Question Number 192098 by cortano12 last updated on 08/May/23 Answered by mehdee42 last updated on 08/May/23 $$\left({c}\right)\:\:\frac{\mathrm{6}}{\mathrm{7}}\:\:\checkmark \\ $$ Commented by Skabetix last updated on…
Question Number 126270 by liberty last updated on 19/Dec/20 $$\:\:{Three}\:{coins}\:{tossed}\:{at}\:{once}\:\mathrm{5}\:{times}.\: \\ $$$${The}\:{probability}\:{getting}\:{all}\:{faces}\:{or}\:{all} \\ $$$${hindsight}\:{a}\:{second}\:{time}\:{are}…. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 126186 by benjo_mathlover last updated on 18/Dec/20 Commented by benjo_mathlover last updated on 18/Dec/20 $$\left({A}\right)\:\frac{\mathrm{23}}{\mathrm{257}}\:\:\:\:\:\:\:\left({B}\right)\:\frac{\mathrm{24}}{\mathrm{257}}\:\:\:\:\:\left({C}\right)\:\frac{\mathrm{25}}{\mathrm{257}} \\ $$$$\left({D}\right)\:\frac{\mathrm{26}}{\mathrm{257}}\:\:\:\:\:\:\:\left({E}\right)\:\frac{\mathrm{27}}{\mathrm{257}} \\ $$ Terms of Service Privacy…
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Question Number 191507 by Spillover last updated on 24/Apr/23 Answered by cortano12 last updated on 25/Apr/23 $$\left(\mathrm{a}\right)\:\underset{−\infty} {\overset{\infty} {\int}}\mathrm{f}\left(\mathrm{x}\right)\mathrm{dx}=\mathrm{1} \\ $$$$\:\:\:\:\mathrm{k}\underset{\mathrm{0}} {\overset{\mathrm{4}} {\int}}\left(\mathrm{x}^{\mathrm{2}} −\mathrm{3x}+\mathrm{4}\right)\mathrm{dx}+\underset{\mathrm{4}} {\overset{\mathrm{5}}…
Question Number 125580 by Mammadli last updated on 12/Dec/20 $$\boldsymbol{{One}}\:\boldsymbol{{number}}\:\boldsymbol{{is}}\:\boldsymbol{{written}}\:\boldsymbol{{on}}\:\boldsymbol{{the}}\:\boldsymbol{{board}}. \\ $$$$\boldsymbol{{Each}}\:\boldsymbol{{time}}\:\boldsymbol{{the}}\:\boldsymbol{{number}}\:\boldsymbol{{is}}\:\boldsymbol{{either}}\:\boldsymbol{{squared}}\:\boldsymbol{{or}}\:\boldsymbol{{multiplied}}\:\boldsymbol{{bh}}\:\mathrm{2}. \\ $$$$\boldsymbol{{If}}\:\mathrm{1}\:\boldsymbol{{is}}\:\boldsymbol{{written}}\:\boldsymbol{{on}}\:\boldsymbol{{the}}\:\boldsymbol{{board}}\:\boldsymbol{{at}}\:\boldsymbol{{the}}\:\boldsymbol{{beginning}}, \\ $$$$\boldsymbol{{it}}\:\boldsymbol{{is}}\:\boldsymbol{{necessary}}\:\boldsymbol{{to}}\:\boldsymbol{{perform}}\:\boldsymbol{{at}}\:\boldsymbol{{least}} \\ $$$$\boldsymbol{{several}}\:\boldsymbol{{operations}}\:\boldsymbol{{to}}\:\boldsymbol{{get}}\:\boldsymbol{{the}}\:\boldsymbol{{number}}\:\mathrm{2}^{\mathrm{2018}} . \\ $$ Terms of Service Privacy…
Question Number 60000 by malwaan last updated on 16/May/19 $${A}\:{cord}\:{is}\:{drawn}\:{at}\:{random} \\ $$$${in}\:{a}\:{given}\:{circle}\:. \\ $$$${Whats}\:{the}\:{probability}\:\boldsymbol{{p}}\:{that} \\ $$$${the}\:{cord}\:{is}\:{longer}\:{than}\:{the}\:{side} \\ $$$${of}\:{an}\:{inscribed}\:{equilateral}\: \\ $$$${triangle}\:{in}\:{the}\:{circle}? \\ $$ Commented by mr…
Question Number 190818 by cortano12 last updated on 12/Apr/23 $$\:\:\mathrm{It}\:\mathrm{is}\:\mathrm{known}\:\mathrm{that}\:\mathrm{the}\:\mathrm{set}\:\mathrm{A}=\left\{\mathrm{1}\:,\:\mathrm{2},\:\mathrm{3},\:…,\:\mathrm{100}\right\} \\ $$$$\:\mathrm{The}\:\mathrm{numbers}\:\mathrm{of}\:\mathrm{subsets}\:\mathrm{of}\:\mathrm{A}\:\mathrm{which}\:\mathrm{when}\: \\ $$$$\:\mathrm{added}\:\mathrm{together}\:\mathrm{are}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{4} \\ $$ Commented by safojontoshtemirov last updated on 12/Apr/23 $$\left[\frac{\mathrm{100}}{\mathrm{4}}\right]=\mathrm{25} \\…
Question Number 125182 by Mammadli last updated on 08/Dec/20 $$\boldsymbol{{How}}\:\boldsymbol{{many}}\:\mathrm{3}−\boldsymbol{{digit}}\:\boldsymbol{{numbers}}\:\boldsymbol{{divisible}}\:\boldsymbol{{by}}\:\mathrm{5}\:\boldsymbol{{can}}\:\boldsymbol{{be}}\:\boldsymbol{{made}}\:\boldsymbol{{using}}\:\boldsymbol{{the}}\:\boldsymbol{{numbers}}\:\mathrm{7},\mathrm{8},\mathrm{9},\mathrm{2},\mathrm{1},\mathrm{0}\:\boldsymbol{{without}}\:\boldsymbol{{repetition}}? \\ $$ Answered by bemath last updated on 08/Dec/20 $${AB}\mathrm{0}\:\Rightarrow\:{P}_{\mathrm{2}} ^{\:\mathrm{5}} \:=\:\frac{\mathrm{5}!}{\mathrm{3}!}\:=\:\mathrm{20}. \\ $$ Terms…
Question Number 125097 by pticantor last updated on 08/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com