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Category: Probability and Statistics

Box-I-has-3-red-and-5-white-balls-while-Box-II-contains-4-red-and-2-white-balls-A-ball-is-chosen-at-random-from-the-first-box-and-placed-in-the-second-box-without-observing-its-colour-Then-a-ball-

Question Number 3824 by Yozzii last updated on 21/Dec/15 $${Box}\:{I}\:{has}\:\mathrm{3}\:{red}\:{and}\:\mathrm{5}\:{white}\:{balls}, \\ $$$${while}\:{Box}\:{II}\:{contains}\:\mathrm{4}\:{red}\:{and}\:\mathrm{2}\: \\ $$$${white}\:{balls}.\:{A}\:{ball}\:{is}\:{chosen}\:{at}\:{random} \\ $$$${from}\:{the}\:{first}\:{box}\:{and}\:{placed}\:{in}\:{the} \\ $$$${second}\:{box}\:{without}\:{observing}\:{its}\:{colour}. \\ $$$${Then}\:{a}\:{ball}\:{is}\:{drawn}\:{from}\:{the}\:{second} \\ $$$${box}.\:{Find}\:{the}\:{probability}\:{that}\:{it}\:{is}\:{white}. \\ $$ Commented…

Question-134296

Question Number 134296 by EDWIN88 last updated on 02/Mar/21 Answered by bramlexs22 last updated on 02/Mar/21 $$\mathrm{total}\:\mathrm{three}\:\mathrm{digit}\:\mathrm{numbers}\:=\:\mathrm{4}×\mathrm{5}^{\mathrm{2}} =\mathrm{100} \\ $$$$\mathrm{the}\:\mathrm{number}\:\mathrm{has}\:\mathrm{identical}\:\mathrm{digit}? \\ $$$$\left[\:\mathrm{111},\:\mathrm{333},\:\mathrm{555},\:\mathrm{999}\:\right]\:=\:\mathrm{4}\:\mathrm{numbers} \\ $$$$\mathrm{the}\:\mathrm{p}\left(\mathrm{A}\right)=\:\frac{\mathrm{4}}{\mathrm{100}}\:=\:\frac{\mathrm{1}}{\mathrm{25}} \\…

Pl-notice-the-answer-of-Q2771-I-have-updated-it-

Question Number 3023 by Rasheed Soomro last updated on 03/Dec/15 $$\mathrm{Pl}\:\mathrm{notice}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{of}\:\underset{−} {\mathrm{Q2771}},\mathrm{I}\:\mathrm{have}\:\mathrm{updated}\:\mathrm{it}. \\ $$ Answered by prakash jain last updated on 04/Dec/15 $$\mathrm{I}\:\mathrm{think}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{should}\:\mathrm{be} \\ $$$$\frac{\mathrm{number}\:\mathrm{of}\:\mathrm{rectangles}\:\mathrm{in}\:\mathrm{7}×\mathrm{7}\:\mathrm{grid}\:\left(\mathrm{8}×\mathrm{8}\:\mathrm{points}\right)}{\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{to}\:\mathrm{select}\:\mathrm{4}\:\mathrm{points}=^{\mathrm{64}}…

64-points-are-in-a-plane-x-y-x-0-1-2-7-y-0-1-2-7-4-points-are-chosen-at-random-What-is-the-proabability-the-lines-connecting-them-do-not-form-a-square-or-rectangle-

Question Number 2771 by prakash jain last updated on 26/Nov/15 $$\mathrm{64}\:\mathrm{points}\:\mathrm{are}\:\mathrm{in}\:\mathrm{a}\:\mathrm{plane}: \\ $$$$\left({x},{y}\right),\:{x}\in\left\{\mathrm{0},\mathrm{1},\mathrm{2},…,\mathrm{7}\right\},\:{y}\in\left\{\mathrm{0},\mathrm{1},\mathrm{2},…,\mathrm{7}\right\} \\ $$$$\mathrm{4}\:\mathrm{points}\:\mathrm{are}\:\mathrm{chosen}\:\mathrm{at}\:\mathrm{random}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{proabability}\:\mathrm{the}\:\mathrm{lines}\:\mathrm{connecting} \\ $$$$\mathrm{them}\:\mathrm{do}\:\mathrm{not}\:\mathrm{form}\:\mathrm{a}\:\mathrm{square}\:\mathrm{or}\:\mathrm{rectangle}? \\ $$ Answered by Rasheed Soomro…

There-are-5-positive-numbers-and-6-negative-numbers-Three-numbers-are-chosen-at-random-and-multiplied-The-probability-that-the-product-being-a-negative-number-is-a-17-33-b-11-34-

Question Number 133821 by bramlexs22 last updated on 24/Feb/21 $$\mathrm{There}\:\mathrm{are}\:\mathrm{5}\:\mathrm{positive}\:\mathrm{numbers}\: \\ $$$$\mathrm{and}\:\mathrm{6}\:\mathrm{negative}\:\mathrm{numbers}.\:\mathrm{Three}\: \\ $$$$\mathrm{numbers}\:\mathrm{are}\:\mathrm{chosen}\:\mathrm{at}\:\mathrm{random} \\ $$$$\mathrm{and}\:\mathrm{multiplied}\:.\:\mathrm{The}\:\mathrm{probability} \\ $$$$\mathrm{that}\:\mathrm{the}\:\mathrm{product}\:\mathrm{being}\:\mathrm{a}\:\mathrm{negative} \\ $$$$\mathrm{number}\:\mathrm{is}\: \\ $$$$\left(\mathrm{a}\right)\:\frac{\mathrm{17}}{\mathrm{33}}\:\:\:\left(\mathrm{b}\right)\:\frac{\mathrm{11}}{\mathrm{34}}\:\left(\mathrm{c}\right)\:\frac{\mathrm{16}}{\mathrm{33}}\:\:\:\left(\mathrm{d}\right)\:\frac{\mathrm{16}}{\mathrm{35}} \\ $$ Answered…