Question Number 18945 by Tinkutara last updated on 01/Aug/17 $$\mathrm{A}\:\mathrm{point}\:'\mathrm{A}'\:\mathrm{is}\:\mathrm{randomly}\:\mathrm{chosen}\:\mathrm{in}\:\mathrm{a} \\ $$$$\mathrm{square}\:\mathrm{of}\:\mathrm{side}\:\mathrm{length}\:\mathrm{1}\:\mathrm{unit}.\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{probability}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{from}\:\mathrm{A}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{centre}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{does}\:\mathrm{not}\:\mathrm{exceed}\:\mathrm{x}. \\ $$ Commented by dioph last updated on 02/Aug/17…
Question Number 149981 by jlewis last updated on 08/Aug/21 $$\mathrm{a}\:\mathrm{full}\:\mathrm{deck}\:\mathrm{of}\:\mathrm{52}\:\mathrm{cards}\:\mathrm{contains}\:\mathrm{13} \\ $$$$\:\mathrm{hearts}.\:\mathrm{Pick}\:\mathrm{8}\:\mathrm{cards}\:\mathrm{from}\:\mathrm{the}\:\mathrm{deck} \\ $$$$\mathrm{at}\:\mathrm{random}\:\mathrm{without}\:\mathrm{replacement}. \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{you}\:\mathrm{get} \\ $$$$\mathrm{no}\:\mathrm{heart}? \\ $$$$ \\ $$ Answered by mr…
Question Number 149532 by ArielVyny last updated on 06/Aug/21 $${on}\:{realise}\:{une}\:{suite}\:{infinie}\:{d}'{epreuves} \\ $$$${independantes}.{chaque}\:{epreuve}\:{resulte}\:{en} \\ $$$$\left.{un}\:{succes}\:{avec}\:{la}\:{probabilite}\:{p}\in\right]\mathrm{0};\mathrm{1}\left[\:{ou}\:{un}\right. \\ $$$${echec}\:{avec}\:{la}\:{probabilite}\:{q}=\mathrm{1}−{p}.{soit}\:{A}_{{n}} \\ $$$${l}'{evement}\:“{obenir}\:{au}\:{moins}\:{un}\:{succes}\:{au} \\ $$$${cours}\:{des}\:{premieres}\:{epreuves}.''\:{determiner} \\ $$$${P}\left({A}_{{n}} \right) \\ $$…
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Question Number 149534 by ArielVyny last updated on 06/Aug/21 Answered by Olaf_Thorendsen last updated on 06/Aug/21 $$\mathrm{Exercice}\:\mathrm{1}. \\ $$$$ \\ $$$$\mathrm{Loi}\:\mathrm{geometrique}\:\mathrm{P}\left(\mathrm{X}={k}\right)\:=\:{q}^{{k}−\mathrm{1}} {p} \\ $$$$\mathrm{La}\:\mathrm{fonction}\:\mathrm{de}\:\mathrm{repartition}\:\mathrm{est}\:: \\…
Question Number 149471 by ArielVyny last updated on 05/Aug/21 $${on}\:{distribue}\:{au}\:{hasard}\:\mathrm{8}\:{boules}\:{b}_{\mathrm{1}} …{b}_{\mathrm{8}} \\ $$$${dans}\:\mathrm{6}\:{tiroirs}\:{t}_{\mathrm{1}} …{t}_{\mathrm{6}} .{soit}\:{A}_{{i}} \:{l}'{evenement} \\ $$$$“{le}\:{tiroir}\:{t}_{{i}} \:{est}\:{vide}''\:{les}\:{evenements}\:{A}_{\mathrm{1}} {et} \\ $$$${A}_{\mathrm{2}} {sont}-{ils}\:{independants}\:? \\ $$…
Question Number 149463 by jlewis last updated on 05/Aug/21 $$\mathrm{Let}\:\mathrm{the}\:\mathrm{independent}\:\mathrm{random}\:\mathrm{variables} \\ $$$$\mathrm{X}_{\mathrm{1}} \:\mathrm{and}\:\mathrm{X}_{\mathrm{2}} \:\mathrm{have}\:\mathrm{binomial}\:\mathrm{distribution} \\ $$$$\mathrm{with}\:\mathrm{parameters}\:\mathrm{n}_{\mathrm{1}} =\mathrm{3},\mathrm{p}=\mathrm{2}/\mathrm{3}\:\mathrm{and}\:\mathrm{n}_{\mathrm{2}} =\mathrm{4} \\ $$$$\mathrm{p}=\mathrm{1}/\mathrm{2}\:\:\mathrm{respectively}.\: \\ $$$$\mathrm{Compute}\:\mathrm{P}\left(\mathrm{X}_{\mathrm{1}} =\mathrm{X}_{\mathrm{2}} \right) \\…
Question Number 149440 by nadovic last updated on 05/Aug/21 Answered by Olaf_Thorendsen last updated on 07/Aug/21 $$\left(\mathrm{a}\right)\:\mathrm{A}_{\mathrm{1}} =\:“\mathrm{persons}\:\mathrm{from}\:\mathrm{only}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{three} \\ $$$$\mathrm{groups}''. \\ $$$$\mathrm{That}\:\mathrm{means}\:\mathrm{3}\:\mathrm{volleyball}\:\mathrm{players}\:\mathrm{or} \\ $$$$\mathrm{3}\:\mathrm{hockey}\:\mathrm{players}. \\…
Question Number 149406 by rexford last updated on 05/Aug/21 $${if}\:{x}\:{has}\:{a}\:{binomial}\:{distribution}\:{with}\:{n}=\mathrm{10}\:{and}\:{p}=\frac{\mathrm{1}}{\mathrm{3}}.{Find}\:{E}\left({e}^{\mathrm{3}{x}} \right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 149030 by jlewis last updated on 02/Aug/21 $$\mathrm{f}\left(\mathrm{x}\right)=\underset{\underset{\mathrm{5}^{\mathrm{x}} +\mathrm{1}} {−}} {\mathrm{4}}\:\:\:\:\mathrm{x}=\mathrm{0},\mathrm{1},\mathrm{2}…..\:\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{moment}\: \\ $$$$\mathrm{generating}\:\mathrm{function} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com