Question Number 77394 by jagoll last updated on 06/Jan/20 $$\mathrm{a}\:\mathrm{6}\:\mathrm{digit}\:\mathrm{number}\:\mathrm{formed}\: \\ $$$$\mathrm{with}\:\mathrm{the}\:\mathrm{first}\:\mathrm{number}\:\mathrm{is}\:\mathrm{2}\:\mathrm{and}\: \\ $$$$\mathrm{contains}\:\mathrm{4}\:\mathrm{equal}\:\mathrm{number}.\:\mathrm{many} \\ $$$$\mathrm{number}\:\mathrm{can}\:\mathrm{be}\:\mathrm{made}\:\mathrm{are}\: \\ $$ Commented by mr W last updated on…
Question Number 11599 by tawa last updated on 28/Mar/17 $$\mathrm{A}\:\mathrm{number}\:\mathrm{is}\:\mathrm{selected}\:\mathrm{at}\:\mathrm{random}\:\mathrm{from}\:\mathrm{the}\:\mathrm{integers}\:\mathrm{10}\:\mathrm{to}\:\mathrm{35}\:\mathrm{exclussive},\:\mathrm{such} \\ $$$$\mathrm{that}\:\mathrm{the}\:\mathrm{chances}\:\mathrm{take}\:\mathrm{the}\:\mathrm{subsets}\:\mathrm{of}\:\mathrm{P},\:\mathrm{Q}\:\mathrm{and}\:\mathrm{R}\:\mathrm{respectively},\:\mathrm{where}\:\mathrm{P}\:\mathrm{is} \\ $$$$\mathrm{even}\:,\:\mathrm{Q}\:\mathrm{is}\:\mathrm{even}\:\mathrm{or}\:\mathrm{prime}\:\mathrm{number},\:\mathrm{and}\:\mathrm{R}\:\mathrm{is}\:\mathrm{odd}\:\mathrm{prime}\:\mathrm{numbers}.\:\mathrm{What}\:\mathrm{is} \\ $$$$\mathrm{the}\:\mathrm{probability}\: \\ $$$$\left(\mathrm{a}\right)\:\mathrm{That}\:\mathrm{exacly}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{events}\:\mathrm{of}\:\mathrm{the}\:\mathrm{subset}\:\mathrm{is}\:\mathrm{choosen}\:? \\ $$$$\left(\mathrm{b}\right)\:\mathrm{Of}\:\mathrm{choosen}\:\mathrm{at}\:\mathrm{most}\:\mathrm{two}\:\mathrm{of}\:\mathrm{the}\:\mathrm{subset}\:\mathrm{of}\:\mathrm{the}\:\mathrm{event}. \\ $$ Answered by mrW1…
Question Number 11600 by tawa last updated on 28/Mar/17 $$\mathrm{A}\:\mathrm{number}\:\mathrm{is}\:\mathrm{selected}\:\mathrm{at}\:\mathrm{random}\:\mathrm{from}\:\mathrm{the}\:\mathrm{integers}\:\mathrm{1}\:\mathrm{to}\:\mathrm{100}\:\mathrm{exclusive},\: \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{chance}\:\mathrm{of}\:\mathrm{choosing}\:\mathrm{at}\:\mathrm{random}\:\mathrm{a}\:\mathrm{two}\:\mathrm{digit}\:\mathrm{number}\:\mathrm{which}\:\mathrm{is} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{Divisible}\:\mathrm{by}\:\mathrm{4} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{The}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{5} \\ $$ Answered by mrW1 last updated on 29/Mar/17…
Question Number 142489 by jlewis last updated on 01/Jun/21 $$\mathrm{In}\:\:\mathrm{a}\:\mathrm{certain}\:\mathrm{urn}\:\mathrm{there}\:\mathrm{are}\:\mathrm{3}\:\mathrm{blue}, \\ $$$$\mathrm{2red}\:\mathrm{and}\:\mathrm{5}\:\mathrm{yellow}\:\mathrm{marbles}. \\ $$$$\mathrm{Calculate}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{atmost} \\ $$$$\mathrm{2}\:\mathrm{marbles}\:\mathrm{will}\:\mathrm{be}\:\mathrm{red}\:\mathrm{if}\:\mathrm{3}\:\mathrm{marbles} \\ $$$$\:\mathrm{are}\:\mathrm{drawn}\:\mathrm{without}\:\mathrm{replacement} \\ $$ Commented by mr W last…
Question Number 76650 by john santu last updated on 29/Dec/19 $${two}\:{dice}\:{are}\:{tossed}\:{together}\:\mathrm{4}\:{times}. \\ $$$${the}\:{odds}\:{appear}\:{that}\:{the}\:{number}\: \\ $$$${on}\:{the}\:{first}\:{dice}\:{us}\:{twice}\:{the}\:{number} \\ $$$${on}\:{the}\:{second}\:{dice}\:{exactly}\:{twice}\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 76651 by john santu last updated on 29/Dec/19 $${if}\:{a}\:{and}\:{b}\:{two}\:{numbers}\:{do}\:{not}\:{have}\: \\ $$$${to}\:{be}\:{chosen}\:{randomly}\:{and}\:{with}\: \\ $$$${returns}\:{from}\:{the}\:{set}\:\left\{\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5}\right\}.\:{what}\: \\ $$$${probability}\:{that}\:\frac{{a}}{{b}}\:{is}\:{an}\:{integer}\:? \\ $$ Answered by benjo 1/2 santuyy last…
Question Number 11101 by FilupS last updated on 12/Mar/17 Commented by FilupS last updated on 12/Mar/17 $$\mathrm{assume}\:\mathrm{that}\:\mathrm{any}\:\mathrm{drawn}\:\mathrm{cards}\:\mathrm{are}\:\mathrm{not} \\ $$$$\mathrm{returned} \\ $$ Answered by DrDaveR last…
Question Number 76588 by Rio Michael last updated on 28/Dec/19 $$\mathrm{Given}\:\mathrm{three}\:\mathrm{events}\:\mathrm{A},\mathrm{B},\:\mathrm{and}\:\mathrm{C}\:\mathrm{sucb}\:\mathrm{that} \\ $$$$\mathrm{P}\left(\mathrm{A}\right)\:=\:\mathrm{P}\left(\mathrm{C}\right)\:,\:\mathrm{P}\left(\mathrm{A}\:\cap\:\mathrm{C}\right)\:=\:\frac{\mathrm{1}}{\mathrm{10}}\:,\:\mathrm{P}\left(\mathrm{A}\:\cup\:\mathrm{C}\right)=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{P}\left(\mathrm{C}\mid\mathrm{B}\right)\:=\:\frac{\mathrm{2}}{\mathrm{7}}\:\:,\:\mathrm{P}\left(\mathrm{B}\cup\mathrm{C}\right)\:=\:\frac{\mathrm{4}}{\mathrm{5}}\:\mathrm{find}\: \\ $$$$\left.\mathrm{a}\right)\:\mathrm{P}\left(\mathrm{A}\right) \\ $$$$\left.\mathrm{b}\right)\:\mathrm{P}\left(\mathrm{B}\right) \\ $$ Answered by john santu…
Question Number 10714 by Saham last updated on 23/Feb/17 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{following}\:\mathrm{information}\:\mathrm{regarding}\:\mathrm{the}\:\mathrm{follwing}\: \\ $$$$\mathrm{distribution}\::\:\: \\ $$$$\mathrm{n}\:=\:\mathrm{5},\:\:\:\:\overset{−} {\mathrm{x}}\:=\:\mathrm{10},\:\:\:\overset{−} {\mathrm{y}}\:=\:\mathrm{20},\:\:\:\Sigma\left(\mathrm{x}\:−\:\mathrm{4}\right)^{\mathrm{2}} \:=\:\mathrm{100},\:\:\Sigma\left(\mathrm{y}\:−\:\mathrm{10}\right)^{\mathrm{2}} \:=\:\mathrm{160}, \\ $$$$\Sigma\left(\mathrm{x}\:−\:\mathrm{4}\right)\left(\mathrm{y}\:−\:\mathrm{10}\right)\:=\:\mathrm{80} \\ $$$$\left(\mathrm{i}\right) \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{two}\:\mathrm{regression}\:\mathrm{coefficient}\:\mathrm{and} \\…
Question Number 141692 by ArielVyny last updated on 22/May/21 $${Daniel}\:{and}\:{Bruno}\:{are}\:{playing}\:{with}\:{perfect}\:{cube} \\ $$$${Daniel}\:{is}\:{the}\:{first}\:{player}\:{if}\:{he}\:{obtains}\:\mathrm{1}\:{or}\:\mathrm{2} \\ $$$${he}\:{wins}\:{the}\:{game}\:{and}\:{the}\:{party}\:{stopping} \\ $$$${or}\:{else}\:{Bruno}\:{plays}\:{and}\:{if}\:{he}\:{have}\:\left\{\mathrm{3}.\mathrm{4}.\mathrm{6}\right\}\:{Bruno}\:{won}\:{and}\:{the}\:{game}\:{stopping} \\ $$$${Determine}\:{the}\:{probability}\:{that}\:{Daniel}\:{winand}\:{the}\:{probability}\:{that}\:{Bruno}\:{win} \\ $$$$ \\ $$ Answered by MJS_new…