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Category: Probability and Statistics

Question-145463

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Question Number 145463 by puissant last updated on 05/Jul/21 Answered by Olaf_Thorendsen last updated on 05/Jul/21 $$\left.{a}\right)\: \\ $$$$\ast{f}\:{est}\:{absolument}\:{continue}\:\mathrm{et} \\ $$$$\mathrm{notamment}\:\mathrm{en}\:{x}=\mathrm{10}\::\:\frac{\mathrm{10}}{{k}}\:=\:\frac{\mathrm{20}−\mathrm{10}}{{k}} \\ $$$$\ast{son}\:{integrale}\:{vaut}\:\mathrm{1}\:: \\ $$$$\int_{\mathrm{0}}…

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Question-145373

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Question Number 145373 by puissant last updated on 04/Jul/21 Answered by Olaf_Thorendsen last updated on 04/Jul/21 $$\left.\mathrm{1}{a}\right) \\ $$$$ \\ $$$$\mathrm{Le}\:\mathrm{rat}\:\mathrm{n}'\mathrm{a}\:\mathrm{pas}\:\mathrm{de}\:\mathrm{memoire}. \\ $$$$\mathrm{A}\:\mathrm{chaque}\:\mathrm{essai},\:\mathrm{il}\:\mathrm{a}\:\mathrm{3}\:\mathrm{chances}\:\mathrm{sur}\:\mathrm{4}\:\mathrm{de} \\ $$$$\mathrm{choisir}\:\mathrm{une}\:\mathrm{mauvaise}\:\mathrm{porte}\:\mathrm{et}\:\mathrm{une}\:\mathrm{chance}…

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On-dispose-de-N-1-urnes-l-urne-U-k-contient-k-boules-blanches-et-N-k-boules-noires-on-tire-successivement-sans-remise-n-boules-de-l-urne-et-on-note-An-l-evenement-choisir-n-boules-noires-lors-des

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Question Number 145134 by ArielVyny last updated on 02/Jul/21 $${On}\:{dispose}\:{de}\:{N}+\mathrm{1}\:{urnes}.{l}'{urne}\:{U}_{{k}} \\ $$$${contient}\:{k}\:{boules}\:{blanches}\:{et}\:{N}−{k}\:{boules} \\ $$$${noires}.{on}\:{tire}\:{successivement}\:{sans}\: \\ $$$${remise}\:{n}\:{boules}\:{de}\:{l}'{urne}\:{et}\:{on}\:{note}\: \\ $$$${An}\:{l}'{evenement}\:''{choisir}\:{n}\:{boules}\:{noires} \\ $$$${lors}\:{des}\:{n}\:{premiers}\:{tirages}''.\:{Determiner} \\ $$$${P}\left({An}\right).\:{on}\:{notera}\:{U}_{{k}} =''{choisir}\:{l}'{urne}\:{k}'' \\ $$…

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Soit-X-une-variable-aleatoire-de-loi-geometrique-de-parametre-p-0-1-calculer-P-X-4-

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Question Number 145136 by ArielVyny last updated on 02/Jul/21 $${Soit}\:{X}\:{une}\:{variable}\:{aleatoire}\:{de}\:{loi} \\ $$$$\left.{geometrique}\:{de}\:{parametre}\:{p}\in\right]\mathrm{0}.\mathrm{1}\left[\right. \\ $$$${calculer}\:{P}\left(\left\{{X}\geqslant\mathrm{4}\right\}\right) \\ $$ Answered by Olaf_Thorendsen last updated on 03/Jul/21 $${P}\left({X}=\:{k}\right)\:=\:{q}^{{k}−\mathrm{1}} {p}\:=\:\left(\mathrm{1}−{p}\right)^{{k}−\mathrm{1}}…

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