Question Number 100017 by bemath last updated on 24/Jun/20 $$\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\:+\:\mathrm{y}\:=\:\mathrm{sec}\:\mathrm{3x}\: \\ $$ Answered by mathmax by abdo last updated on 24/Jun/20 $$\mathrm{y}^{''} \:+\mathrm{y}\:=\frac{\mathrm{1}}{\mathrm{cos}\left(\mathrm{3x}\right)}\:\:\:\:\:\left(\mathrm{he}\right)\:\rightarrow\mathrm{r}^{\mathrm{2}}…
Question Number 99666 by byaw last updated on 22/Jun/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 99665 by byaw last updated on 22/Jun/20 Commented by byaw last updated on 05/Jul/20 $$ \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 99661 by byaw last updated on 22/Jun/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 164995 by Mathematification last updated on 24/Jan/22 Answered by aleks041103 last updated on 25/Jan/22 $${Let}'{s}\:{label}\:{the}\:{top}\:{vertex}\:{V}^{\:+} ,\:{the}\:{bottom} \\ $$$${one}\:−\:{V}^{\:−} ,\:{and}\:{the}\:{verteces}\:{on}\:{the}\:{base}\:−\:{O}. \\ $$$${Notation}: \\ $$$${p}\left({n}\mid{A}\rightarrow{B}\right)\:−\:{the}\:{probability}\:{of}\:{arriving}…
Question Number 33867 by Joel578 last updated on 26/Apr/18 $$\mathrm{Given}\:{A}\left({t}\right)\:\mathrm{is}\:\mathrm{an}\:\mathrm{area}\:\mathrm{bounded}\:\mathrm{between}\: \\ $$$${y}\:=\:{x}^{\mathrm{2}} \:+\:{tx}\:\mathrm{and}\:\mathrm{x}−\mathrm{axis},\:\:\mathrm{0}\:<\:{t}\:<\:\mathrm{2} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{propability}\:\mathrm{we}\:\mathrm{choose}\:{t} \\ $$$$\mathrm{so}\:\frac{\mathrm{1}}{\mathrm{48}}\:\leqslant\:{A}\left({t}\right)\:\leqslant\:\frac{\mathrm{1}}{\mathrm{16}} \\ $$ Answered by MJS last updated on…
Question Number 99230 by Ar Brandon last updated on 19/Jun/20 $$\ast\backslash\mathcal{I}\mathrm{n}\:\mathrm{a}\:\mathrm{certain}\:\mathrm{country},\:\mathrm{4}\:\mathrm{people}\:\mathrm{are}\:\mathrm{tested}\:\mathrm{positive}\:\mathrm{for}\:\mathrm{the}\:\mathrm{covid}−\mathrm{19}\:\mathrm{per}\:\mathrm{hour}. \\ $$$$\mathcal{D}\mathrm{etermine}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{in}\:\mathrm{an}\:\mathrm{hour}; \\ $$$$\mathrm{a}\backslash\mathrm{Exactly}\:\mathrm{2}\:\mathrm{people}\:\mathrm{are}\:\mathrm{contaminated} \\ $$$$\mathrm{b}\backslash\mathrm{At}\:\mathrm{most}\:\mathrm{one}\:\mathrm{person}\:\mathrm{is}\:\mathrm{contaminated}. \\ $$$$\mathrm{c}\backslash\mathrm{Between}\:\mathrm{2}\:\mathrm{and}\:\mathrm{5}\:\mathrm{people}\:\mathrm{are}\:\mathrm{contaminated}. \\ $$ Commented by john santu…
Question Number 99229 by Ar Brandon last updated on 19/Jun/20 $$\ast\backslash\:\mathcal{I}\mathrm{n}\:\mathrm{the}\:\mathrm{fight}\:\mathrm{against}\:\mathrm{covid}−\mathrm{19},\:\mathrm{the}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{finding}\:\mathrm{an}\:\mathrm{individual} \\ $$$$\:\:\:\:\:\mathrm{with}\:\mathrm{signs}\:\mathrm{of}\:\mathrm{allergy}\:\mathrm{during}\:\mathrm{the}\:\mathrm{injection}\:\mathrm{of}\:\mathrm{chloroquine}\:\mathrm{is}\:\mathrm{assumed}\:\mathrm{to}\:\mathrm{be}\:\mathrm{0}.\mathrm{2} \\ $$$$\:\:\:\:\:\mathcal{F}\mathrm{or}\:\mathrm{a}\:\mathrm{selection}\:\mathrm{of}\:\mathrm{10}\:\mathrm{people},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}; \\ $$$$\mathrm{a}\backslash\mathcal{A}\mathrm{t}\:\mathrm{least}\:\mathrm{3}\:\mathrm{people}\:\mathrm{show}\:\mathrm{signs}\:\mathrm{of}\:\mathrm{this}\:\mathrm{allergy}. \\ $$$$\mathrm{b}\backslash\mathrm{Between}\:\mathrm{3}\:\mathrm{and}\:\mathrm{5}\:\mathrm{people}\:\mathrm{present}\:\mathrm{these}\:\mathrm{signs}. \\ $$$$\mathrm{c}\backslash\mathcal{D}\mathrm{etermine}\:\mathrm{the}\:\mathrm{mathematical}\:\mathrm{expectation}\:\mathrm{and}\:\mathrm{the}\:\mathrm{standard}\:\mathrm{deviation}. \\ $$ Terms of…
Question Number 98201 by pranesh last updated on 12/Jun/20 Answered by Rio Michael last updated on 12/Jun/20 $${P}\left({A}\right)\:=\:\mathrm{0}.\mathrm{4},\:{P}\left({B}\right)\:=\:\mathrm{0}.\mathrm{3}\:,\:{P}\left({A}\:\cup\:{B}\right)\:=\:\mathrm{0}.\mathrm{6} \\ $$$$\mathrm{but}\:{P}\left({A}\:\cup\:{B}\right)\:=\:{P}\left({A}\right)\:+\:{P}\left({B}\right)−{P}\left({A}\:\cap\:{B}\right) \\ $$$$\Rightarrow\:\mathrm{0}.\mathrm{6}\:=\:\mathrm{0}.\mathrm{4}\:+\:\mathrm{0}.\mathrm{3}−{P}\left({A}\:\cap\:{B}\right) \\ $$$$\Rightarrow\:−\mathrm{0}.\mathrm{1}\:=\:−{P}\left({A}\:\cap\:{B}\right)\:\Rightarrow\:\:{P}\left({A}\:\cap\:{B}\right)\:=\:\mathrm{0}.\mathrm{1} \\…
Question Number 98142 by Ar Brandon last updated on 11/Jun/20 $$\mathcal{A}\:\mathrm{man}\:\mathrm{arrives}\:\mathrm{at}\:\mathrm{a}\:\mathrm{bus}\:\mathrm{stop}\:\mathrm{in}\:\mathrm{between}\:\mathrm{12}:\mathrm{00pm}\:\mathrm{and} \\ $$$$\mathrm{12}:\mathrm{15pm}.\:\mathrm{Assuming}\:\mathrm{a}\:\mathrm{bus}\:\mathrm{arrives}\:\mathrm{the}\:\mathrm{bus}\:\mathrm{stop}\:\mathrm{every} \\ $$$$\mathrm{15}\:\mathrm{minutes},\:\mathrm{find}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{him}\:\mathrm{getting}\:\mathrm{a}\:\mathrm{bus}\:\mathrm{in} \\ $$$$\mathrm{less}\:\mathrm{than}\:\mathrm{5}\:\mathrm{minutes}. \\ $$ Terms of Service Privacy Policy Contact:…