Question Number 135998 by nadovic last updated on 17/Mar/21 A bowl contains carefully shredded confetti, 6 of which are blue and the remaining 12 are red.…
Question Number 135861 by liberty last updated on 16/Mar/21 $${Probability} \\ $$Digits from 1 to 9 are randomly placed to form a 9-digit number. What…
Question Number 4753 by FilupSmith last updated on 05/Mar/16 $$\ast\:\:\ast\:\:\ast\:\:\ast\:\:\ast \\ $$$$\ast\:\:\ast\:\:\ast\:\:\ast\:\:\ast \\ $$$$\ast\:\:\ast\:\:\ast\:\:\ast\:\:\ast \\ $$$$ \\ $$$$\mathrm{Selecting}\:\mathrm{a}\:\mathrm{random}\:\mathrm{star}\:\mathrm{is}\:\mathrm{a}\:\:\frac{\mathrm{1}}{\mathrm{15}}\:\mathrm{chance} \\ $$$$\mathrm{at}\:\mathrm{random}.\:\mathrm{Lets}\:\mathrm{say}\:\mathrm{you}\:\mathrm{have}\:\mathrm{to}\:\mathrm{pick} \\ $$$$\mathrm{a}\:\mathrm{second}\:\mathrm{random}\:\mathrm{star}\:\mathrm{that}\:\mathrm{is}\:\mathrm{next}\:\mathrm{to}\:\mathrm{it}. \\ $$$${Either}\:{above},\:{below},\:{or}\:{to}\:{the}\:{side}. \\…
Question Number 135352 by EDWIN88 last updated on 12/Mar/21 $$\underline{\mathrm{Probability}} \\ $$$$\mathrm{Urn}\:\mathrm{I}\:\mathrm{contains}\:\mathrm{5}\:\mathrm{red}\:\mathrm{and}\:\mathrm{3}\:\mathrm{green}\:\mathrm{balls}.\:\mathrm{Urn}\:\mathrm{II} \\ $$$$\mathrm{contains}\:\mathrm{2}\:\mathrm{red}\:\mathrm{and}\:\mathrm{7}\:\mathrm{green}\:\mathrm{balls}.\:\mathrm{One}\:\mathrm{balls} \\ $$$$\mathrm{is}\:\mathrm{transferred}\:\left(\mathrm{at}\:\mathrm{random}\right)\:\mathrm{from}\:\mathrm{urn}\:\mathrm{I}\:\mathrm{to}\:\mathrm{urn}\:\mathrm{II} \\ $$$$.\:\mathrm{After}\:\mathrm{stirring}\:,\:\mathrm{1}\:\mathrm{ball}\:\mathrm{is}\:\mathrm{chosen}\:\mathrm{from}\:\mathrm{urn}\:\mathrm{II}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{the}\:\left(\mathrm{final}\right)\:\mathrm{ball}\:\mathrm{is} \\ $$$$\mathrm{green}?\: \\ $$ Answered…
Question Number 4166 by Filup last updated on 30/Dec/15 Commented by prakash jain last updated on 31/Dec/15 $$\mathrm{To}\:\mathrm{go}\:\mathrm{broke}:\:{k}\:\mathrm{wins},\:\mathrm{2}+{k}\:\mathrm{losses} \\ $$$$\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{{k}} \left(\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{2}+{k}} =\:\frac{\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} }{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{16}}}\:=\:\frac{\mathrm{1}}{\mathrm{13}}\:?…
Question Number 135217 by benjo_mathlover last updated on 11/Mar/21 Commented by mr W last updated on 11/Mar/21 $${please}\:{explain}\:{what}\:{you}\:{mean}\:{with} \\ $$$$“{there}\:{is}\:{exactly}\:{only}\:{a}\:{circle}\:{that} \\ $$$${has}\:\mathrm{6}\:{girls}''! \\ $$$${when}\:{a}\:{circle}\:{has}\:{exactly}\:\mathrm{6}\:{girls}, \\…
Question Number 135181 by liberty last updated on 11/Mar/21 $$\mathrm{A}\:\mathrm{bag}\:\mathrm{has}\:\mathrm{4}\:\mathrm{red}\:\mathrm{marbles},\:\mathrm{5}\:\mathrm{white}\: \\ $$$$\mathrm{marbles}\:,\:\mathrm{and}\:\mathrm{6}\:\mathrm{blue}\:\mathrm{marbles}.\:\mathrm{Three} \\ $$$$\mathrm{marbles}\:\mathrm{are}\:\mathrm{drawn}\:\mathrm{from}\:\mathrm{the}\:\mathrm{bag},\:\left(\mathrm{without}\right. \\ $$$$\left.\mathrm{replacement}\right)\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability} \\ $$$$\mathrm{that}\:\mathrm{they}\:\mathrm{are}\:\mathrm{all}\:\mathrm{the}\:\mathrm{same}\:\mathrm{color}\:?\: \\ $$ Answered by EDWIN88 last updated…
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Question Number 3894 by Filup last updated on 24/Dec/15 $$\mathrm{I}\:\mathrm{have}\:{n}\:\mathrm{six}\:\mathrm{sided}\:\mathrm{dice}. \\ $$$$\mathrm{I}\:\mathrm{roll}\:\mathrm{them}\:\mathrm{all}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{proability} \\ $$$$\mathrm{that}\:{k}\:\mathrm{of}\:\mathrm{them}\:\mathrm{share}\:\mathrm{the}\:\mathrm{same}\:\mathrm{value}? \\ $$ Commented by Filup last updated on 24/Dec/15 $$\mathrm{Whoops}.\:\mathrm{That}\:\mathrm{was}\:\mathrm{my}\:\mathrm{mistake}! \\…
Question Number 3824 by Yozzii last updated on 21/Dec/15 $${Box}\:{I}\:{has}\:\mathrm{3}\:{red}\:{and}\:\mathrm{5}\:{white}\:{balls}, \\ $$$${while}\:{Box}\:{II}\:{contains}\:\mathrm{4}\:{red}\:{and}\:\mathrm{2}\: \\ $$$${white}\:{balls}.\:{A}\:{ball}\:{is}\:{chosen}\:{at}\:{random} \\ $$$${from}\:{the}\:{first}\:{box}\:{and}\:{placed}\:{in}\:{the} \\ $$$${second}\:{box}\:{without}\:{observing}\:{its}\:{colour}. \\ $$$${Then}\:{a}\:{ball}\:{is}\:{drawn}\:{from}\:{the}\:{second} \\ $$$${box}.\:{Find}\:{the}\:{probability}\:{that}\:{it}\:{is}\:{white}. \\ $$ Commented…