Question Number 30565 by abdo imad last updated on 23/Feb/18 $${let}\:{f}\left({x}\right)=\:\frac{\mathrm{1}}{{n}!}\left({px}−{qx}^{\mathrm{2}} \right)^{{n}} \:\:\:{find}\:{maxf}\:\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30563 by abdo imad last updated on 23/Feb/18 $${let}\:{f}\left({x}\right)=\mid{x}−\mathrm{2}\:\left[\frac{{x}+\mathrm{1}}{\mathrm{2}}\right]\mid \\ $$$$\left.\mathrm{1}\right)\:{prove}\:{that}\:{f}\:{is}\:{periodic} \\ $$$$\left.\mathrm{2}\right)\:{simplify}\:{f}\left({x}\right)\:{if}\:{p}\leqslant{x}+\mathrm{1}\:{and}\:{p}\in{Z}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30560 by abdo imad last updated on 23/Feb/18 $${study}\:{the}\:{roots}\:{of}\:{f}_{{n}} \left({x}\right)=\:\sum_{{k}=\mathrm{0}} ^{{n}} \:\:\:\frac{{x}^{{k}} }{{k}!}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30556 by abdo imad last updated on 23/Feb/18 $${let}\:\:{S}_{{n}} \left({x}\right)=\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\:\frac{{sin}\left({kx}\right)}{{k}^{\mathrm{2}} \left({k}+\mathrm{1}\right)}\:\:{find}\:{lim}_{{n}\rightarrow\infty} {S}_{{n}} \left({x}\right). \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 30551 by abdo imad last updated on 23/Feb/18 $$\:{find}\:\:{S}\:=\:\sum_{{n}\geqslant\mathrm{3}} \:\:\:\frac{\mathrm{1}}{\left({n}+\mathrm{1}\right)\left({n}−\mathrm{2}\right)\mathrm{2}^{{n}} }\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30552 by abdo imad last updated on 23/Feb/18 $${find}\:{s}\left({x}\right)=\:\sum_{{n}\geqslant\mathrm{0}} \:\frac{{sin}\left({na}\right)}{\left({sina}\right)^{{n}} }\:\frac{{x}^{{n}} }{{n}!}\:{and}\: \\ $$$${T}\left({x}\right)\:=\sum_{{n}\geqslant\mathrm{0}} \:\:\frac{{cos}\left({na}\right)}{\left({sina}\right)^{{n}} }\:\frac{{x}^{{n}} }{{n}!}\:. \\ $$ Terms of Service Privacy…
Question Number 30550 by abdo imad last updated on 23/Feb/18 $${let}\:{f}\left({z}\right)=\:\sum_{{n}\geqslant\mathrm{0}} {a}_{{n}} {z}^{{n}} \:\:\:/{a}_{\mathrm{0}} =\mathrm{1}\:,{a}_{\mathrm{1}} =\mathrm{3}\:{and}\:\forall{n}\geqslant\mathrm{2} \\ $$$${a}_{{n}} =\mathrm{3}{a}_{{n}−\mathrm{1}} −\mathrm{2}\:{a}_{{n}−\mathrm{2}} \:\:\:\:{find}\:{f}\left({z}\right)\:{for}\:\mid{z}\mid<\mathrm{1}\:\:\left({z}\in{C}\right)\:. \\ $$ Terms of…
Question Number 30549 by abdo imad last updated on 23/Feb/18 $${let}\:{S}\left({x}\right)=\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\frac{{x}^{\mathrm{3}{n}} }{\left(\mathrm{3}{n}\right)!}\:\:{find}\:{S}\left({x}\right). \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30547 by abdo imad last updated on 23/Feb/18 $${ind}\:{S}=\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\:\frac{{n}^{\mathrm{3}} \:+{n}^{\mathrm{2}} \:+{n}+\mathrm{1}}{{n}!}\:\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30526 by abdo imad last updated on 22/Feb/18 $${let}\:{f}\left({x}\right)=\sqrt{\mathrm{1}+{ax}}\:\:{with}\:{a}\in{C}\:\:\:{find}\:\:{f}^{\left({n}\right)} \left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right)\:{developp}\:{f}\left({x}\right)\:{at}\:{integr}\:{series}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com