Question Number 9818 by j.masanja06@gmail.com last updated on 05/Jan/17 Commented by sandy_suhendra last updated on 06/Jan/17 $$\mathrm{the}\:\mathrm{intervals}\:\mathrm{is}\:\mathrm{usually}\:\mathrm{not}\:\mathrm{overlapping} \\ $$$$\mathrm{such}\:\mathrm{as}\::\:\mathrm{1}−\mathrm{10},\:\mathrm{11}−\mathrm{20},\:\mathrm{21}−\mathrm{30}\:\mathrm{etc} \\ $$ Terms of Service Privacy…
Question Number 75325 by TawaTawa last updated on 09/Dec/19 Answered by MJS last updated on 10/Dec/19 $${z}_{{A}} =\frac{\mathrm{500}−\mathrm{524}.\mathrm{66}}{\mathrm{15}.\mathrm{01}}\approx−\mathrm{1}.\mathrm{643} \\ $$$${z}_{{B}} =\frac{\mathrm{500}−\mathrm{528}.\mathrm{21}}{\mathrm{15}.\mathrm{01}}\approx−\mathrm{1}.\mathrm{879} \\ $$$$\mathrm{1}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}\pi}}\underset{{z}_{{A}} } {\overset{\infty}…
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Question Number 9577 by j.masanja06@gmail.com last updated on 18/Dec/16 $$\mathrm{The}\:\mathrm{mean}\:\mathrm{of}\:\mathrm{n}\:\mathrm{number}\:\mathrm{is}\:\mathrm{20}.\mathrm{if}\: \\ $$$$\mathrm{the}\:\mathrm{same}\:\mathrm{numbers}\:\mathrm{together}\:\mathrm{with}\:\mathrm{30} \\ $$$$\mathrm{give}\:\mathrm{a}\:\mathrm{new}\:\mathrm{mean}\:\mathrm{of}\:\mathrm{22}, \\ $$$$\mathrm{find}\:\mathrm{n}. \\ $$ Answered by ridwan balatif last updated on…
Question Number 140596 by nadovic last updated on 10/May/21 $$ \\ $$$$\mathrm{A}\:\mathrm{class}\:\mathrm{contains}\:\mathrm{20}\:\mathrm{students}\:\mathrm{of}\:\mathrm{whom}\:\mathrm{2} \\ $$$$\mathrm{are}\:\mathrm{men}\:\mathrm{and}\:\mathrm{8}\:\mathrm{are}\:\mathrm{women}.\:\mathrm{A}\:\mathrm{random} \\ $$$$\mathrm{sample}\:\mathrm{of}\:\mathrm{2}\:\mathrm{students}\:\mathrm{is}\:\mathrm{taken}\:\mathrm{from}\:\mathrm{the} \\ $$$$\mathrm{class}\:\mathrm{without}\:\mathrm{replacement}.\:\left(\mathrm{random}\right. \\ $$$$\mathrm{imlies}\:\mathrm{that}\:\mathrm{each}\:\mathrm{student}\:\mathrm{has}\:\mathrm{an}\:\mathrm{equal} \\ $$$$\left.\mathrm{chance}\:\mathrm{of}\:\mathrm{appearing}\:\mathrm{in}\:\mathrm{the}\:\mathrm{sample}\right) \\ $$$$\left({a}\right)\:\mathrm{Use}\:\mathrm{a}\:\mathrm{diagram}\:\mathrm{to}\:\mathrm{illustrate}\:\mathrm{the}\:\mathrm{possible} \\…
Question Number 74860 by rajesh4661kumar@gmail.com last updated on 02/Dec/19 Answered by MJS last updated on 02/Dec/19 $$\mathrm{no}\:\mathrm{head} \\ $$$$\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{6}} =\frac{\mathrm{1}}{\mathrm{64}} \\ $$$$\mathrm{minimum}\:\mathrm{one}\:\mathrm{head} \\ $$$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{64}}=\frac{\mathrm{63}}{\mathrm{64}} \\…
Question Number 8973 by tekviah munandi last updated on 09/Nov/16 $${given}\:{that}\:{x}\:{and}\:{y}\:{are}\:{samples}\: \\ $$$${of}\:{random}\:{variable}\:{drawn}\:{from}\:{a}\: \\ $$$${population}\:{that}\:{is}\:{normally}\:{distributed} \\ $$$${find}\:{the}\:{joint}\:{distribution}\:{of}\:{x}\:{and}\:{y}.\: \\ $$$${if}\:{x}\:{and}\:{y}\:{are}\:{independent}\:{find}\:{the} \\ $$$${marginal}\:{distributions}. \\ $$ Terms of…
Question Number 8870 by FilupSmith last updated on 03/Nov/16 $$\mathrm{You}\:\mathrm{have}\:{n}\:\mathrm{dice}.\:\mathrm{Each}\:\mathrm{dice}\:\mathrm{has}\:{p}\:\mathrm{sides}, \\ $$$$\mathrm{labled}\:\mathrm{1}\:\mathrm{to}\:{p}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability} \\ $$$$\mathrm{of}\:\mathrm{rolling}\:{k}\:\:\:\:\:\left(\mathrm{1}\leqslant{k}\leqslant{p}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 139868 by I want to learn more last updated on 01/May/21 Answered by TheSupreme last updated on 02/May/21 $$\mathrm{10}\:{question} \\ $$$${P}\left({Answer}\:{correct}\:{per}\:{question}\right)=\mathrm{0}.\mathrm{5} \\ $$$${P}\left({N}\:{Answer}\:{correct}\right)=\begin{pmatrix}{\mathrm{10}}\\{{n}}\end{pmatrix}\mathrm{0}.\mathrm{5}^{\mathrm{10}}…
Question Number 74005 by mhmd last updated on 17/Nov/19 $${find}\:{C}_{\mathrm{8}} ^{\mathrm{15}} +{C}_{\mathrm{9}} ^{\mathrm{15}} −{C}_{\mathrm{7}} ^{\mathrm{15}} −{C}_{\mathrm{6}} ^{\mathrm{15}} \:? \\ $$$${pleas}\:{help}\:{me}\:{sir}\:? \\ $$ Terms of Service…