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Category: Relation and Functions

1-for-x-gt-0-prove-that-1-x-1-ln-x-1-lnx-1-x-2-let-u-n-p-1-kn-1-p-find-lim-n-u-n-

Question Number 32287 by abdo imad last updated on 22/Mar/18 $$\left.\mathrm{1}\right)\:{for}\:{x}>\mathrm{0}\:{prove}\:{that}\:\frac{\mathrm{1}}{{x}+\mathrm{1}}\:\leqslant{ln}\left({x}+\mathrm{1}\right)−{lnx}\:\leqslant\:\frac{\mathrm{1}}{{x}} \\ $$$$\left.\mathrm{2}\right)\:{let}\:{u}_{{n}} =\:\sum_{{p}=\mathrm{1}} ^{{kn}} \:\frac{\mathrm{1}}{{p}}\:\:\:{find}\:{lim}_{{n}\rightarrow\infty\:} \:{u}_{{n}} . \\ $$ Terms of Service Privacy Policy…

prove-that-x-0-pi-4-x-tanx-2x-2-find-n-and-n-from-R-n-k-2-n-tan-pi-2n-n-

Question Number 32284 by abdo imad last updated on 22/Mar/18 $${prove}\:{that}\:\forall\:{x}\in\left[\mathrm{0},\frac{\pi}{\mathrm{4}}\right]\:\:{x}\leqslant{tanx}\leqslant\mathrm{2}{x} \\ $$$$\left.\mathrm{2}\right)\:{find}\:\alpha_{{n}} \:{and}\:\beta_{{n}} \:{from}\:{R}\:/\:\:\alpha_{{n}} \leqslant\:\sum_{{k}=\mathrm{2}} ^{{n}} \:{tan}\left(\frac{\pi}{\mathrm{2}{n}}\right)\leqslant\:\beta_{{n}} \\ $$ Terms of Service Privacy Policy…

let-f-x-x-n-1-ln-1-x-with-n-integr-and-n-1-1-calculate-f-p-x-2-find-f-n-x-

Question Number 32285 by abdo imad last updated on 22/Mar/18 $${let}\:{f}\left({x}\right)=\:{x}^{{n}−\mathrm{1}} {ln}\left(\mathrm{1}+{x}\right)\:{with}\:{n}\:{integr}\:{and}\:{n}\geqslant\mathrm{1} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({p}\right)} \left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{f}^{\left({n}\right)} \left({x}\right) \\ $$ Terms of Service Privacy Policy…

let-give-f-x-x-2-x-1-1-find-f-1-x-inverse-of-f-x-2-calculate-f-1-x-

Question Number 32283 by abdo imad last updated on 22/Mar/18 $${let}\:{give}\:{f}\left({x}\right)={x}+\mathrm{2}\:−\sqrt{{x}+\mathrm{1}} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{f}^{−\mathrm{1}} \left({x}\right)\:{inverse}\:{of}\:{f}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\left({f}^{−\mathrm{1}} \right)^{'} \left({x}\right)\:. \\ $$ Commented by abdo imad last…

let-u-n-e-1-n-2-1-1-1-find-a-equivalent-of-u-n-and-lim-n-u-n-2-study-the-convergence-of-u-n-

Question Number 32280 by abdo imad last updated on 22/Mar/18 $${let}\:{u}_{{n}} =\:{e}^{\frac{\mathrm{1}}{{n}^{\mathrm{2}} \:+\mathrm{1}}} \:\:−\mathrm{1} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{a}\:{equivalent}\:{of}\:{u}_{{n}} \:{and}\:{lim}_{{n}\rightarrow\infty} {u}_{{n}} \\ $$$$\left.\mathrm{2}\right)\:{study}\:{the}\:{convergence}\:{of}\:\:\Sigma{u}_{{n}} \:. \\ $$ Terms of…