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Category: Relation and Functions

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Question Number 30431 by abdo imad last updated on 22/Feb/18 $${let}\:{f}\left({x}\right)=\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\frac{{x}^{{n}} }{\mathrm{1}−{x}^{{n}} }\:\:{with}\:{x}\in\left[\mathrm{0},\mathrm{1}\left[\:\:{prove}\:{that}\right.\right. \\ $$$${f}\left({x}\right)\sim_{{x}\rightarrow\mathrm{1}} \:\:\:\frac{{ln}\left(\mathrm{1}−{x}\right)}{{x}−\mathrm{1}}. \\ $$ Terms of Service Privacy Policy…

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Question Number 30412 by abdo imad last updated on 22/Feb/18 $$\left.{f}\left.\:{is}\:{a}\:{function}\:{increazing}\left({or}\:{decreazing}\right){on}\:\right]\mathrm{0},\mathrm{1}\right] \\ $$$${prove}\:{that}\:{lim}_{{n}\rightarrow\infty} \:\frac{\mathrm{1}}{{n}}\sum_{{q}=\mathrm{1}} ^{{n}} {f}\left(\frac{{q}}{{n}}\right)=\int_{\mathrm{0}} ^{\mathrm{1}} {f}\left({t}\right){dt}. \\ $$$$ \\ $$ Terms of Service…

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Question Number 30407 by abdo imad last updated on 22/Feb/18 $${let}\:{give}\:{s}\left({x}\right)=\:\sum_{{n}=\mathrm{1}} ^{\infty} {nx}^{{n}} \:\:{and}\:{w}\left({x}\right)=\sum_{{n}=\mathrm{1}} ^{\infty} \frac{\mathrm{1}}{{n}}{x}^{{n}−\mathrm{1}} \:\:{for}\mid{x}\mid<\mathrm{1} \\ $$$${find}\:{s}\left({x}\right).{w}\left({x}\right)\:{at}\:{form}\:{of}\:{series} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{s}\left({x}\right).{w}\left({x}\right)\:{at}\:{form}\:{of}\:{function}. \\ $$ Terms of…