathit{b}\mathit{e}\mathit{k}3737$$…

Question Number 110911 by Ar Brandon last updated on 31/Aug/20 $$\mathrm{Four}\mathrm{teachers}\mathrm{A},\mathrm{B},\mathrm{C},\mathrm{and}\mathrm{D}\mathrm{each}\mathrm{proposed}\mathrm{two}\mathrm{exercises},$$$$\mathrm{one}\mathrm{on}\mathrm{algebra}\mathrm{and}\mathrm{another}\mathrm{on}\mathrm{analyses},\mathrm{to}\mathrm{form}\mathrm{an}\mathrm{exam}.$$$$\mathrm{The}\mathrm{students}\mathrm{have}\mathrm{to}\mathrm{choose}\mathrm{two}\mathrm{exercises}\mathrm{at}\mathrm{random}.$$$$1.\mathrm{Calculate}\mathrm{the}\mathrm{probability}\mathrm{P}\left(\mathrm{a}\right)\mathrm{of}\mathrm{a}\mathrm{student}\mathrm{to}\mathrm{choose}$$$$\mathrm{two}\mathrm{exercises}\mathrm{on}\mathrm{algebra}.$$$$\mathrm{a}\mathrm{\setminus }\mathrm{P}\left(\mathrm{a}\right)=\frac{3}{16},\mathrm{b}\mathrm{\setminus }\mathrm{P}\left(\mathrm{a}\right)=\frac{3}{14},\mathrm{c}\mathrm{\setminus }\mathrm{P}\left(\mathrm{a}\right)=\frac{1}{4},\mathrm{d}\mathrm{\setminus }\mathrm{None}$$$$2.\mathrm{Calculate}\mathrm{the}\mathrm{probability}\mathrm{P}\left(\mathrm{b}\right)\mathrm{of}\mathrm{choosing}\mathrm{two}\mathrm{exercises}$$$$\mathrm{proposed}\:\mathrm{by}\:\mathrm{the}\:\mathrm{same}\:\mathrm{teacher}.…

Question Number 110826 by Aina Samuel Temidayo last updated on 30/Aug/20 $$\mathrm{The}\mathrm{probability}\mathrm{that}\mathrm{at}\mathrm{least}\mathrm{one}\mathrm{of}$$$$\mathrm{the}\mathrm{events}\mathrm{A}\mathrm{and}\mathrm{B}\mathrm{occurs}\mathrm{is}0.7\mathrm{and}$$$$\mathrm{they}\mathrm{occur}\mathrm{simultaneously}\mathrm{with}$$$$\mathrm{probability}0.2.\mathrm{Then}\mathrm{P}\left(\stackrel{-}{\mathrm{A}}\right)+\mathrm{P}\left(\overline{\mathrm{B}}\right)=$$ Commented by kaivan.ahmadi…

Question Number 44389 by rahul 19 last updated on 28/Sep/18 $$Given2eventsAandBsuchthat$$$$P\left(A\right)=\frac{1}{3},P(A\cup B)=\frac{3}{4}then$$$$findrangeofP\left(B\right)?$$ Terms of Service Privacy Policy Contact: info@tinkutara.com