Question Number 168375 by fotosy2k last updated on 09/Apr/22 Commented by fotosy2k last updated on 09/Apr/22 $${pls}\:{help}\:{me}\:{solve} \\ $$$$ \\ $$ Commented by peter frank…
Question Number 168180 by peter frank last updated on 05/Apr/22 Answered by MJS_new last updated on 05/Apr/22 $$\left(\mathrm{i}\right)\:\mathrm{if}\:\mathrm{there}\:\mathrm{are}\:\mathrm{12}\:\mathrm{face}\:\mathrm{cards}\:\mathrm{the}\:\mathrm{possibility}\:\mathrm{to} \\ $$$$\mathrm{draw}\:\mathrm{one}\:\mathrm{is}\:\frac{\mathrm{12}}{\mathrm{52}}=\frac{\mathrm{3}}{\mathrm{13}} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{1}−\frac{\mathrm{1}}{\mathrm{4}}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$ Commented…
Question Number 168178 by peter frank last updated on 05/Apr/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 168179 by peter frank last updated on 05/Apr/22 Answered by peter frank last updated on 07/Apr/22 $$\mathrm{Total}\:\mathrm{number}\:\mathrm{of}\:\mathrm{object}= \\ $$$$\mathrm{100}+\mathrm{50}=\mathrm{150} \\ $$$$\mathrm{n}\left(\mathrm{S}\right)=^{\mathrm{150}} \mathrm{C}_{\mathrm{2}} \:=\mathrm{11175}…
Question Number 168035 by pete last updated on 01/Apr/22 $$\mathrm{In}\:\mathrm{an}\:\mathrm{examination},\:\mathrm{the}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{charles} \\ $$$$\mathrm{scoring}\:\mathrm{the}\:\mathrm{highest}\:\mathrm{mark}\:\mathrm{in}\:\mathrm{Maths},\:\mathrm{Physics} \\ $$$$\mathrm{and}\:\mathrm{Chemistry}\:\mathrm{are}\:\mathrm{0}.\mathrm{90},\:\mathrm{0}.\mathrm{75}\:\mathrm{and}\:\mathrm{0}.\mathrm{80}\:\mathrm{respectively}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{he}\:\mathrm{will}\:\mathrm{get} \\ $$$$\mathrm{the}\:\mathrm{highest}\:\mathrm{mark}\:\mathrm{in}\:\mathrm{at}\:\mathrm{least}\:\mathrm{3}\:\mathrm{subjects}. \\ $$ Commented by MJS_new last updated…
Question Number 167848 by ArielVyny last updated on 27/Mar/22 $${Dans}\:{une}\:{PME},\:{sont}\:{employes}\:\mathrm{6}{ouvriers} \\ $$$$\mathrm{5}\:{employes}.\:{le}\:{PDG}\:{souhaite}\:{prendre}\:{l}'{avis} \\ $$$${de}\:{son}\:{personnel}.\:{il}\:{interroge}\:\mathrm{7}\:{personnes} \\ $$$${choisies}\:{au}\:{hasard}\:{parmi}\:{ces}\:\mathrm{11}\:{personnes}. \\ $$$${soit}\:{X}\:{la}\:{variable}\:{aleatoire}:\:“{nombre}\: \\ $$$${d}'{ouvriers}\:{interroges}'' \\ $$$$\left.\mathrm{1}\right){quelles}\:{sont}\:{les}\:{valeurs}\:{prises}\:{par}\:{X} \\ $$$$\left.\mathrm{2}\right){quelle}\:{est}\:{la}\:{loi}\:{de}\:{probabilite} \\…
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Question Number 102269 by mohammad17 last updated on 07/Jul/20 $${if}\:{P}_{\mathrm{2}} ^{\:{n}−{m}} =\mathrm{72}\:\:{and}\:{P}_{\mathrm{2}} ^{\:{n}+{m}} =\mathrm{210}\:{find}\:{the}\:{value}\:{of}\:{m}\:{and}\:{n}\:? \\ $$ Answered by Dwaipayan Shikari last updated on 07/Jul/20 $$\frac{\left({n}−{m}\right)!}{\left({n}−{m}−\mathrm{2}\right)!}=\mathrm{72}…
Question Number 167449 by Backrom last updated on 16/Mar/22 Commented by Backrom last updated on 16/Mar/22 $$ \\ $$$$\mathrm{Please}\:\mathrm{help}\:\:\mathrm{me}.\:\mathrm{I}\:\mathrm{need}\:\mathrm{it}\:\mathrm{before}\:\mathrm{friday} \\ $$$$\mathrm{Thanks}\:\mathrm{beforehand} \\ $$$$ \\ $$$$…
Question Number 167454 by rexford last updated on 16/Mar/22 Terms of Service Privacy Policy Contact: info@tinkutara.com