Question Number 144754 by ArielVyny last updated on 28/Jun/21 $${consider}\:{a}\:{random}\:{variable}\:{definite}\:{by} \\ $$$${geometric}\:{law}\:{compute}\:{P}\left(\left\{{X}\geqslant\mathrm{4}\right\}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 13336 by tawa tawa last updated on 19/May/17 $$\mathrm{A}\:\mathrm{debating}\:\mathrm{team}\:\mathrm{is}\:\mathrm{to}\:\mathrm{be}\:\mathrm{selected}\:\mathrm{from}\:\mathrm{a}\:\mathrm{group}\:\mathrm{of}\:\mathrm{8}\:\mathrm{boys}\:\mathrm{and}\:\mathrm{6}\:\mathrm{girls}.\:, \\ $$$$\mathrm{in}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{this}\:\mathrm{be}\:\mathrm{done}\:\mathrm{if}\:\mathrm{the}\:\mathrm{team}\: \\ $$$$\left(\mathrm{a}\right)\:\mathrm{Must}\:\mathrm{be}\:\mathrm{either}\:\mathrm{all}\:\mathrm{boys}\:\mathrm{or}\:\mathrm{all}\:\mathrm{girls} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{Must}\:\mathrm{consist}\:\mathrm{of}\:\mathrm{two}\:\mathrm{boys}\:\mathrm{and}\:\mathrm{two}\:\mathrm{girls} \\ $$ Commented by tawa tawa last updated…
Question Number 144372 by katongo last updated on 25/Jun/21 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21 by user1 last updated on 25/Jan/15 $$\mathrm{A}\:\mathrm{card}\:\mathrm{is}\:\mathrm{drawn}\:\mathrm{at}\:\mathrm{random}\:\mathrm{from}\:\mathrm{a}\:\mathrm{well} \\ $$$$\mathrm{shuffled}\:\mathrm{deck}\:\mathrm{of}\:\mathrm{52}\:\mathrm{cards}.\:\mathrm{Find}\:\mathrm{the}\:\: \\ $$$$\mathrm{probability}\:\mathrm{of}\:\mathrm{its}\:\mathrm{being}\:\mathrm{a}\:\mathrm{spade}\:\mathrm{or}\:\mathrm{a}\:\mathrm{king}. \\ $$ Answered by user1 last updated on 30/Oct/14 $$\mathrm{Let}\:{S}\:\mathrm{be}\:\mathrm{the}\:\mathrm{sample}\:\mathrm{space}.\:{n}\left({S}\right)=\mathrm{52}.\: \\…
Question Number 12649 by tawa last updated on 28/Apr/17 Answered by mrW1 last updated on 28/Apr/17 $$\frac{\mathrm{300}+\mathrm{500}+\mathrm{700}−\mathrm{440}−\mathrm{1000}}{\mathrm{2}}=\mathrm{30} \\ $$$$\Rightarrow\mathrm{30}\:{persons}\:{involved}\:{lost}\:{of}\:{injury} \\ $$$${to}\:{all}\:{the}\:{three}. \\ $$ Commented by…
Question Number 12561 by tawa last updated on 25/Apr/17 $$\mathrm{Prove}\:\mathrm{mean},\:\mathrm{expected}\:\mathrm{mean}\:\mathrm{of}\:\mathrm{binomial}\:\mathrm{and}\:\mathrm{bernoulli}\:\mathrm{distribution}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 143593 by pticantor last updated on 16/Jun/21 $${soit}\:\left(\boldsymbol{{X}}_{{i}} \right),{i}\in\left\{\mathrm{1},\mathrm{2},……,{n}\right\}\:{une}\:{suite}\:{de}\:{variable}\:{a}\boldsymbol{{leartoire}}\:\boldsymbol{{independante}} \\ $$$$\left(\boldsymbol{{iid}}\right)\:\boldsymbol{{suivant}}\:\boldsymbol{{la}}\:\boldsymbol{{loi}}\:\boldsymbol{{binomiale}}\:\boldsymbol{{B}}\left(\boldsymbol{{n}},\boldsymbol{{p}}\right)\: \\ $$$$\boldsymbol{{montrer}}\:\boldsymbol{{que}}\:\overset{\_} {\boldsymbol{{X}}}_{\boldsymbol{{n}}} \boldsymbol{{converge}}\:\boldsymbol{{en}}\:\boldsymbol{{loi}}\:\boldsymbol{{vers}}\:\boldsymbol{{E}}\left(\boldsymbol{{X}}\right) \\ $$$$\mathrm{2}−\:\boldsymbol{{montrer}}\:\boldsymbol{{que}}\:\frac{\mathrm{1}}{\boldsymbol{{n}}}\underset{{i}=\mathrm{1}} {\overset{\mathrm{2}} {\sum}}\boldsymbol{{X}}_{\boldsymbol{{i}}\:\:} ^{\mathrm{2}} \boldsymbol{{converge}}\:\boldsymbol{{en}}\:\boldsymbol{{loi}}\:\:\boldsymbol{{vers}}\:\:\:\:\:\:\:\:\boldsymbol{{E}}\:\left(\boldsymbol{{X}}^{\mathrm{2}} \right) \\…
Question Number 12306 by Gaurav3651 last updated on 18/Apr/17 $${Two}\:{similar}\:{boxes}\:{B}_{{i}} \:\left({i}=\mathrm{1},\mathrm{2}\right){contain} \\ $$$$\left({i}+\mathrm{1}\right){red}\:{and}\:\left(\mathrm{5}−{i}−\mathrm{1}\right)\:{black}\:{balls}. \\ $$$${One}\:{box}\:{is}\:{chosen}\:{at}\:{random}\:{and} \\ $$$${two}\:{balls}\:{are}\:{drawn}\:{randomly}. \\ $$$${what}\:{is}\:{the}\:{probability}\:{that}\:{both} \\ $$$${balls}\:{are}\:{of}\:{different}\:{colours}? \\ $$$$\left({a}\right)\:\:\mathrm{1}/\mathrm{2} \\ $$$$\left({b}\right)\:\:\mathrm{3}/\mathrm{10}…
Question Number 77777 by jagoll last updated on 10/Jan/20 $${The}\:{number} \\ $$$${of}\:{words}\:{can}\:{be}\:{made}\:{formed} \\ $$$${using}\:{all}\:{letters}\:{in}\:{the}\:{word} \\ $$$$'{amutasia}'\:{by}\:{not}\:{containing} \\ $$$${the}\:{three}\:{vowels}\:{side}\:{by}\:{side}\:{is}\:? \\ $$ Answered by mr W last…
Question Number 12156 by tawa last updated on 15/Apr/17 $$\mathrm{If}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{the}\:\mathrm{students}\:\mathrm{that}\:\mathrm{pass}\:\mathrm{a}\:\mathrm{test}\:\mathrm{to}\:\mathrm{those}\:\mathrm{that}\:\mathrm{fail}\:\mathrm{is}\:\mathrm{in}\:\mathrm{ratio}\:\mathrm{4}:\mathrm{1}, \\ $$$$\mathrm{If}\:\:\mathrm{9}\:\mathrm{students}\:\mathrm{were}\:\mathrm{chosen}\:\mathrm{at}\:\mathrm{random},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{exactly} \\ $$$$\mathrm{7}\:\mathrm{passed}\:\mathrm{the}\:\mathrm{test}. \\ $$ Answered by mrW1 last updated on 23/Apr/17 $${probability}\:{pass}\:{test}\:{p}=\frac{\mathrm{4}}{\mathrm{4}+\mathrm{1}}=\mathrm{0}.\mathrm{8} \\…